You really need to learn to use the quote function so we can tell just who the heck you're talking to!!!
This post, as it is now, is worthless because there's NO way to tell who it's in response to. That's not too bright in anyone's book.:bugeye:
Why Is The Moon Not Spinning Then?
- Thread starter common_sense_seeker
- Start date
You really need to learn to use the quote function so we can tell just who the heck you're talking to!!!
This post, as it is now, is worthless because there's NO way to tell who it's in response to. That's not too bright in anyone's book.:bugeye:
Rabon, it's easy to see that you have no idea what you're babbling about. Every bit of your post is nothing but pure nonsense. Even a kid of 18 knows better.
DwayneD.L.Rabon
Registered Senior Member
Read only, your a proffessional dumb ass.
DwayneD.L.Rabon
DwayneD.L.Rabon
Haha.
You really need to learn to control yourself.
Who???????
Once again, by quoting nothing and addressing nothing, you are just talking to yourself alone. No one has any idea who else you might be talking to.:shrug:
Silly boy/girl/whatever.
Ophiolite
Valued Senior Member
Stranger,
Read-Only is right. Your last comment, for example. "You really need to learn to control yourself."
It follows a post from Steve100. Internet forum convention would strongly suggest your post is directed at Steve. However, it makes little sense to ask Steve to control himself. He seems perfectly in control.
It is more likely that you are talking to Dwayne. (He does need to control himself.) But how are we meant to know this? You could be talking to anyone, frankly.
Cheers
O.
Read-Only is right. Your last comment, for example. "You really need to learn to control yourself."
It follows a post from Steve100. Internet forum convention would strongly suggest your post is directed at Steve. However, it makes little sense to ask Steve to control himself. He seems perfectly in control.
It is more likely that you are talking to Dwayne. (He does need to control himself.) But how are we meant to know this? You could be talking to anyone, frankly.
Cheers
O.
#1 - that graphic has nothing in common with your earlier 3 graphics which all (more or less) had kept their same side pointing towards the center.
#2 - your 4th graphic, if viewed from a planet at the center of its orbit, would be tumbling around two axes. It thus would NOT be tidally locked ...UNLESS, there were other moons close by that were causing it to tumble and keeping it from becoming tidally locked.
How do your graphics relate to the issue of whether (or not) our own moon is still *rotating* around its polar axis?
If our moon is still rotating around its internal polar axis one (1) time per complete orbit as some here claim, then please do name the force that has (for at least 3 billion years) kept our moon rotating around its polar axis against the torque of tidally locking?
Other than the Earth and moon's mutual pull of gravity on each other (and to a lessor extent of the sun & Jupiter, etc), the only remaining force I see that's affecting the moon's motion would be the moon's own orbital motion around the Earth-moon barycenter, and the force of that orbital motion is not constant since the moon's orbital motion is speeding up as energy is transferred from the Earth through tidal braking.
Pretty graphics, though.
Ken
Ken your post 93has many errors, which I CORRECTED IN POST 96, but you have ignored that so I condense your post 93 to display only your errors directly related to the thread:
Did not I and the moon make one 360 degree turn about the polar axis?
I also watched the Foucault pendulum near me make one 360 degree turn during those 28 days. That you yourself CORRECTLY said was PROOF that the moon did turn on its polar axis. Are you contradicting yourself? Or just confused?
You also think the Earth’s gravity force on the moon is stronger than the sun’s gravity force on the moon is. It is so easy to show you are wrong here too, that I will:
If M & m be the masses for Sun and Earth and D & d be the distances of Sun and Earth from the moon. Thus, the ratio of Sun’s to Earth’s gravity on moon is:
{M/(D^2)} / {m/(d^2)} or (M/m) x (d/D)^2.
Now the mass ratio (M/m) = 1.3 x 10^6 and D = 150 x10^6 km. The moon to Earth separation, d, is 0.384 x10^6 km and I assume the moon is as far as it can be from the sun so D = 150.384 x 10^6.
Then (d/D)^2 = (0.00255)^2 or (2.55)^2 x10^-6 or 6.5 x 10^-6
Thus the Sun’s gravity is 1.30 x 6.50 = 8.45 times stronger force on the moon than the Earth’s gravity is. This is why the moon orbits the sun, not the Earth. All the Earth does is make the moon’s basically elliptical orbit about the sun have some small “wobble.”
How small is that “wobble”? Well that too is easy to answer: It is as 0.384 is to 150 or a ¼ of one percent variation in the moon to sun distance. So do graph it but for easy assume a circular orbit. When you draw a circle with 13 cycles of only ¼% variation in the radius you will see that AT ALL POINTS in the moon’s orbit it is ALWAYS turning towards the sun. The moon does NOT orbit the Earth it only very slightly crosses from one side of the Earth’s orbit to the other as it orbits the sun.
Summary: YOU HAVE BEEN 100% WRONG on everything stated directly related to the thread and even about the cause of the tides. You did NOT even correctly note the fact that both the Earth and moon only APPEAR* to rotate about their barycenter, which only wobbles from its elliptical orbit very little (due mainly to the perturbations of Jupiter).
--------------------------
*Appear” as neither is rotating about the barycenter, but if you were traveling with it in orbit about the sun it does APPEAR to be what they are doing; however, from ANY point fixed in space, both Earth and moon are in slightly (1/4 of a percent at most perturbed) elliptical orbits about the sun. They are NOT rotating or orbiting about each other nor about the barycenter. It only APPEARS THAT WAY. Also in case you are also confused about the sun: The sun is not rotating about the Earth either, but it too APPEARS to be rotating about the Earth from an Earth based perspective. Most educated persons now know that appearance is false. - The sun does not orbit the Earth; it only Appears to orbit the Earth. Unfortunately, most people still think the moon DOES orbit the Earth because it appears to orbit the Earth. Things are not always what they appear to be. To know the truth you need to do the calculations / analysis (as done above) not just assume the common POV and appearance are correct.
Finnally: As the moon goes around the sun in an eliptical orbit with 1/4 percent perturbation by the Earth of that orbit it is spinning about its polar axis approximately 13 times in each complete orbit of the sun. From Mars or some more distant place the telescope-aidded eye could ONLY observe the polar spin of the moon, not the tiny, slow 1/4 % wobble.
If I sit on North pole of the moon for 28 days without moving initially facing the sun, two weeks later the sun is at my back and 28 days later the sun is again at my face again.
Did not I and the moon make one 360 degree turn about the polar axis?
I also watched the Foucault pendulum near me make one 360 degree turn during those 28 days. That you yourself CORRECTLY said was PROOF that the moon did turn on its polar axis. Are you contradicting yourself? Or just confused?
You also think the Earth’s gravity force on the moon is stronger than the sun’s gravity force on the moon is. It is so easy to show you are wrong here too, that I will:
If M & m be the masses for Sun and Earth and D & d be the distances of Sun and Earth from the moon. Thus, the ratio of Sun’s to Earth’s gravity on moon is:
{M/(D^2)} / {m/(d^2)} or (M/m) x (d/D)^2.
Now the mass ratio (M/m) = 1.3 x 10^6 and D = 150 x10^6 km. The moon to Earth separation, d, is 0.384 x10^6 km and I assume the moon is as far as it can be from the sun so D = 150.384 x 10^6.
Then (d/D)^2 = (0.00255)^2 or (2.55)^2 x10^-6 or 6.5 x 10^-6
Thus the Sun’s gravity is 1.30 x 6.50 = 8.45 times stronger force on the moon than the Earth’s gravity is. This is why the moon orbits the sun, not the Earth. All the Earth does is make the moon’s basically elliptical orbit about the sun have some small “wobble.”
How small is that “wobble”? Well that too is easy to answer: It is as 0.384 is to 150 or a ¼ of one percent variation in the moon to sun distance. So do graph it but for easy assume a circular orbit. When you draw a circle with 13 cycles of only ¼% variation in the radius you will see that AT ALL POINTS in the moon’s orbit it is ALWAYS turning towards the sun. The moon does NOT orbit the Earth it only very slightly crosses from one side of the Earth’s orbit to the other as it orbits the sun.
Summary: YOU HAVE BEEN 100% WRONG on everything stated directly related to the thread and even about the cause of the tides. You did NOT even correctly note the fact that both the Earth and moon only APPEAR* to rotate about their barycenter, which only wobbles from its elliptical orbit very little (due mainly to the perturbations of Jupiter).
--------------------------
*Appear” as neither is rotating about the barycenter, but if you were traveling with it in orbit about the sun it does APPEAR to be what they are doing; however, from ANY point fixed in space, both Earth and moon are in slightly (1/4 of a percent at most perturbed) elliptical orbits about the sun. They are NOT rotating or orbiting about each other nor about the barycenter. It only APPEARS THAT WAY. Also in case you are also confused about the sun: The sun is not rotating about the Earth either, but it too APPEARS to be rotating about the Earth from an Earth based perspective. Most educated persons now know that appearance is false. - The sun does not orbit the Earth; it only Appears to orbit the Earth. Unfortunately, most people still think the moon DOES orbit the Earth because it appears to orbit the Earth. Things are not always what they appear to be. To know the truth you need to do the calculations / analysis (as done above) not just assume the common POV and appearance are correct.
Finnally: As the moon goes around the sun in an eliptical orbit with 1/4 percent perturbation by the Earth of that orbit it is spinning about its polar axis approximately 13 times in each complete orbit of the sun. From Mars or some more distant place the telescope-aidded eye could ONLY observe the polar spin of the moon, not the tiny, slow 1/4 % wobble.
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I will help you by drawing a verbal picture. (I cannot post any picture for reasons not known):
Imagine an eight inch diameter perfect circle drawn on an 8.5x11 inch piece of paper with a pencil that makes a mark 0.01 inches wide. (That is about the width of: | on my computer screen.)
Now you have a "circularized" scale model of the moon's orbit going around the sun. I.e. the 1/4 of one percent "wobbles" do not go outside of the 0.01 inch wide line, but are contained entirely inside its 0.01 inch width. This is why it is correct to state the moon is in orbit about the sun, not the Earth.
It is also why it is correct to state that it spins on its polar axis as it does so. The only motion noticeable to a telescope aided eye from most everywhere in the universe is this polar spin, not these tiny wobbles. To even see them with a telescope, your position if represented on the scale drawing would need to be close to the point on the circle of the scale drawing where the Earth is.
Also I worked out for you in my last post the sun's gravity on the moon is 8.45 times larger than that of the Earth. You seem to be a very stubborn fool to ignore all the facts that I and others have explained to you and persist in beliefs that contradict these facts which are only based on appearances when viewed from the Earth.
Based on the appearances you equally well can believe the sun orbits the Earth also as it too does gives the appearance of doing so. You have only the appearance to support your POV and none of the facts. Facts you have all wrong, including the believe that gravity, not the gravity gradient, causes the tides.
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If the Earth just disappeared, would the moon continue to rotate about its axis, instantly start rotating about its axis, or remain not rotating about its axis?
If you think it's the second option, what causes the moon's rotational acceleration?
If you think it's the third option, you need to get on the right stick, never mind the right end.
If you think it's the second option, what causes the moon's rotational acceleration?
If you think it's the third option, you need to get on the right stick, never mind the right end.
Ophiolite
Valued Senior Member
You are wrong. Completely and utterly wrong. You are more wrong than a hirsute Latvian accordionist wearing embroidered silk bloomers in a remake of The Third Man. If they gave Oscar's for wrongness you would have a clean sweep. Generations from now young children will be shown these posts in order to understand how wrong, wrong can be. Your wrongness is of such magnitude that it may even stop the LHC from operating correctly. W-R-O-N-G. Wrong!
Did that help.
I tried to be polite by using a common colloquial expression. Suggesting you had the wrong end of the stick allows the possibility that you just have the wrong perspective on things. However, as Steve100 has now touched on, it looks like you may not even have the right stick.
What I don't understand, returning to my original comments, is how someone so apparently smart could be so persistently committed to remaining wrong.
Here's some unsolicited advice. When you are in a hole that you do not wish to be in the first thing to do is to stop digging. We are all rooting for you, but only you can make the transition.
DwayneD.L.Rabon
Registered Senior Member
Well, heres a little in addition..... The mass for the moon according to Nasa is 1/87th the mass of the earth, which cleary would define that the moon, exerts less force on the earth than the earths magentic feild.
Also if you are going to consider the effect of the sun on the moon then you should also consider the effect of the sun on the earth. Which would result in finding out that the earth should not spin either.
Under such anaolgy the moon would not rotate it would be locked as the earth should be locked in orbit with the sun.
The earth is located just out side of a region where things stop rotating, and begin to become more like the motion of venus and mercury.
and so the moon is just small enough that if it broke away from the earth it would begin to rotate.
And so also the moon is in a normal orbit around the earth.
DwayneD.L.Rabon
Also if you are going to consider the effect of the sun on the moon then you should also consider the effect of the sun on the earth. Which would result in finding out that the earth should not spin either.
Under such anaolgy the moon would not rotate it would be locked as the earth should be locked in orbit with the sun.
The earth is located just out side of a region where things stop rotating, and begin to become more like the motion of venus and mercury.
and so the moon is just small enough that if it broke away from the earth it would begin to rotate.
And so also the moon is in a normal orbit around the earth.
DwayneD.L.Rabon
Post 93 in part.
I guess Ken is just a very slow learner (or perhaps a masochist?).
Since the moon is revolving around an exterior axis (the barycenter within the Earth), if the Earth were magically removed, then the moon would switch over to revolving around the barycenter of the moon & sun's combined common-mass, a point near the sun's center.
Because the moon had no actual polar rotation prior to being released by the Earth's gravity, at most the moon would wobble slightly until tidal-braking by the sun stabilized it.
The proof that the moon's circular revolution around the Earth is not the same thing as polar rotation is easy. Have you never seen an athlete's hammer toss?
Prior to releasing the hammer (a round metal ball on a chain), the hammer-thrower's ball is whizzing about him (or her) at such blazing speed the ball is just a blur at a high rate of circular motion, but upon release, the ball at most does a slow tumble and does NOT spin in the air at all.
Any minor tumbling of the ball upon release is caused by minor cartwheeling prior to the release, thus any minor tumbling motion caused by cartwheeling (around its own mass) the ball would retain after its release.
Here's a video clip - there are several athletes tossing in this clip and only the last athlete's toss can be seen clearly while in the air, the blond Russian gal's toss. At the end of the clip they replay her toss in slow motion making it easy to see the ball's lack of rotation while in the air (add the http & www):
youtube.com/watch?v=Jpbgg2TRCuw
Don't believe the video? Then go to the park and fling a couple balls for yourself.
Ken
DwayneD.L.Rabon
Registered Senior Member
I would have to agree,
if the moon were suddenly released from earth the moon would wobble around a bit first the start in to a rotation later.
However in the release the moon could make a tumble into a orbit region where it would not gain a rotation, given that the earth is just a few million miles out side of the no rotation region of our solar system.
DwayneD.L.Rabon
if the moon were suddenly released from earth the moon would wobble around a bit first the start in to a rotation later.
However in the release the moon could make a tumble into a orbit region where it would not gain a rotation, given that the earth is just a few million miles out side of the no rotation region of our solar system.
DwayneD.L.Rabon