In post #59, you clearly acknowledge that the scenario is defined according to times in the rest frame of M.First, post #53 clearly demonstrates I am talking about M' as stationary.
Perhaps we need to readdress how you this scenario is described.
So:
We start with the conditions of rest M:
A and B are equidistant and stationary with respect to M. Lightning strikes at A and B simultaneously with M' passing M.
Lightning strike at A:
(x,t) = (-d,0)
Lightning strike at B:
(x,t) = (d,0)
M' passes M:
(x,t) = (0,0)
OK? All the above is defined with M at rest.Lightning strike at A:
(x,t) = (-d,0)
Lightning strike at B:
(x,t) = (d,0)
M' passes M:
(x,t) = (0,0)
Now, we switch to working in the rest frame of M':
You said: "...assume there were M' observers co-located at B and A when the lightning strikes occurred at A and B and call them A' and B'."
However, that sentence is inconsistent with your following analysis, which implies that A' meets A at the same time as B' meets B.
Perhaps you meant this:
assume there were M' observers co-located at A and B when M is co-located with M' and call them A' and B'.
Does that sound reasonable? There are two immediate results of this change in the setup.First, we're not assuming anything about the simultaneity of the lightning strikes.
Second, we immediately get the results you calculated:
These statements are correct. Right?When M and M' are co-located, the distance from M' to B' is d/λ and the distance from M' to A' is d/λ.
Obviously, if B' is located at a rest distance d/λ, then M could conclude B' and B are not co-located at the time of the strike since M would view B' at a distance of d/λ^2.
Now, moving on:
We know the first is not true, because M' is stationary, as you correctly point out:To support Einstein’s conclusion that M' sees the light from B prior to A one of the following two possibilities must be true:
1. M' moves toward the lightning strike at B closing the distance for light to travel relative to the strike at A.
2. The strike at B occurs prior to the strike at A in the time coordinates of M'.
Possibility 1
Since M' is stationary, it is not moving. A, B and M are moving relative to M'. Sure, B closes the distance to M' as the light travels toward M' but this has nothing to do with the distance light traveled in the frame of M'.
And now we see that the earlier assumption about simultaneity has come back to bite us.Possibility 2
Since, there are the observers B' and A' co-located at the lightning strikes at A and B, it is impossible there is any disagreement between the frames as to whether light is moving along the x-axis or not. Hence, for example, if B' claims lightning just struck, B will make the same claim as well. So, it cannot be claimed the lightning appears for one frame at some location while a co-located observer claims light is not at that location. Therefore, perhaps the time on the clock of B' will show an earlier time than the clock of A' for the light strike and this explains it. In other words, the light emitted from B' before it emitted from A'.
You set up A' and B' so that A' meets A and B' meets B when M meets M'.
You assumed that this is also when lightning strikes A and lightning strikes B. Why?