Paul W. Dixon
Registered Senior Member
SUPERNOVA FROM EXPERIMENTATION AT FERMILAB, CERN, BROOKHAVEN AND LOS ALAMOS
The subjective impression of a nearby Supernova may be of interest in this connection also.
"If a supernova happened 50 light years from Earth, would it outshine the
Sun?
The amount of light produced in the core of a supernova is beyond
comprehension, and equals 10^54 ergs. The Sun emits 4x10^33 ergs/sec, so
in one blast a supernova produces more energy than the Sun does in about 3
x10^20 seconds or 10^13 years.
The luminosity of a supernova is this energy delivered over its roughly
week maximum brightness period which leads to 10^54 ergs/600,000 seconds =
2 x 10^48 ergs/sec or 4 x 10^14 times the output of the Sun. This is why
supernova regularly outshine entire galaxies of stars.
Now if such a supernova were 50 light years away, the flux would be L/(4
pi d^2) = 7 million ergs/sec/centimeters^2. The Sun at its distance from
the earth of 150 million kilometers delivers a flux of energy of 4 x 10^33
ergs/sec divided by 4 pi d^2 = 2 million ergs/sec/centimeters^2.
So, in very round numbers such a nearby supernova would deliver 7 times
more energy IN ALL FORMS than just the light energy we see from the Sun.
But a large fraction of the supernova energy goes into accelerating
particles, perhaps only 1 percent ends up in visible light, so although a
supernova would be a bright, intense pinpoint of light in the sky, my
guess is that it would be somewhere between a Full Moon and noon-day
sunlight. It would certainly light up the night sky probably to the
intensity of an overcast day. It would be quite an event to experience,
and it would stay this way for several months before fading.
Ask the Astronomer"
All the children will thank you for your kind actions on their behalf.
All Best Wishes,
Yours sincerely,
Paul W. Dixon, Ph.D.
Supernova from Experimentation
The subjective impression of a nearby Supernova may be of interest in this connection also.
"If a supernova happened 50 light years from Earth, would it outshine the
Sun?
The amount of light produced in the core of a supernova is beyond
comprehension, and equals 10^54 ergs. The Sun emits 4x10^33 ergs/sec, so
in one blast a supernova produces more energy than the Sun does in about 3
x10^20 seconds or 10^13 years.
The luminosity of a supernova is this energy delivered over its roughly
week maximum brightness period which leads to 10^54 ergs/600,000 seconds =
2 x 10^48 ergs/sec or 4 x 10^14 times the output of the Sun. This is why
supernova regularly outshine entire galaxies of stars.
Now if such a supernova were 50 light years away, the flux would be L/(4
pi d^2) = 7 million ergs/sec/centimeters^2. The Sun at its distance from
the earth of 150 million kilometers delivers a flux of energy of 4 x 10^33
ergs/sec divided by 4 pi d^2 = 2 million ergs/sec/centimeters^2.
So, in very round numbers such a nearby supernova would deliver 7 times
more energy IN ALL FORMS than just the light energy we see from the Sun.
But a large fraction of the supernova energy goes into accelerating
particles, perhaps only 1 percent ends up in visible light, so although a
supernova would be a bright, intense pinpoint of light in the sky, my
guess is that it would be somewhere between a Full Moon and noon-day
sunlight. It would certainly light up the night sky probably to the
intensity of an overcast day. It would be quite an event to experience,
and it would stay this way for several months before fading.
Ask the Astronomer"
All the children will thank you for your kind actions on their behalf.
All Best Wishes,
Yours sincerely,
Paul W. Dixon, Ph.D.
Supernova from Experimentation
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