OK...at the very least I think we've identified our point of disagreement. My stance is that Schwarzschild coordinates have a special physical meaning whereas Kruskal coordinates do not. Would you agree that if that were the case then the Kruskal treatment of black holes does not provide evidence of their existence?
No, for a number of reasons:
1) Very simply, it's a non sequitur. "Physical meaning" is a vague catch-all that could mean anything, and it does not follow that a singularity in the coordinates represents anything physical just because you, me, Misner, Thorne, and Wheeler, or anyone else think the coordinates satisfy some value of "physical meaning".
2) Due to the coordinate singularity at the Schwarzschild radius, it's dubious at best to claim they have any meaning at all there (whether you think the singularity is physical or not).
3) General relativity, as part of its foundation, is based on the principle of general covariance (i.e. coordinate system independence). If you study general relativity in a course or from a textbook, or even from some of Einstein's original publications, literally the first thing you learn is how to cope with completely arbitrary coordinate systems in relativistic physics. So if you make
any argument that requires treating some coordinate system as "special", I'd consider it contrary to the spirit of GR and view it with extreme suspicion.
4) Even ignoring point 3), arguing some principle of "physicality" based on Schwarzschild coordinates is hopelessly ad hoc and wouldn't generalise to the rest of GR. Most of the time, in GR, there is
no coordinate system that has all the geometric niceties that Misner, Thorne, and Wheeler describe in the passage you quote from their book. So if you decide those geometric features are so important to you that you could never part with them, you really shoot yourself in the foot. You'd be unable to cope with any physical system in GR that didn't happen to be static and spherically symmetric.
From GRAVITATION (Misner, Thorne, Wheeler, pg 596), Physical interpretation and geometrical significance of the Schwarzschild coordinates:
[...]
Misner, Thorne, and Wheeler list geometric features of Schwarzschild coordinates that are completely consistent with what I told you in the third part of [POST=3156938]post #66[/POST]. They also say of the coordinate singularity at the Schwarzschild radius:
MTW said:
The Schwarzschild spacetime geometry
$$ds^{2} \,=\, - \, \Bigl(1 \,-\, \frac{2M}{r} \Bigr) dt^{2} \,+\, \frac{dr^{2}}{1 \,-\, 2M / r} \,+\, r^{2} (d\theta^{2} \,+\, \sin^{2} \theta d\phi^{2}) \qquad (31.1)$$
appears to behave badly near $$r \,=\, 2M$$; there $$g_{tt}$$ becomes zero, and $$g_{rr}$$ becomes infinite. However, one cannot be sure without careful study whether this pathology in the line element is due to a pathology in the spacetime geometry itself, or merely to a pathology of the $$(t,\, r,\, \theta,\, \phi)$$ coordinate system near $$r \,=\, 2M$$. [...]
The worrisome region of the Schwarzschild geometry, $$r \,=\, 2M$$ is called [...]. It is also called the "Schwarzschild singularity" in some of the older literature; but that is a misnomer, since, as will be shown, the spacetime geometry is not singular there.
MTW said:
Since the spacetime geometry is well behaved at the gravitational radius, the singular behaviour there of the Schwarzschild metric components, $$g_{tt} \,=\, -\, (1 \,-\, 2M/r)$$ and $$g_{rr} \,=\, (1 \,-\, 2M / r)^{-1}$$, must be due to a pathology there of the Schwarzschild coordinates $$t,\, r,\, \theta,\, \phi$$. [...]
and so on, and soon quite happily go on to describe various other coordinate systems, including Kruskal-Szekeres. So however much "geometric meaning" Misner, Thorne, and Wheeler think the Schwarzschild coordinates might have, they plainly don't think it should extend to treating the Schwarzschild chart as special or the coordinate singularity as physical.
I mean, really, what were you hoping to achieve by quoting Misner, Thorne, and Wheeler at me? "You must be wrong, przyk. Look, here's this book written by these famous authors who completely agree with everything you told me!"
The book goes on to mention that these are not the ONLY coordinates with such properties and identifies
Isotropic Coordinates as another system which adheres to these criteria. Unfortunately, isotropic coordinates would continue to
expose the same coordinate problem at the event horizon.
No they don't. Put $$r_{1} \,=\, r_{\mathrm{s}} / 4$$ into the metric expression and see for yourself what happens. You'll find that the $$g_{rr}$$ metric component is just 4 (by contrast with Schwarzschild coordinates, where it becomes infinite). The $$g_{tt}$$ component is still zero, but that's hardly surprising since both charts use the same $$t$$ coordinate.
(Also, technically, isotropic coordinates don't all "adhere to the same criteria". A spherical shell in isotropic coordinates of radius $$r$$ won't have a surface area of $$4 \pi r$$ unless $$g(r) \,=\, 1$$, which isn't the case for the isotropic version of the Schwarzschild metric you linked to except in the limit $$r_{1} \,\to\, \infty$$.)