Time to feed to the troll....
Lets take a simple deterministic system where the input is a number, the output is that number + 1, which is then the next input to the system.The only response you offer is what you have just posted... nada..
again you have not addressed why only one path...
and simply repeat what you have posted ad nauseum...
You have to explain why there can only be one path as the logic you are using is insufficient when dealing with living and learning human beings...
So whatever starting condition (x) you begin with, there is always a singular possible output associated with it: x+1.
That output becomes the next input, so the following output is x+2, then x+3 etc.
Following?
So, from a given starting point, there is a single, predictable, and predetermined path that the system follows.
This is true of all deterministic systems.
This is what it means for a system to be deterministic: every time you have a given input to the system you have the same output, which is the next input to the system.
Follow the logic of it.
Once the system starts with its initial condition, where in this example do you see there being any other chain of predetermined inputs/outputs than the one perfectly described, and perfectly predictable, and predetermined, by the initial condition and the law of the system?
The very idea of having “multiple (infinite) predetermined potential pathways” is mutually exclusive to a deterministic system once it has started.
There is no potential for any other than the one pathway once the system begins.
Try it with the example given.
Input a starting condition, and then tell me who you think you can talk about there being others predetermined potential pathways.
I await your startling revelation of these multiple predetermined potential pathways.