plane:
You seem to be playing dumb, by homing in on what you apparently think are inconsistencies in the statements I have made, while at the same time ignoring the information that has been patiently given to you.
Still, as I said, I will try to explain things more carefully to you, since you seem to have trouble grasping things (whether this be innocent ignorance on your part or a wilful attempt at obfuscation).
You introduced the phrase “acceleration of gravity”. I inquired as to whether or not you meant “acceleration due to gravity”.
The wording is unimportant. We talked about meaningless semantics previously.
plane said:
JR said:
This is a meaningless semantic question again. M and m interact gravitationally, such that each experiences a force of the same magnitude. Take away either one of the two masses and the other experiences no force. So, both masses are required for a force to exist on either of them.
You cannot say that only one of the masses "causes" the force. The force only exists when there are two masses.
As you can see this is not consistent with
JR said:
The formula F=GMm/r^2 gives the magnitude of the force on one object (either M or m), and not some kind of "shared" force that applies to both objects. To make this clearer, let's consider the acceleration of one of the two objects instead of the force. Take object M to be the one creating the force (for example, M is the Earth), and object m to be the one experiencing the force
Take M to be the one creating the force/ you cannot say only one of the masses causes the force. At that point I elected to introduce the 10 - 4 diagram to try and get to the bottom of what you actually believe. As already explained, am without ability to do diagrams at the moment but as you can well see you lack coherency from page to page of this thread.
Your problem here comes back to Newton's third law again.
Newton's third law implies that ALL forces arise from interactions between two objects. Each object exerts a force of the same magnitude on the other, but the forces are oppositely directed. This is as true for a baseball hitting a bat as it is for an apple attracting the Earth gravitationally. This was the gist of my first quoted statement, above.
My second statement involves Newton's law of gravity. It allows us to calculate the magnitude of the gravitational force on
either of two objects (mass M and mass m). The
direction of that force will be opposite for each of the objects, but the
magnitude is the same for both - a fact that is in total agreement with Newton's third law.
My statement that the law of gravity gives the force on one object has to do with the interpretation of that law, including the directional information. It also has to do with the definition of the term "force" itself. I was trying to make clear to you that a force, by definition, only ever acts on one object. When we talk about "a force", we always mean a force that is "caused" by one object and acts on another. So, for example, I can talk about the "force on an apple due to the Earth" or the "force on the Earth due to the apple". In this example, there are
two forces. One acts on the apple, one acts on the Earth. As it happens, the two forces have the same magnitude in this case, but opposite directions. In technical terms, they form what is known as an action-reaction pair of forces, in the terminology of Newton's third law.
So, when I wrote this:
JR said:
Take object M to be the one creating the force (for example, M is the Earth), and object m to be the one experiencing the force
I was merely indicating to you that I wished to select out mass m as the object being acted upon and mass M as the object causing the action. Why? Because I wished to look at the acceleration of mass m, and to determine that I needed to look at the force
on mass m only. There is, of course, an equal and opposite force on mass M due to mass m, but for the purpose of my discussion at the time, I did not wish to consider that.
I hope this clears up your misunderstanding of this simple issue. I really can't be much clearer.
Think you mean its mass is the same. A free falling body is weightless.
That depends on how you define "weight". For clarity, let me tell you how I define it. I define the weight of an object to be the gravitational force exerted on it. Using this definition, a free-falling object is not weightless.
There is, however, no universally agreed definition of "weight". Some physicists prefer to define weight as what a scale would measure. I prefer to call that "apparent weight". For an object in free fall, a scale will read zero, and so the object has no apparent weight. But it still has weight, according to my definition.
I hope this also clears up any confusion you have on this point. Having explained how I am using the word "weight", we will now be on the same page.
This is where you completely lose me. Go back to the diagram in post 78 and your reply in post 79. Your answer says nothing but Newton’s law of gravity was deduced from Newton’s second law. You are all over the shop. There is nothing clear and consistent coming through.
Newton's second law contains nothing about the inverse-square nature of Newton's law of gravity. This alone ought to make it clear to you that the law of gravity cannot be deduced from Newton's second law. On the other hand, Newton's method of arriving at the law of gravity involved a process both of induction from observation and deduction using his other knowledge of the laws of motion. Perhaps this confused you.
You’re doing it again. You are saying the force applied to m is dependent on the magnitude of m.
That is true for gravitational forces, according to Newton's law of gravitation. Just look at the equation if you're in any doubt.
Like saying the force a bat applies to a ball is dependent on the mass of the ball.
A bigger ball (in terms of mass) will require a greater force relative to a smaller ball to be accelerated at the same rate.
But basically, get a bigger faster bat, more force applied to any sized ball.
You're mixing all kinds of concepts here.
When a bat hits a ball, then according to Newton's third law, both the bat and the ball experience forces of equal magnitude and opposite directions. The bat exerts a force on the ball; the ball exerts a force on the bat. If you do not believe that the ball exerts a force on the bat, you need to explain why you can feel the ball hitting the bat, though the handle.
If the force exerted by the bat on the ball is F, then the acceleration of the ball is
a = F/m
where m is the mass of the ball. So, what you said about the effect of the mass of the ball is correct. Bigger m requires more F for the same acceleration.
You may well be able to apply more force if you get a more massive bat, or swing it faster. I am puzzled as to how you think this is relevant to gravity.
Thanks for agreeing that Newton didn't investigate what happens where opposite directions of a field meet. Such is irrelevant to the super position of forces.
Ok. If it's irrelevant, I won't worry about addressing it.