MetaKron said:
Billy, besides the fact that you are an ignorant bastard, a lot of progress has been made since it was hard to get a space capsule to splash down on target in the Pacific. Why don't you go shoot your psychiatrist or something?
I do not call names. Instead I suggest you consider the weight of fuel required at Earth launch to return your 400 pound missile (intact) to the Earth. To help you, I define some terms. All refer to fuel weight only:
T = Tomahawk flight fuel (about 30 pounds per 100 miles - I think.)
Wo = for Low Earth Orbit, LEO, altitude.(straight up, no orbital velocity)
W1 = for Synchronous Orbit SO, altitude.(straight up, no orbital velocity)
W2 = for near zero speed at gravity "cross-over" point. (moon gravity stronger than Earth's)
W3 = for soft landing on moon. Fall to moon will have terminal velocity of approximately 2.37Km/sec or the "escape velocity" of moon. (Everything would be destroyed on moon impact unless more than 99% of this is removed by "retro rockets" as there is no air to skip in and out of to loss energy acquired in the fall to moon.)
W4 = for lift off of moon. Again need to acquire nearly the escape velocity.
W5 = for slowing fall to Earth. If enter atmosphere at Earth's escape velocity, 11.2 Km/sec everything is destroyed. Skip in and out of thin high atmosphere after this "retro burn" of W5 fuel to lose more speed and be able to descend thru the denser high atmosphere. (You can not re-enter significantly faster that the Shuttles does from only LEO.)
W6 = T = for terminal flight - Because of the skipping in thin high atmosphere is very hard to predict and control, you need reserve fuel for several hundred mile correction to target, but any not burnt by good luck in the skips, is part of the destructive payload.
Lets crudely compare these fuel burns, in each stage for transport of your 400 "Rock" of missile with reentry guidance NOT CONSIDERING that each EARLIER stage must lift the fuel for all LATER stages. I.e. the relative fuel burn per Kg requirements:
T < < Wo
Wo < < < W1
W1 < < W2
W3 = W4 = ~ W5 = ~W6 = ~ T = about 100 pounds for a 300 mile range.
Now let us even more crudely give some recognition to fact the fuel burned in later stages greatly increases the fuel required by all the earlier stages. (This all should be done with the "rocket equations.")
W6 = 100 lbs
W5 = 1000 lbs (Had to de-accelerate 400lbs of rocket + W6 fuel = 500lbs)
W4 = 5000 lbs (Had to lift off moon 1500 lbs)
W3 = 20,000 lbs (Had o stop 6500 lbs from crashing into moon - soft land on moon)
W2 = 100,000 lbs (Had to lift 26,500 lbs from SO altitude to cross-over point)
W1 = 400,000 lbs (Had to lift 126,500 lbs from LEO altitude to SO altitude)
Wo = 800,000 (Had to lift 526,500 lbs from Earth surface to LEO altitude)
I do not know the cost of liquid Hydrogen and Oxygen (or what less efficient, more massive, fuel you will use for launch from moon) but am sure it is well above $12.5/lb so 800,000 pounds will cost at least $10,000,000. Lets estimate that the multi stage rockets are the same cost as the fuel. (Ground crews are expensive also.)
SUMMARY:
You are actually suggesting much more than about 20 million dollars be spent to avoid firing a 50 thousand dollar Tomahawk missile, because there are no "moon men" to unload your economical, un-man, "cargo ships."
How do you pan to:
(1)Off load the missiles from the cargo ships. (Because of Moon's low gravity two men probably can lift the 1500 lbs = W3, earth weight, of the missiles off transport racks and carry them to launchers, if launchers are not more than 1000feet away, but it will be hard work in spacesuits.
(2)Make firm launch pads for the launchers.
(3)Set up the missile launchers.
(4)Aim and test.
(5)Step thru the launch routine. I think about 10, highly trained men on moon as minimum will be required for this, not counting all several hundred on earth, backing them up. All must be safely delivered to moon and returned to Earth (years later? or do you plan to start WW3 ASAP?)
These are just a few of the reasons why would plan will actually cost at least 200 million dollars to fire the first missile! For that sum, you could have fired about (2x10^8) /(5x10^4) = 4,000 Tomahawk missiles (and I am sure if you work thru the numbers less crudely, at least 10,000 Tomahawk missiles.)
Make some contact with reality, before it is too late.