AlphaNumeric, I don't want to bash you, I am more interested in intellectual discussion. The subject of General Relativity is at least 80 years old, however it has only come to real favor over the last 15 years. And this mostly due to our advanced telescope technology and our high energy colliders.
So although we can have some, as well as a firm understanding of the math and physics of spacetime, we including myself are still interesred in learning new things from people such as yourself about the math and physics of GR, Cosmology, and High Energy Physics.
Part of growing and learning is engaging in discussions with others that do not necessarily agree with you, and hearing their ideas, wrestled against the facts; that in my opinion is what posting in these forums is about.
Agreed.
I dont agree with you here. The Schwarzschild Radius is truly a vector having both a magnitude or scalar quantity as you point out, and it is also a vector quantity.
Lets stick with Spherical Coordinates. And call the Schwarzshild Radius a static "black Hole" event horizon, which is an isolated net inertial mass system located in some region of space. The space and time in the local vicinity of the mass creates a gradient field in space, and where the curvature is most maximum in that gradient field, is define by the Spherical body whose vector radius is the Schwarzschild Radius. The closed Geodesic associated with the matter and energy in that location is Source of Curvature.
Schwarzschild Radius Vector - Tensor
$$r_{S} \^r = \2 (\frac{m_{net}G} {c^2}) \^r = (\frac{\frac{1}{2}\ m_{net}c^2} {\frac{1}{4} \frac{c^4}{G}}) \^r = (\frac{T_{ab}} {\frac{1}{4} \frac{c^4}{G}})= \frac{G_{ab}}{2 \pi} $$.
Spacetime Metric for Non Expanding Spherical Net Inertial Mass Body at the Schwarzschild radius Event Horizon
$$s^2 = \({r_{S}^2} + \ {r_{S}^2}\({a}^2 + \ b^2 \sin^2(a_0))$$.
Vector for Non Expanding Spherical Net Inertial Mass Body at the Schwarzschild radius Event Horizon
$$s \^r = \({r_{S}\^r} + (\ {r_{S}{a})\^a} + ({r_{S}{b}}) \sin(a_0) \^b$$.
Schwarzschild Radius - - $$r_{S} -> m $$
Net Inertial Mass - - $$m_{net} -> kg$$
Rest Energy - - $$E_{Rest} = m_{net}c^2 -> \frac{kgm^2}{s^2}$$
Speed of Light - - $$c -> \frac{m}{s}$$
Universal Gravitational Constant - - $$G -> \frac{m^3}{kgs^2}$$
Source of Curvature Geodesic - - $$G_{ab} -> m$$
Riemann/Ricci Maximum Curvature Geodesic - - $$R_{ab} -> m$$
Stress Energy Tensor - - $$T_{ab} -> \frac{kgm^2}{s^2}$$
Tensor Indices, Latitude & Longitude Direction Angles - - $${(a), (b)} -> radians$$
I believe that the units do match!
Best.
So although we can have some, as well as a firm understanding of the math and physics of spacetime, we including myself are still interesred in learning new things from people such as yourself about the math and physics of GR, Cosmology, and High Energy Physics.
Part of growing and learning is engaging in discussions with others that do not necessarily agree with you, and hearing their ideas, wrestled against the facts; that in my opinion is what posting in these forums is about.
Not all systems have closed geodesics. A sphere is a simple case which does, due to its uniform positive curvature. A space with negative curvature will not have any closed geodesics.
Agreed.
That equation is flat out wrong. $$G_{ab}$$ is a rank 2 tensor, $$2\pi r_{S}$$ is a scalar. You've made the same mistake I've previously pointed out. If you didn't understand what I said and you don't understand why its wrong then you have no business claiming to grasp any general relativity because you're making a mistake in basic linear algebra, never mind GR.
I dont agree with you here. The Schwarzschild Radius is truly a vector having both a magnitude or scalar quantity as you point out, and it is also a vector quantity.
Lets stick with Spherical Coordinates. And call the Schwarzshild Radius a static "black Hole" event horizon, which is an isolated net inertial mass system located in some region of space. The space and time in the local vicinity of the mass creates a gradient field in space, and where the curvature is most maximum in that gradient field, is define by the Spherical body whose vector radius is the Schwarzschild Radius. The closed Geodesic associated with the matter and energy in that location is Source of Curvature.
Schwarzschild Radius Vector - Tensor
$$r_{S} \^r = \2 (\frac{m_{net}G} {c^2}) \^r = (\frac{\frac{1}{2}\ m_{net}c^2} {\frac{1}{4} \frac{c^4}{G}}) \^r = (\frac{T_{ab}} {\frac{1}{4} \frac{c^4}{G}})= \frac{G_{ab}}{2 \pi} $$.
Spacetime Metric for Non Expanding Spherical Net Inertial Mass Body at the Schwarzschild radius Event Horizon
$$s^2 = \({r_{S}^2} + \ {r_{S}^2}\({a}^2 + \ b^2 \sin^2(a_0))$$.
Vector for Non Expanding Spherical Net Inertial Mass Body at the Schwarzschild radius Event Horizon
$$s \^r = \({r_{S}\^r} + (\ {r_{S}{a})\^a} + ({r_{S}{b}}) \sin(a_0) \^b$$.
.You're doing a more abstract version of saying "4 seconds = 10 kilograms". Units don't match therefore its wrong. If tensor rank doesn't match then its wrong, no ifs, no buts.
Schwarzschild Radius - - $$r_{S} -> m $$
Net Inertial Mass - - $$m_{net} -> kg$$
Rest Energy - - $$E_{Rest} = m_{net}c^2 -> \frac{kgm^2}{s^2}$$
Speed of Light - - $$c -> \frac{m}{s}$$
Universal Gravitational Constant - - $$G -> \frac{m^3}{kgs^2}$$
Source of Curvature Geodesic - - $$G_{ab} -> m$$
Riemann/Ricci Maximum Curvature Geodesic - - $$R_{ab} -> m$$
Stress Energy Tensor - - $$T_{ab} -> \frac{kgm^2}{s^2}$$
Tensor Indices, Latitude & Longitude Direction Angles - - $${(a), (b)} -> radians$$
I believe that the units do match!
Best.