I have a partial equation that finds the velocity of x, and the time to the receiver at x, if the y time is known, and the y and z component velocities are zero, which goes like this:
v(x)=sqrt(t(y)^2-l(y)^2)/t(y)
t(x)=l(x)/(c-v(x))
Using a cube with sides of length 1 light second, and a light source that remains at the center of the cube, with receivers in the center of the x,y, and z walls, given a y and z time of .65 seconds, I know the x component velocity and the x component time to receiver.
x time= 1.384930 seconds
y time= .65 seconds
z time= .65 seconds
x component velocity = 0.638971 c
y component velocity = 0 c
z component velocity = 0 c
The location of the y receiver at .65 seconds is (0.41533, .5, 0)
x= .65(.63897c)=.41533
y= .5
(0.41533, 0.5, 0)
d = sqrt(0.41533^2 + 0.5^2 )
d = sqrt(0.1724990089 + 0.25)
d = sqrt(0.4224990089)
d = 0.65 light seconds
BTW...look what v=(ct-l)/t says the x component velocity is:
v(x)=(1.384930-.5)/1.384930
v(x)=.63897 c
This example shows that speed of light is not measured to be c in any direction inside the box.