theorist-constant12345:
You have moved on an introduced new irrelevancies rather than dealing with the topic we were originally discussing.
No, youre immersed in the light, you are already are connected to the emission, you see an object that reflects light because the surface of the object is different to the emission constant
I previously asked you to explain what this kind of statement means.
As far as I can tell, it's meaningless blather. Even you can't explain it, and they're your words. You're wasting my time.
It is not a magical connection, it is a development by evolution. The emission constant is the Sun, that emits light at a constant speed that is a constant one frequency because the visible spectrum is mixed into one frequency. A constant see through emission.
It is clear that you don't know what the word "frequency" means, or the word "spectrum". If you did, you wouldn't make this kind of self-contradictory statement. You're wasting my time.
Light is ejected from the sun at a constant speed, a constant that changes by making contact with a surface , an exchange rate that is constant but different to the emission constant, a bottle necking of the constant, a stop pass filter that allows propagation of light to the wavelength .
More blather. Surely you must be trolling.
happens to travel in the right direction, is not logical, a coupling by the light to objects is logical.
From a distance, many sources of light are effectively point sources that emit in all directions. It is both logical and not surprising that you can see some light emitted from something like the Sun or a light blub, both of which emit light in all directions.
I gave a simple statement, we are immersed in the light so why would light have to enter our eyes when the light is constantly in your eyes.
Why is it dark when you close your eyes?
It is not logical that when I look across the horizon that all matter and mediums are all reflecting rays of light equal to the shape of the objects in all directions and to my eyes, the underneath of a cloud for example, are you saying that light hits the ground and reflects back up to the clouds underneath then back off the cloud at an angle to me eyes?
Some sunlight filters through cloud from above. Some is reflected onto the bottom of the cloud from below. (Clouds can also be lit by sources of light on the ground.) Also, the air scatters sunlight. That is why the sky looks blue.
A bit far fetched I feel when we can clearly observe an actual white light ray through a cloud on an overcast day where there is a break in the cloud and it allows the congestion pass through at a slower rate allowing you to see white light through the clear light.
When you see a "ray" of sunlight through a break in the clouds, what you're actually seeing is sunlight reflected from water or dust in the atmosphere where the "ray" is. Some of that reflected light happens to travel towards your eyes, so you see it.
I disagree a wave will create an interference pattern around an object, a shadow is the obstruction of light but not without light, the dark passive space becomes more observable in a shadow, a translucency of the dark by a decrease in the volume energy.
I said I'd ignore interference effects for now, because they are beyond you. Any light you see in the shadow of an object has been reflected from something else. From example, turn on the light in a bedroom and have the corridor outside dark. Light spills out the door of the room. Outside the straight-line shadow of the door edges (in the corridor), the floor is dark. Not completely dark though! Why not? Not because light from the room turned the corner, but because some of the light from the room went out, reflected off floor, ceiling, walls, objects in the corridor etc. and then off the floor in the "shadow" region and to your eyes.
You have to be careful when you do these kinds of experiments to eliminate "stray" reflections. Otherwise, you can get the wrong idea.
Mind you, I thought it would be fairly obvious to most people that light travels in straight lines and doesn't turn corners.
The frequency of sight is equal to the wave(s) of the mixture of white light, the mind and eyes are equally tuned in to the frequency(s).
Meaningless.
''The
flicker fusion threshold (or
flicker fusion rate) is a concept in the
psychophysics of
vision. ...
A distraction. I am not interested in pursuing this tangent with you.
Sight is equal to the ''white light'' flicker threshold, a timing synchronisation , time-variant fluctuations of intensity and time varying exchange rates of light with matter.
Nonsense piled on nonsense.
''The
phi phenomenon is the optical illusion of perceiving continuous motion between separate objects viewed rapidly in succession. ....
Another distraction. I am not interested in pursuing this tangent with you.
Are Photons not rapid separate objects viewed rapidly in succession?
No.
Is the white light mixture not a white noise phi phenomenon?
It's nothing of the kind.
''A special case is white Gaussian noise ...
Another distraction. I am not interested in pursuing this tangent with you.
My process formula F=P/ab/t=f
where F is the covariance force and P is the pressure applied from the force that is equal to the spectral magnitude frequency, (a) being the covariance xyz, and (b) being the object with constant exchange rate value and where t is time and f is frequency.
This is pure crap, and you know it.
Show me the derivation of your "process formula", or admit you are a troll.
It is really simple my idea in simple terms is that the white light value is zero, since the image of
X is
countable, the probability mass function
fX(
x) is zero for all but a countable number of values of
x.
Meaningless blather.