A typically deep and meaningful input from you eram. Can't imagine how you could digest anything wearing that silly rocking helmet, but then I'm not a gamer pro!Nice hearty chunks of text. Hard to digest though.
A typically deep and meaningful input from you eram. Can't imagine how you could digest anything wearing that silly rocking helmet, but then I'm not a gamer pro!Nice hearty chunks of text. Hard to digest though.
Oh c'mon. I don't wear a silly helmet, and it's not related to gaming!A typically deep and meaningful input from you eram. Can't imagine how you could digest anything wearing that silly rocking helmet, but then I'm not a gamer pro!
I had to read this several times before I could understand what he was saying. I don't think I'm the only one.I can see that you might be saying that no one is interested in the new kind of clock, and that my purpose for bringing it up as if it related to how we could establish and maintain a fixed position relative to the observed redshift and CMB is not clear.
If I look at your posts from that perspective then my conclusion is that the members are not interested in the significance of how the redshift is information about a history of motion going away from all points in the observable universe, and the CMBR is information about a history of motion in the form of radiation coming toward all points in the observable universe.
My point in making that distinction, is that for the separation to be true, the outward motion clearly represents a finite length of time since some initial event (the big bang), but for the inward motion to be entirely connected to that same event is problematic. What is the explanation, within the standard cosmological model, for the source of the inward motion of the CMBR at all points in the observable universe?
Ah yes, sorry, I forgot. it relates to dubstep. But you are a gamer pro - no?Oh c'mon. I don't wear a silly helmet, and it's not related to gaming!
Not a particularly huge wall of text, and i did say preamble to eq'n (1), all of which I'm quite sure Markus is perfectly familiar with.What I'm trying to say is, when you include a huge wall of text, it's easy for both you and Markus to get confused and start arguing over something trivial.
Not at all. Unless you think a fundamental aspect of the very nature of gravitational field is 'just definitional'.Or arguing over a definition.
No I detest it, but argumentation is forced on me by others imo.Hence your argument will last longer than necessary. Unless you like arguing.
Learning curve!It's like trying to read through quantum_wave's text....I had to read this several times before I could understand what he was saying.
If you say so.No I detest it, but argumentation is forced on me by others imo.
Huge enough to get into a prolonged argument. Well, are you familiar with it too?Not a particularly huge wall of text, and i did say preamble to eq'n (1), all of which I'm quite sure Markus is perfectly familiar with.
They cover many genres, but a Daft Punk fan would clobber you for saying that.Ah yes, sorry, I forgot. it relates to dubstep. But you are a gamer pro - no?
Fundamentals are supposed to be simple, I don't know how you guys manage to blow it up.Not at all. Unless you think a fundamental aspect of the very nature of gravitational field is 'just definitional'.
Markus - you have been logging in several times each day since my #770 query, so what exactly is the problem in not extending the minimal courtesy of responding? Till now expected better of you than to (non)react with an evident snub. Whatever - have become used to that kind of thing here.
I find it confusing and strange that a schizophrenic response to 'gravity does/doesn't gravitate' abounds amongst GR trained folks
Well sorry for your bout of food poisoning and pardon me please for misinterpreting the situation which is highly unusual in timing and circumstance. Had no way of knowing that when 'Markus Hanke' shows up as on-line it really isn't Markus Hanke at times. But I think you should understand why I drew the conclusion I did, and it wasn't 'crap' to do so.Huh ?! How would you know whether or not I have been present here ? I never log out from any of the sites I am active on, so every time a member of my family opens the browser I will appear as “online” on all of them. As a matter of fact I have been bedridden with a bout of severe food poisoning, and have not been anywhere near my computer since last Saturday morning; so, frankly, your comment is way out of line, and quite ridiculous, especially the bit about an “evident snub”, considering I just saw your post this very minute. You may wish to think first before publicly posting this kind of crap !
Where on earth are you pulling this from? I don't get your drift here at all. Are you referring to gravitational waves or what? Because in static case it's bleeding obvious that absent the usual stress-energy tensor density there is zero Ricci curvature. Zero source density (of any kind) = zero Ricci curvature. As you know, say for exterior Schwarzschild metric there is only a non-zero Weyl (shear) curvature - Ricci flat. Now if the field were it's own source in GR this would be a nonsense - it should - must - act as a kind of 'atmosphere' having a non-zero source density 'out there' exterior to usual stress-energy tensor source, thus a non-zero Ricci curvature in vacuo. But in GR it doesn't! End of story surely. Tell me otherwise. But you are.Your very own example, that the Ricci tensor vanishes in empty space-time, illustrates this very well - we get a curved space-time even though the source term in the field equation ( the stress-energy tensor ) vanishes. How is that possible ? Precisely because gravity is self-interacting. If that weren’t so, how could we get a curved space-time even though the Ricci tensor and the stress tensor vanish ? What could be source of this, if not gravity itself ?
Well my understanding is one is left with a non-zero Weyl curvature - e.g. exterior SC solution above mentioned. Which is not flat in the Minkowski sense but is flat in the Ricci curvature sense.Mathematically, this happens because the Ricci tensor is a non-linear combination of the metric tensor and its derivatives; if it were linear, and the field was not self-interacting, then a vanishing Ricci tensor would automatically imply a flat space-time. Obviously, that isn't the case.
I didn't say or imply artificial addition, and that's not how it's put in that Mathpages article I linked to. How it's put there is that Einstein postulated that condition as a necessary one.Also, what do you mean by the "Ricci flat postulate" was built into GR ? It is a natural consequence of the trace-reversed field equations, and not an artificial addition of some kind.
Except they do. Or do want me to make verbatim quotes here? You surely cannot deny PeterDonis did say a definite NO in the classical GR case! And btw that first quote I gave back in #770 was from a Sascha Vongehr (Alpha Meme) of Science20.com (he also strongly disagrees with your position that conservation of energy holds in GR in general). If you like, I can provide a direct link to the exact passage where he makes that point re gravity not gravitating, just so you can be sure there was no taking things out of context. There wasn't. But look I'm not out to argue this matter, just arrive at the truth.Btw, none of the links you provided contradicts what I said in any way, shape or form.
Self-interacting then apparently is not synonymous with 'being it's own source'. Unless you mean as in GW's. But how is that different to saying an EM wave 'is it's own source'?No matter how you look at it, the gravitational field in GR is self-interacting; in fact it could not be any different, since we are dealing with rank-2 tensor fields here !
Because in static case it's bleeding obvious that absent the usual stress-energy tensor density there is zero Ricci curvature. Zero source density (of any kind) = zero Ricci curvature. As you know, say for exterior Schwarzschild metric there is only a non-zero Weyl (shear) curvature - Ricci flat. Now if the field were it's own source in GR this would be a nonsense - it should - must - act as a kind of 'atmosphere' having a non-zero source density 'out there' exterior to usual stress-energy tensor source, thus a non-zero Ricci curvature in vacuo. But in GR it doesn't! End of story surely. Tell me otherwise. But you are.
Well my understanding is one is left with a non-zero Weyl curvature - e.g. exterior SC solution above mentioned.
If you like, I can provide a direct link to the exact passage where he makes that point re gravity not gravitating
Self-interacting then apparently is not synonymous with 'being it's own source'.
But how is that different to saying an EM wave 'is it's own source'?
You surely cannot deny PeterDonis did say a definite NO in the classical GR case!
Markus, methinks above represents a more or less convergence of viewpoint on this, and here's where I'd like to leave it. Trust there are no hard feelings and hope you accept my explanation for unfortunate and misplaced judgement call I made earlier.No, it’s not, see above. Come to think of it, I might have carelessly used that expression once or twice - in that I was clearly wrong, and apologize. It is self-interacting, but not it’s own source. So long as it is stated this way, there is no confusion.
Markus, methinks above represents a more or less convergence of viewpoint on this, and here's where I'd like to leave it. Trust there are no hard feelings and hope you accept my explanation for unfortunate and misplaced judgement call I made earlier.
For trying to discuss that idea, Farsight was (hastily and unfairly?) lambasted by some of the "experts" here and elsewhere.
No, just busy. I haven't read this current discussion, but I did spot this:Guys, very interesting discussion (specifically the "self-interacting gravity field" side discussion between Q-reeus and Markus Hanke), and rare in that a consensus between you two was reached and the discussion ended in mutual understanding and respect. Very heartening for observer like me and everyone else interested in discussion rather than conflict for ego's sake! Thankyou both for that very good read/conversation on self-interaction of gravity field "free-space components" terms etc.
Edit/---By the way, I recall reading Farsight somewhere also maintained and explained that gravity was self-interacting as has just been concluded between you two. For trying to discuss that idea, Farsight was (hastily and unfairly?) lambasted by some of the "experts" here and elsewhere. I guess that Farsight will feel pretty much vindicated against his attackers on this particular idea when he reads/hears about your discussion and its conclusion here! Where is Farsight, anyway? I haven't seen him on the board for some time? Is he ill too?
No, just busy. II haven't read this current discussion, but I did spot this:
"And btw that first quote I gave back in #770 was from a Sascha Vongehr (Alpha Meme) of Science20.com (he also strongly disagrees with your position that conservation of energy holds in GR in general)."
I disagree with Markus about a fair few things, but can I say that I'm certain that conservation of energy holds in GR. I don't recall being lambasted by experts about that.
The question about energy conservation is a whole different beast again.
... There is no denying the fact that in GR gravity is "self-interacting", but it is definitely not "it's own source". ...
If something(say mass or as you say 'gravity in GR') does not interact with self(or its own source), then how it( GR gravity) becomes "self-interacting"?
You are mixing up terms - self-interaction of the field is not the same as the field being its own source. That is the main point. This is because all components of the metric tensor, which can be considered the "field" in GR, are mutually interdependent, unlike for example in Newtonian gravity.
You can also look at it from a quantum field theory point of view, which is perhaps simpler - (hypothetical) gravitons don't just interact with their sources, but also with each other, because they couple to rank-2 tensor fields.
Do you know, why perihelion precession happens? Due to attractive force or repulsive force(consider the Sun at the centre of the orbit)?
there is no such thing as repulsive force, you have been told this repeatedly, you need to stop trolling.
The discovery and attempts to find classical causes for the precession of the perihelion of the planet Mercury are well known.1 In the 19th century, the French astronomer Le Verrier found that the perihelion of Mercury advanced by 43 arc- seconds/100y, an amount which could not be accounted for in terms of the gravitational forces exerted on Mercury by the other known planets. Le Verrier assumed another planet, which he named Vulcan, existed between Mercury and the Sun. However, observations failed to establish that Vulcan existed. Another explanation put forth by astronomers was that Newton's law of gravitation was not correct but, if additional terms were added, these could account for the excess rate of turning of the orbit of Mercury. For example, it is known that if a repulsive force C/r3 is added to Newton's law it would provide a correct value for precession of the perihelion of planet Mercury.2 A different explanation is offered by Einstein's theory of gravitation which calls for an extra term A/r4 which, if added to Newton's law, gives the excess turning rate of 43 arcseconds/100y. Importantly, A was not adjusted to give this value. It emerged uniquely out of Einstein's theory. Thus, classical explanations, which could not be found since the 19th century were replaced by Einstein's theory in the 20th century.
These "interplanetary gravitational interactions" can be considered as "repulsive" from "the Sun" point of view.