The conference hall debate!

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You are not understanding that visible light spectrum energy range is by device and not by sight. By sight visible white light is not visible it is clear,invisible, the perceived image is because of a device making a visible wave and value, this is where and why science is making this confusing. Forget your device read outs.
What device is at work when I look at the Sun and see white light? Which device is making a visible wave and value? Which device is reading out something?
 
This is the best you can do? I wrote you a lengthy post, and you've got a one-line reply about something I didn't mention. Are you trolling?

You only "see" something when light enters your eye. You don't see any light that crosses in front of your eyes (e.g. from left to right between your eyes and your computer screen). Light must hit your retina for you to see something.


Sensed how? With a magical sixth sense?


You seem incapable of explaining yourself clearly. Is English your first language?


I don't understand what you're saying here.

Are you saying that there's still some light in a dark room? Nobody is arguing with that.
Are you saying that there are other types of EM radiation other than visible light? Nobody is arguing with that.
Are you saying something completely different? If so, then why can't you explain what you're saying?


Human eyes are not as sensitive as, say, the eyes of a cat or an owl. Is this a big mystery to you?


The photoreceptors on your retina will not fire with very low energy light.


Why do you think that?


You do not observe "clear". "Clear" is not light. Clear is a property of an object or medium. You can't see air because light passes through it. That's not you observing "clear". Anything you see through the air is a result of light passing through the air and entering your eye.

As for the spectrum, that is clearly seen through the use of a prism, or even in a rainbow.


Photons are "invisible" until they hit your retina. Then they dump their energy and you can see them. Nobody is arguing against that.
Sorry about the earlier post James I got distracted. I will break your post down and answer all of it the best I can. Thanks for the effort in the questioning.
 
1.
Huh..I understanding air and refractive index , you say the visible light passes through air , what visible light?
''This is the best you can do? I wrote you a lengthy post, and you've got a one-line reply about something I didn't mention. Are you trolling?

You only "see" something when light enters your eye. You don't see any light that crosses in front of your eyes (e.g. from left to right between your eyes and your computer screen). Light must hit your retina for you to see something.''

Ok, I am sitting here now with the light on , I can see objects , you are saying that the only light I am seeing is reflecting off objects into my eyes so I can see that object and in the space I see no other light than the reflected light from the object, is that correct?

If so, that does not make sense, why does light need to reflect from an object to our eyes for us to see that object?, when the light is on , is the room not full of EM radiation from the light source?, are we not immersed in the radiation incident ray(s)? are our eyes not automatically coupled to objects by being in the immersion of incident ray(s) from the source?


In short is light not already in our eyes by means of the source without reflective rays?




light in space is not seen it is sensed.

''Sensed how? With a magical sixth sense?''


Sensed by our eyes and photon receptors and sensed to be at an equal frequency to sight, a sensory perception that notices frequency or intensity change to the equal frequency to sight.



''Light is seen. If there is no light or EMR of any kind it would be dark.'' yes if there was no em energy it would be dark, for this you would need to be in a void. If you are not in a void then light still exists in the background, beyond your sight limitations.


''I don't understand what you're saying here.''

''Are you saying that there's still some light in a dark room? Nobody is arguing with that.
Are you saying that there are other types of EM radiation other than visible light? Nobody is arguing with that.

Are you saying something completely different? If so, then why can't you explain what you're saying?''


You did understand what I was saying.


At night outdoors in a forest you can not see, where as other species can see by use of low energy. Your eyes are open so why can you not see if the background light is still there?


''Human eyes are not as sensitive as, say, the eyes of a cat or an owl. Is this a big mystery to you?''

No, I know about a tapeum layer .No mystery .


If light is a thing, it should not matter how low the energy is or what the frequency is we should be able to see it compared to the dark.

''Why do you think that?''

Because things we can see, especially if that thing is giving off light or is light. How could it be possible to not see light in the dark if light is a thing.




I understand the whole of Em radiation and the spectrum. I am not arguing about the colours, I am arguing that the definition of visible that means is seen, I do not see light in space, I observe clear, you observe clear, everyone observes clear, the spectral range is seen on objects only, light is seen on objects by spectral magnitude, in the space it has no spectral magnitude , it is clear.

''You do not observe "clear". "Clear" is not light. Clear is a property of an object or medium. You can't see air because light passes through it. That's not you observing "clear". Anything you see through the air is a result of light passing through the air and entering your eye.

As for the spectrum, that is clearly seen through the use of a prism, or even in a rainbow.''


You cant see air because it has a little to none refractive index and is transparent to light, a passive element for light that does not interfere with light speed to a great effect, a light speed mixture of frequencies that travels so fast and is so expanded/stretched that you can not see it until it slows down fractionally becoming a visible spectral range of light by propagation of itself.
I am not arguing the spectrum is not visible light, I am arguing the Suns incident white light entanglement of spectral frequencies is not visible to sight because it is equal to sight.
 
What device is at work when I look at the Sun and see white light? Which device is making a visible wave and value? Which device is reading out something?
Your brain and eyes are at work when you look at the sun, I think the device is called an oscillator we use for waves?
 
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By sight visible white light is not visible it is clear,invisible, the perceived image is because of a device making a visible wave and value, this is where and why science is making this confusing. Forget your device read outs.
The only person here who is confused is you. Science only "makes it confusing" if you do not understand the science, which you do not.
 
theorist-constant12345:

You should enclose quotes in [quote][/quote] tags. It makes things clearer.

Ok, I am sitting here now with the light on , I can see objects , you are saying that the only light I am seeing is reflecting off objects into my eyes so I can see that object and in the space I see no other light than the reflected light from the object, is that correct?
There are only two ways you can see something:

1. The thing emits light directly towards your eyes.
2. Light reflects off the thing and enters your eyes.

If so, that does not make sense, why does light need to reflect from an object to our eyes for us to see that object?, when the light is on , is the room not full of EM radiation from the light source?, are we not immersed in the radiation incident ray(s)? are our eyes not automatically coupled to objects by being in the immersion of incident ray(s) from the source?
Light travels in straight lines through empty space (or air). A room can be full of light travelling in all different directions, but the only light you can see is the light that happens to be heading into your eye.

I have no idea what your idea of "coupling" involves. Our eyes don't "couple" to objects. Some of the light that is reflected or emitted by an object happens to travel in the right direction to enter our eyes, that's all.

Incidentally, this is why you can't see around corners: light travels in straight lines.

In short is light not already in our eyes by means of the source without reflective rays?
Light can travel in a straight line from a source directly to your eye. That's what happens when you look at a light bulb or the Sun. But to see an object that isn't emitting its own light, light must reflect off the object and then travel to your eye.

Sensed by our eyes and photon receptors and sensed to be at an equal frequency to sight, a sensory perception that notices frequency or intensity change to the equal frequency to sight.
Explain "frequency of sight" for me. What does that mean?

You: If light is a thing, it should not matter how low the energy is or what the frequency is we should be able to see it compared to the dark.

Me: ''Why do you think that?''

You: Because things we can see, especially if that thing is giving off light or is light. How could it be possible to not see light in the dark if light is a thing.
I already told you. It takes a certain amount of energy to cause the receptors on your retina to fire. If the light doesn't have enough energy, you won't see it.

You cant see air because it has a little to none refractive index...
The refractive index of air is 1.

...and is transparent to light
Visible light, yes.

... a passive element for light that does not interfere with light speed to a great effect, a light speed mixture of frequencies that travels so fast and is so expanded/stretched that you can not see it until it slows down fractionally becoming a visible spectral range of light by propagation of itself
Light travelling in air does not slow down appreciably. Sight does not depend on the speed of light, anyway.

I am not arguing the spectrum is not visible light, I am arguing the Suns incident white light entanglement of spectral frequencies is not visible to sight because it is equal to sight.
The sentence "The Sun's ... white light entanglement of spectral frequencies ... is equal to sight" is meaningless.

Try again to express yourself clearly.
 
theorist-constant12345:

You should enclose quotes in [quote][/quote] tags. It makes things clearer.


There are only two ways you can see something:

1. The thing emits light directly towards your eyes.
2. Light reflects off the thing and enters your eyes.

or you simply are already in the light so no reflection of light is needed to see.


Light travels in straight lines through empty space (or air). A room can be full of light travelling in all different directions, but the only light you can see is the light that happens to be heading into your eye.

Not true, we see through the light,light that travels across my path I can see through.

I have no idea what your idea of "coupling" involves. Our eyes don't "couple" to objects. Some of the light that is reflected or emitted by an object happens to travel in the right direction to enter our eyes, that's all.

happens to travel in the right direction, is not logical, a coupling by the light to objects is logical. The link is the light/energy.

Incidentally, this is why you can't see around corners: light travels in straight lines.

Light travels very well around corners, except less intensity, hence shadows.


Light can travel in a straight line from a source directly to your eye. That's what happens when you look at a light bulb or the Sun. But to see an object that isn't emitting its own light, light must reflect off the object and then travel to your eye.

No, youre immersed in the light, you are already are connected to the emission, you see an object that reflects light because the surface of the object is different to the emission constant


Explain "frequency of sight" for me. What does that mean?

The frequency of sight is equal to the wave(s) of the mixture of white light, the mind and eyes are equally tuned in to the frequency(s).
 
I am not arguing the spectrum is not visible light, I am arguing the Suns incident white light entanglement of spectral frequencies is not visible to sight because it is equal to sight.

The sentence "The Sun's ... white light entanglement of spectral frequencies ... is equal to sight" is meaningless.


Our brains are in timing sync to em radiation, tuned in to the white light frequency.
 
The Sun has gone , it is night, we can not see, however there is still light present , technically dark is not the absence of light but the absence of sight, and talking about dark on the surface and not pitch black in a cave.
 
Why is it, that I can reflect light into your eyes using a mirror, and glare your vision by changing the intensity, making you temporary blinded by the light? the opposite to the action of dark and removing sight, I can remove sight by increased energy entering your eyes making you ''bright blind''. An offset to the equilibrium I mention of white light.

This shows your brain is the converter of energy, not enough energy your brain sees dark, to much energy your brain becomes glared.

In either instant, you can not see.

You do not see with your eyes, your eyes are detectors, your brain does the seeing. Fact.
 
If light reflects into my eyes to allow me to see objects, why do I not observe in a dark smoke filled room any reflective ray from a laser incident ray being aimed at my wall?

I see no reflective ray(s) or a spatter reflective ray(s) , this evidence suggests no reflective ray(s).
 

This video is a laser observational experiment I did , using a water medium to show the incident beam , and to try and trace any reflective rays. We can observe that when the laser incident ray leaves the medium, it become invisible again from visible. I observe no reflective rays, or spread of the laser in the medium.

You can clearly observe the side of the glass being lit, but observe no reflective rays back through the medium.
 
The Sun has gone , it is night, we can not see, however there is still light present , technically dark is not the absence of light but the absence of sight, and talking about dark on the surface and not pitch black in a cave.

Light from the other stars is there, as is some light refracting through the atmosphere (the sun isn't "gone", just on the other side of the planet), and the moon of course reflects sunlight.

Why do we see this ''white light'' instead of all different colours? Why do we not see colours in ''white light'' with our eyes?
Because when the different colors of light combine, it is perceived as "white"... that's how your eyes and brain work...


Why is it, that I can reflect light into your eyes using a mirror, and glare your vision by changing the intensity, making you temporary blinded by the light? the opposite to the action of dark and removing sight, I can remove sight by increased energy entering your eyes making you ''bright blind''. An offset to the equilibrium I mention of white light.

This shows your brain is the converter of energy, not enough energy your brain sees dark, to much energy your brain becomes glared.

In either instant, you can not see.

You do not see with your eyes, your eyes are detectors, your brain does the seeing. Fact.


No, you can make someone temporarily blinded by overloading the retina... much like having a camera lens open too wide and thus washing out the picture (or sometimes even resulting in a pure-white exposure). Your brain does the "seeing" only insomuch as it is the seat of our consciousness - what you are describing is like trying to say that in a computer the monitor does the graphics - this is true only insomuch as it shows them to us, but the graphics card inside the tower does the actual processing.
If light reflects into my eyes to allow me to see objects, why do I not observe in a dark smoke filled room any reflective ray from a laser incident ray being aimed at my wall?

I see no reflective ray(s) or a spatter reflective ray(s) , this evidence suggests no reflective ray(s).

Laser light is highly focused, whereas normal light is highly scattered. Thus, laser light refracts and scatters very minimally - however, if you did not see any "reflective rays", then you would not SEE the laser, period.

Case in point - take a standard red laser pointer, and point it at an object - you will see a red dot, but no beam. This is because the laser is not of a high enough magnitude/power to be seen through the air.
Now, take a high power green laser pointer, and point it at an object - you will see the beam, at least partway to the object. This is because of the higher magnitude/power, which causes the amount of light being reflected off the particles in the air to be a high enough magnitude to be visible to the human eye.

http://physics.stackexchange.com/qu...beams-visible-and-other-laser-beams-invisible

As previous answers have stated, the wavelength (or frequency) and intensity of the beam are important, as well as the type and amount of impurities in the air. The beam must be of a wavelength that is visible to humans, and fog or dust scatters the light very strongly so that you can see it. However, even in pure, clean air, you will be able to see a laser beam under certain conditions.

This is because light can scatter from air molecules themselves via Rayleigh scattering. Rayleigh scattering has a strong inverse dependance on wavelength, specifically λ−4, so it will be easier to see with a green, and especially a blue, laser1. It also has a scattering angle dependance that goes like 1+cos2θ, so it may be easier to see if your viewing angle is very close to the beam2.

With a 5mW green laser pointer, Rayleigh scattering is pretty easy to see. I imagine it would be even easier with blue/violet, but I'm not sure, since human eyes are most sensitive at green, so that may tip the balance. A more intense beam, like those used at night clubs or laser light shows, would be very easy to see if the beam were held still, but in those situations the beams are moving around rapidly to produce the light show, so Rayleigh scattering alone wouldn't really let you see much. In situations like night clubs, the scattering from fog produced by fog machines is much more important.

You are correct that, in space, because there is no atmosphere and nothing to scatter off of, you wouldn't see any sort of laser beam.
 
Light from the other stars is there, as is some light refracting through the atmosphere (the sun isn't "gone", just on the other side of the planet), and the moon of course reflects sunlight.


Because when the different colors of light combine, it is perceived as "white"... that's how your eyes and brain work...





No, you can make someone temporarily blinded by overloading the retina... much like having a camera lens open too wide and thus washing out the picture (or sometimes even resulting in a pure-white exposure). Your brain does the "seeing" only insomuch as it is the seat of our consciousness - what you are describing is like trying to say that in a computer the monitor does the graphics - this is true only insomuch as it shows them to us, but the graphics card inside the tower does the actual processing.


Laser light is highly focused, whereas normal light is highly scattered. Thus, laser light refracts and scatters very minimally - however, if you did not see any "reflective rays", then you would not SEE the laser, period.

Case in point - take a standard red laser pointer, and point it at an object - you will see a red dot, but no beam. This is because the laser is not of a high enough magnitude/power to be seen through the air.
Now, take a high power green laser pointer, and point it at an object - you will see the beam, at least partway to the object. This is because of the higher magnitude/power, which causes the amount of light being reflected off the particles in the air to be a high enough magnitude to be visible to the human eye.

http://physics.stackexchange.com/qu...beams-visible-and-other-laser-beams-invisible


The Sun has gone , it is night, we can not see, however there is still light present , technically dark is not the absence of light but the absence of sight, and talking about dark on the surface and not pitch black in a cave.


Light from the other stars is there, as is some light refracting through the atmosphere (the sun isn't "gone", just on the other side of the planet), and the moon of course reflects sunlight.

I know about ambient light that was not my point. I know the Sun is not gone, it was just a figure of speech.

My point was that your perceived image is that it is dark, another species would deem it to be light, light is still present but without the intensity that allows us to see.
So we deem it the absence of light, the absence of visible light, dark, however the only dark that exists in this situation, is the lack of Neural stimulant by means of the eyes, a lack of sight and not the lack of light, because night vision goggles and other species are evidence that there is still lots of light to see by.




Why do we see this ''white light'' instead of all different colours? Why do we not see colours in ''white light'' with our eyes?

Because when the different colors of light combine, it is perceived as "white"... that's how your eyes and brain work...


Perceived as ''white'', so what do you mean by this?

''white
wʌɪt/
adjective
  1. 1.
    of the colour of milk or fresh snow, due to the reflection of all visible rays of light; the opposite of black.''

''perceive
pəˈsiːv/
verb
past tense: perceived; past participle: perceived
  1. 1.
    become aware or conscious of (something); come to realize or understand.''


I perceive ''white light'' to be evidentially clear light by the observation of now, I do not see a milk colour or snow colour , can you please define your definition of white?
 
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