Well done, you've shown you are willing to lie to someone's face about what they said. Either you know you're lying, in which case you've proven my point that you shouldn't be allowed in the main part of the forum, or you are so colossally thick, so paste eatingly stupid, so reality warpingly moronic that you still don't grasp your mistake. Either way the closing of your Konig's theorem thread was completely valid, since you clearly lack the capability to discuss basic set theory.
No, show the cantor thread where you proved the emergence of the continuum from the natural numbers using only one sequence.
Next, Konig's theorem is trivial, You proceed by transfinite induction for each ordinal n. At each level, you associate an element at the level with both sides. Then, you choose the R least element in the difference set at that level since the levels do not contain the same number of elements.
At limit ordinals, it is trivial since you union all successors in which the condition holds. The union of all true is true.
Next, I have given math specifics for this thread, can you refute the below yes or no.
First off, your closing of the Cantor thread with your last statement accepted that the missing cantor sequence union the set of countable sequences was countable. Then, you claimed, oh, you can just do it again and then the result was not countable. But, the result is again the same, a countable listing unioned with one sequence is still countable. As you can see, I am very specific here. There is not way to escape countability one unit at a time. Yet, that is your claim.
Now, who makes more sense?
Further, in this thread, I am very specific, a light pulse is emitted when the clocks are common.
One clock moves in a circle and returns to the other clock.
Here is Einstein's statement.
If we assume that the result proved for a polygonal line is also valid for a continuously curved line, we arrive at this result: If one of two synchronous clocks at A is moved in a closed curve with constant velocity until it returns to A, the journey lasting t seconds, then by the clock which has remained at rest the travelled clock on its arrival at A will be second slow.
Next, since the y-axis is perpendicular to the line of travel, it is not length contracted. So, assume both frames the distance the pulse traveled is d.
Also, assume the time on the clock with the stationary observer is t.
By SR, c = d/t.
However, since the moving clock moves in a circle, then there exists some very very small time differential from the stationary clock, say t'.
Then, we must apply Einstein reasoning, the moving clock shows a time of t/γ.
So, the actual time on the moving clock is t' + t/γ.
According to Einstein, c is a constant between the frames and time dilation is a result of this assumption.
Now, since t' is absolute, we can remove t' from the calculations and all we have left is what Einstein claimed as the time on the moving clocks as t/γ.
But, that means, c' = d/(t/γ) for the moving clock.
We also have c = d/t for the stationary clock. But, under SR all observers must measure c as the speed of light.
Hence, c = d/t = c' = d/(t/γ). This means γ=1.
But, if γ=1, then v = 0, which is a contradiction.
There is the specific math and logic.
Your turn with your math.
