ok ...maybe this will help...
If we take on this duality of d= ? and d=0
If we consider for a moment that the photon is only a wave and simultaneously consider that the vibration is also a wave.
The only difference is in the delivery of that wave. [ an abstraction to help with understanding]
with d=? [photon wave ] the wave must take time to travel from source to reflector. Regarding d=0 [resonance wave] time is not present but the effect is the same.
[note even calling it a resonance wave implies time and this can be misleading as no time is involved]
So the refraction of the resonance wave would be exactly as it is for the photon wave. The effect would be exactly as already recorded.
The only difference is that the reflecting point resonance is occuring upon that reflective point and not traveling to that point
For example say we have light passing through an aquarium full of clean water.
No matter were you put and object of mass in that water [ even a grain of sand] the resonance will occur at that position [ of the sand] and give the same effect as if we have photon waves travelling. The delay in the reflector [sand]changing to harmonise is shown as 'c'. rather than 'c' being d/t between source and reflective point.
The only thing that is taken out of the equation is the distance therefore time, between source and reflective point.
<img src=http://www.ozziesnaps.com/ozziemate/images%20general/sundry%20Diagrams/diagram%20moon%20shadow1a.gif>
Just a simple shadow diagram with circles described to indicate reflective resonance points as a distance from the source.
The resonance being absorbed by the obstructive object thus casting a shadow.
If we take on this duality of d= ? and d=0
If we consider for a moment that the photon is only a wave and simultaneously consider that the vibration is also a wave.
The only difference is in the delivery of that wave. [ an abstraction to help with understanding]
with d=? [photon wave ] the wave must take time to travel from source to reflector. Regarding d=0 [resonance wave] time is not present but the effect is the same.
[note even calling it a resonance wave implies time and this can be misleading as no time is involved]
So the refraction of the resonance wave would be exactly as it is for the photon wave. The effect would be exactly as already recorded.
The only difference is that the reflecting point resonance is occuring upon that reflective point and not traveling to that point
For example say we have light passing through an aquarium full of clean water.
No matter were you put and object of mass in that water [ even a grain of sand] the resonance will occur at that position [ of the sand] and give the same effect as if we have photon waves travelling. The delay in the reflector [sand]changing to harmonise is shown as 'c'. rather than 'c' being d/t between source and reflective point.
The only thing that is taken out of the equation is the distance therefore time, between source and reflective point.
<img src=http://www.ozziesnaps.com/ozziemate/images%20general/sundry%20Diagrams/diagram%20moon%20shadow1a.gif>
Just a simple shadow diagram with circles described to indicate reflective resonance points as a distance from the source.
The resonance being absorbed by the obstructive object thus casting a shadow.
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