Can you show us those calculations?
Here's one example.
Magnesium.
Talc has the composition $$Mg_3Si_4O_{10}(OH)_2$$
This can be written as $$3MgO.4SiO_2.H_2O$$
$$M_{Mg}=24.305 gmol^{-1}$$
$$M_{Si}=28.0855 gmol^{-1}$$
$$M_O=15.9994 gmol^{-1}$$
$$M_H=1.00794 gmol^{-1}$$
So, $$M_{3MgO.4SiO_2.H_2O}$$=(24.305*3)+(28.0855*4)+(15.9994*12)+(1.00794*2)
$$M_{3MgO.4SiO_2.H_2O}$$= 72.915+112.342+191.9928+2.01588
$$M_{3MgO.4SiO_2.H_2O}$$= 379.26568
The percentage of Magnesium in Talc can be calculated by $$\frac{M_{Mg}*3}{M_{3MgO.4SiO_2.H_2O}}*100$$
$$\frac{72.915}{379.26568}*100$$
Which is 19.23% by weight Magnesium in Talc.
According to Hoz
Post #2279
Talc constitutes 21%-30% of the Tnemec Proprietary Pigment.
And the Tnemec Proprietary Pigment constitutes 33.7% of the Pigment.
Talc is 19.23% Magnesium by weight, and the pigment is 21%-30% Talc by weight, therefore the Pigment must be (19.23%*21%) - (19.23%*30%) Magnesium by weight, or 4.04% - 5.77% Magnesium, by weight.
The Pigment component of the Primer used on the WTC steel is 33.7% by weight (or at least that's what Harrit assumes) Tnemec Proprietary Pigment, so the Pigment component of the primer must be (4.04%*33.7%) - (5.77%*33.7%) or 1.4% - 1.9% by weight Magnesium.
And that's as far as I'm willing to take it at this point, as I have yet to come across any information as to the ratio of Pigment:Vehicle (remember, the above is for the pigment only).
Incidentally, I seem to recall in one of Hoz's posts, him saying that Harrit in his response estimates that the paint contained up to 40% volatiles, but according to this information, it's more likely to be in the range of 24%-29% volatiles, meaning Harrit over estimates his compositions in the dired paint.
Is this something that you believe is missing from Harrit's article?
Yes, i've already outlined several points in this thread that detail what I consider to be failings of basic good science in Harrits paper. Personally, If I wa sin the editors position, I probably would have resigned as well.