I used what little knowledge I had and solved major issues in your field. You have tons of knowledge and solved nothing.
You have solved no major issues. You are still lost trying to understand how to do the math, and if you think you solved anything it was by failing to understand what the issues actually are. So far all or most of the formulations and solutions I've seen you do are wrong, or if they are right you seem confused by what they mean.
Two identical cars (except for engine and gears, same weight) are moving along at a steady 24 mph in second gear side by side. They both punch it at the same exact time. Which one will pull ahead immediately, and get to 67 mph the soonest, and cover the greatest distance in the same time period? The one with the greatest engine TORQUE, or the one with the greatest engine HP??
Torque by itself does not have units of power; you have to know the angular velocity to compare it to power. The question of who wins is answered by who has more power at the wheels. Since wheel size is the same, the angular velocities are the same for the same vehicular speeds. Therefore it's fair to compare them by their rear wheel torques to ascertain which has more power. By your data, that would be B.
Wheel torque is proportional to engine torque by the net gear ratio. Therefore it's fair to compare them by their engine torques, factoring for each net gear ratio, but that will give the same results as above since you gave us redundant information.
As for comparing by horsepower, this is a true power measurement, so it need not take into account the angular velocity of the crankshaft. If the cars were lossless, and there were no reactances in the engines, drivetrains or chassis, we could judge by horsepower alone. However, you could have left the hp numbers out and I could have filled them in for you, since your numbers assume no losses; by simply multiplying engine torque by angular velocity of the crank I got your hp numbers. Therefore this criteria also follows the same results as above.
SI units simplifies this. I converted your numbers to SI, and noticed you lost some accuracy by limiting your hp numbers to 3 digits of precision. This is also a problem in measurement, when high accuracy may not be possible due to instrument and test fixture limitations. It would tend to suspect a dyno that claims to be better than 3 digits, so maybe that was the source of the error. Here are my SI numbers.
_crank_|_eng trq|_eng pwr|_speed__| rw trq | error
rad/s__|__N•m___|___W____|__m/s___|__N•m___|__W__
(A)
209.44 | 629.10 | 131243 | 10.729 | 4022.7 | 515
261.80 | 653.50 | 170765 | 13.411 | 4178.6 | 322
314.16 | 672.49 | 211033 | 16.540 | 4300.7 | 235
366.52 | 692.82 | 253538 | 19.223 | 4430.8 | 395
418.88 | 686.04 | 287094 | 21.905 | 4387.4 | 275
471.24 | 652.15 | 307228 | 24.587 | 4170.5 | 89
523.60 | 578.93 | 302754 | 27.269 | 3701.4 | 375
575.96 | 492.16 | 283366 | 29.952 | 3146.9 | 99
(B)
241.80 | 555.89 | 134226 | 10.729 | 4105.4 | 186
302.33 | 583.00 | 175985 | 13.411 | 4304.7 | 271
362.75 | 623.68 | 225947 | 16.540 | 4605.7 | 291
423.17 | 630.46 | 266215 | 19.223 | 4655.9 | 577
483.70 | 630.46 | 304246 | 21.905 | 4655.9 | 706
544.12 | 603.34 | 328108 | 24.587 | 4455.2 | 183
604.55 | 528.77 | 319160 | 27.269 | 3904.8 | 506
665.08 | 447.42 | 297534 | 29.952 | 3304.1 | 34
In short your question asked us whether we understand that angular velocity divides by gear ratio, and does power, and does torque multiply, and the answer is: yes, we do.