Pete said:If each clock is stopped after one hour in their own frame, then of course they'll read 3600 seconds. Duh!
Mac, you're reading far too much into this thing you've made up and labelled "reciprocity". I think it is part of your misunderstanding of relativity.
Please, read through my last long post. I really think it is relevant, and may help to clear up your misunderstandings, or mine, as the case may be.
James R said:Good thinking, Pete.
MacM:
Another straight question about reference frames.
Is it possible for two objects with different velocities to exist in the same reference frame?
Yes or no?
James R said:MacM:
In your X=Y example, there is no "linear relationship" between X and Y. In your example, both X and Y are constant. There is no variation of Y with X.
Therefore, it is irrelevant.
Without a reference frame, your question is unanswerable.
Who measures the 1 hour?
Pete said:Regarding "reciprocity"...
I think that MacM believes that the postulates of Relativity imply that two objects always have the same velocity as each other.
MacM thinks that according to SR, if two objects have a relative velocity X, then X is the "real" velocity of each object. This leads to Mac wanting to work in two reference frames at once.
Mac think that it is against the postulates of SR to work in a reference frame in which the one object is stationary, and the second has velocity X.
This is what I think he means by "reciprocity".
He invented this notion to justify his fallacious [post=683805]clock synchronization procedure[/post],
as addressed [post=684082]earlier in the thread[/post]. Followups: [post=684209]MacM[/post], [post=684241]Pete[/post], [post=684248]MacM[/post], [post=684253]Pete[/post], [post=684256]MacM[/post]. I got distracted on other issues at that point... perhaps I should return to it now.
Mac, point 6 in your synchronization procedure requires that the two clocks are moving at equal speeds in opposite directions.
Do you maintain that this is dictated by relativity, and is this what you mean by "reciprocity"?
Me: Is it possible for two objects with different velocities to exist in the same reference frame?
You: I would say no.
What is the game here to keep asking questions until I screw up and then say"Ah Hah, see you don't understand"?
You cannot claim A<---0.9c----->B is not 0.9c for each regardless of any frame assignement of either clock such as being in a rest frame.
I'm sorry you couldn't follow the clearly spelled out refutation ([post=684082]link[/post]).MacM said:For which no VALID refutation has ever been given. A lot of wishy washy irrelevant efforts or confuse or divert the issue was but not valid refutation.
Because that view is wrong.MacM said:Duh! indeed. You mean after these many months you finally agree that time dialtion is perception and not physical reality. That is all I have ever said. You have belittled that view. Why?
You didn't ask... but if you insist:MacM said:Note: You haven't addressed the fact that each clock "sees" the other clock as having an equally different time.
Crap.I am afraid not. It (Reciprocity - Pete) is inherent in Relativity otherwise it is not relative.
Please don't make me impugn your intelligence again.MacM said:What about "Address the reciprocity issue do you not understand".
James R said:MacM:
Game over.
You're answers are inconsistent with your own definition of "reference frame".
Conclusion:
Either
A. You don't believe your own definition of what a reference frame is.
OR
B. You don't actually understand the concept of a reference frame.
OR
C. You're so muddle-headed, you don't think rationally.
OR
D. Some combination of A,B and C.
Since we have established that you don't have a clue about reference frames, or logical thinking, or both, and since relativity is all about reference frames, there's really no point going on, is there?
You can't get to first base in a discussion of relativity.
Your crazy, mixed up, flip-flopping, inconsistent notions about reference frames making any discussion of substantive issues a complete waste of time. All conclusions you draw are inherently and fundamentally flawed at the most basic level, except for the odd occasion where you happen to make a correct statement by chance alone.
James R said:
Pete said:Can you explain what you mean?
Pete said:I'm sorry you couldn't follow the clearly spelled out refutation ([post=684082]link[/post]).
It shows that your synchronization procedure work only for the reference frame in which the two clocks have equal and opposite velocities.
You rebuttal to that post was to suggest that relativity dictates that the two clocks do indeed have equal and opposite velocities and to avoid the question of reference frame.
Pete said:Because that view is wrong.
Your leap from:
"If each clock is stopped after one hour in their own frame, then of course they'll read 3600 seconds."
to:
"time dilation is perception and not physical reality"
is sadly misguided, and once again demonstrates your misunderstanding of SR.
You didn't ask... but if you insist:
Each clock rightly maintains that (in their own frame), they stopped before the other clock.
Crap.
Prove it.
Please don't make me impugn your intelligence again.
Do you really not see the relevance? Or are you simply unable to work through the logic?
It's really not that difficult.
With a constant relative velocity of 0.9c between clocks after one hour according to their clock do you agree that they will jpercieve the other clock as reading 1,569.2 seconds? Yes or No.
Pardon me but bullshit. I knew you had no answer for the reciprocity issue. You have just proven it.
James R said:Your question is meaningless unless you specify a reference frame.
James R said:Bait and switch. You have no answer to the point raised, so you attempt to change the topic.
Typical.
Each clock sees itself at rest so the calculation is based on the viewing clock as being v = 0 and the other clock being 0.9c in relative velocity.
I note once more that you attempt to divert the issue and fail to address reciprocity and its implications for Relativity.