Ohm's Law says that if you have a circuit with two resistors in them, and then if you replace one resistor with another one with a higher resistance, the new resistor will have a higher percentage of the voltage dropped across it than the old one would have had.
If a cap has a high internal resistance, it would act like a resistor with a high ohmic value, no? You would be able to measure more voltage across it than you would if the cap had a low internal resistance.
Congratulations Benny. That is the first post of your many dozens with no nonsense it and some correct facts! Unfortunately, for you it also refutes your silly, ignorant claim in post 478 that series capacitors could be used instead of series resistors to make a high-voltage voltage divider.
In any series circuit all element in series have the same current passing thru them. In the case of a REAL capacitor there is the internal resistance. For example consider again, 3 capacitors, A B & C connected in series and all with the same capacitance C but their internal resistances are 300Meg ohms, for A, 200 Meg ohms for B and 100 meg ohms* for C with again, as in my last post, 3V applied to the the series string. To continue with numbers let 3V = 300KV and the capacitors all are rated for 120KV which if capacitors worked as voltage divider as Benny claimed would be adequate. I.e. Benny erroneously and ignorantly suggested, based on his paper only knowledge, that three capacitors all of capacitance C would each have V across them with 3V is applied to the string.
But in fact half of the 3V or 1.5V or 150KV tries to appear across the capacitor A, one third of V or 100KV tries to appear across capacitor B and one sixth or 50KV appears across capacitor C (by Benny's often quoted ohms law. I.e. they have the same current flowing thur resistors of 300, 200 & 100 meg ohms)
But it does not work in reality as it does for Benny in his paper diagrams. When the voltage on capacitor A get a little above 120KV it arcs thru and shorts out. (A cannot support half of 300KV.) Once the arc forms the internal resistance drops way down, so low it can be ignored compared to 100 or 200 meg ohms. Then with only 200megohms in series with 100 Meg ohms, the voltage on capacitor B tries to go to 200KV but of course it cannot so B breaks down with an internal arc also. now the full 300KV is applied to capacitor C and it breaks downs also.
Ironically, when Benny finally posted something that was not silly, false nonsense, he has refuted his own earlier post 478 nonsense that one can make a high-voltage voltage divider with a string of series capacitors!
But of course I had already proved this in post 479 by other means.
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*Quite typical variations as the maker is trying to make all as high as possible. The best way to measure these high resistances is to charge the capacitors up and see how long it takes them to self discharge drop to 1/e of their original charge. - That, if memory serves me, is their RC time constant and C is known.
PS, I am sorry Benny, but I only read point 1 of post 478. I learned long ago that if the first bite of an egg is rotten, don't eat (or read) any more.
