The Relativity of Simultaneity

Which in you gibberish way is exactly what I said. He thinks that light will be measured as c from a fixed point whatever that is, and it will have a different relative velocity if you are moving relative to that fixed point.



Nope. Unless you are saying that he no longer thinks that 2 observers moving at different speeds will measure a different value for the relative speed of light. Is that what you are saying?



No no no. I don't care what Einstein said at this point I am simply stating the fact that the speed of light (relative to the observer if you like) is always measure at c in a vacuum. MD says it should not always be measured the same, because we are moving in different directions as the year passes - well the speed of light doesn't vary, so he loses, reality wins.




No knucklehead, I am saying that it is different from what is actually measured. This has been pointed out to you guys about 20 time and it still cannot seem to penetrate your skulls!



Measurement. Actual measurements. Do you know what a measurement is? It is not an opinion.



Yes and measurements show that it is independent of the motion of the observer.
Excuse me, Origin. I didn't know you meant actual measurements. Thanks again for providing that link to actual measurements that are accepted by the scientific community as proof of the second postulate. I'll study if for awhile so it can seep into my pea brain. Wait, you did provide a link didn't you?
 
Oh really? According to MD's postulate there is only one way that we can measure the relative speed of light as c, and that is if we are at absolute rest.
At rest relative to the point of emission. If you measure the speed of light at c, you can determine the point of emission or don't you agree?
That is why he dodges the question about the speed of light. You didn't understand that so you acknowledged the obvious, which is that the speed of light is measured at c. MD won't admit that, he can't, he knows that will blowup his concept.

Clearly we are on a spining planet, orbiting the sun, circling the galaxy and moving towards the vega supercluster. If we are at absolute rest then we are the only place in the universe at rest and are very special. Check with MD he will let you know that you must dodge the question about the measured speed of light.
OK, I'll check.

MD. Is Origin right? Has he provided a link to the experiments that are accepted by the scientific community that prove Einstein's second postulate is right?
 
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MD. Is Origin right? Has he provided a link to the experiments that are accepted by the scientific community that prove Einstein's second postulate is right?

Origin has no measurements using my method.

For one, Einstein uses a different sync method. Another thing which einstein makes a fatal mistake is that he measures the round trip light travel time in the frame, and divides that time in two to come up with the length. That is absurd!!! Obviously the length is wrong if the frame is in motion, as the times could be"

(2+4)/2=3
(3+3)/2=3
(4+2)/2=3

As you can see, since he uses round trip light travel time and divides by two, he gets the length wrong for anything other than a zero velocity (3+3) in the example.

His method has so many mistakes it's laughable!

He assumes the frame to be at rest ("at rest" in reference to what he has no clue).

He uses round trip light travel time and divides by 2 and hides the different one-way times.

He assumes that it always takes .5 seconds for light to travel the distance of .5 light seconds in every frame, regardless of the velocity.

He disregards the fact that light is emitted at a point in space, and light travels away from that point equally in all directions.

He disregards the fact that after the source emits light it could travel away from the center of the light sphere.

He just plain makes a big hairy mess of everything! His method is a joke!!!
 
Origin has no measurements using my method.

For one, Einstein uses a different sync method. Another thing which Einstein makes a fatal mistake is that he measures the round trip light travel time in the frame, and divides that time in two to come up with the length. That is absurd!!! Obviously the length is wrong if the frame is in motion, as the times could be"

(2+4)/2=3
(3+3)/2=3
(4+2)/2=3

As you can see, since he uses round trip light travel time and divides by two, he gets the length wrong for anything other than a zero velocity (3+3) in the example.

His method has so many mistakes it's laughable!

He assumes the frame to be at rest ("at rest" in reference to what he has no clue).

He uses round trip light travel time and divides by 2 and hides the different one-way times.

He assumes that it always takes .5 seconds for light to travel the distance of .5 light seconds in every frame, regardless of the velocity.

He disregards the fact that light is emitted at a point in space, and light travels away from that point equally in all directions.

He disregards the fact that after the source emits light it could travel away from the center of the light sphere.

He just plain makes a big hairy mess of everything! His method is a joke!!!
Thanks. I don't feel the reverence but I don't see Origin's link to the evidence that proves E's 2nd either. Maybe he will provide it tomorrow :)?
 
Motor Diddly said:
He assumes the frame to be at rest ("at rest" in reference to what he has no clue).
What you're saying here is you have no clue what a rest frame is.
He disregards the fact that light is emitted at a point in space, and light travels away from that point equally in all directions.
No, he doesn't. You need to make things up to support your idea that you're better at thinking than Einstein was.
He disregards the fact that after the source emits light it could travel away from the center of the light sphere.
No he doesn't. You disregard the fact that any coordinates in spacetime are chosen completely arbitrarily.
But then, you may not know what "arbitrary" means, either.
He just plain makes a big hairy mess of everything! His method is a joke!!!
Diddly diddly. Diddly diddly dee . . .
 
What you're saying here is you have no clue what a rest frame is.

Is it a train when the tracks are moving away from the train? Is it the center of a light sphere moving away from a cube?

You are in a cube. That is your frame. You assume it to be at rest. What do you base your assumption of "at rest" on? What is your concept of the cube being "at rest?" "At rest" compared to what??????

Start with the basics before you start pretending again. :rolleyes:

...and dare you say the cube's velocity is zero, because I am also in the cube, and I claim the cube's velocity is 437,874,687,345,867 m/s. Are we both correct?
 
If you are at rest on the surface of the earth (let's say you're sitting in front of a computer), what do you base your assumption of "at rest" on?

What is your concept of being at rest? At rest compared to what?

Diddly dee.
 
If you are at rest on the surface of the earth (let's say you're sitting in front of a computer), what do you base your assumption of "at rest" on?

What is your concept of being at rest? At rest compared to what?

Diddly dee.

Is that how you try to wiggle out of a question, by asking a question in return?

You are in a cube. You assume the cube to be at rest. "At rest" compared to what?
 
If you're in a cube, how do you know it's a cube? Maybe it's really a sphere?
That aside, if the cube is at rest, it's at rest relative to another frame of reference.

If you're inside the cube, how do you know if you're at rest? If you were walking or running around, would you know if you're at rest, relative to this cube?

You aren't perhaps Irish, are you?
 
Lost 1, this is lost 3, are you lost 2? Over.

Lost 1, this is lost 3, are you in motion? Lost 3 this is lost 1, no, I'm at rest.

Lost 1 this is lost 3, I'm at rest too.

Lost 1 this is lost 3, it seems that all ships are at rest at this time, I've contacted every one of them (3,465 ships) and they all claim to be at rest.

What a joke!!! :rolleyes:
 
That aside, if the cube is at rest, it's at rest relative to another frame of reference.

What frame of reference is at rest relative to, and why do you assume that your velocity is zero and the other frame is the frame in motion?

You just make stuff up? You just make up a velocity of 0 m/s and claim that to be true? Why not claim to have a velocity of 564,657,897,989,234,543,621,456,768 m/s????
 
MD said:
What frame of reference is at rest relative to, and why do you assume that your velocity is zero and the other frame is the frame in motion?
You "assume" the cube is at rest. To find a proper rest frame you need coordinates outside the cube, and you need to show the distance between the cube and the external frame does NOT change.

That is how a rest frame is defined, diddly dee!
Now if the distance changes between the two frames, which one is in motion, the cube or the external coordinates?
 
You "assume" the cube is at rest. To find a proper rest frame you need coordinates outside the cube, and you need to show the distance between the cube and the external frame does NOT change.

No you don't ASSUME anything! You do not need coordinates outside the frame to know the velocity of the frame. You originate a light sphere at the center of the cube, and you check the times on the receivers to see how much time it took the light to reach each receiver. From that you KNOW (not assume) the velocity of the frame!



That is how a rest frame is defined, diddly dee!
Now if the distance changes between the two frames, which one is in motion, the cube or the external coordinates?

If the times on the receivers are not the same, the cube is in motion. There is no other object to make your false claims about. The cube's motion is relative to the point in space the light sphere was originated, period!
 
MD said:
No you don't ASSUME anything!
MD said:
You are in a cube. You assume the cube to be at rest.
Oops.

MD said:
You originate a light sphere at the center of the cube, and you check the times on the receivers to see how much time it took the light to reach each receiver. From that you KNOW (not assume) the velocity of the frame!
Aren't you ASSUMING that you can 1) find the centre of the cube and emit light from that point, and 2) accurately measure the time it takes to get to a receiver? Wouldn't the cube's dimensions need to be "at rest" so you can do all that?

Aren't you assuming the cube stays at constant volume and shape, while you do the measurements?

You ARE Irish, aren't you?
 
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quantum wave:

James R, I must be the only one that can't see your diagram. Am I just missing it or did you forget to add the link?

This is the URL. Paste it into your browser. Can you see it now?

http://www.sciforums.com/picture.php?albumid=151&pictureid=892


Motor Daddy:

Are you ignoring my posts now? Too hard for you?

You are in a cube. You assume the cube to be at rest. "At rest" compared to what?

All objects are at rest in their own rest frame. That's what "rest frame" means.

If you want it to be at rest relative to something else other than the cube itself, then you need to introduce another object of some kind. For example, imagine an observer (a person) somewhere inside the cube who is not moving relative to the walls of the cube. Then, the cube is at rest relative to that observer.
 
Motor Daddy:

I have re-drawn my diagram to include a picture showing how things would look in the Motor Daddy universe in the frame of the train/box.

attachment.php


Notice that in the Motor Daddy universe the light spreads out in a sphere in "space" around the point of emission of the light. In the frame of the box, that point in "space" moves backwards with respect to the box.

Compare the Einstein train/box frame, in which the light sphere spreads out from the source at the centre of the box at an equal speed in all directions. This is in accordance with Einstein's 2nd posulate.
 
Motor Daddy:

I have re-drawn my diagram to include a picture showing how things would look in the Motor Daddy universe in the frame of the train/box.

attachment.php


Notice that in the Motor Daddy universe the light spreads out in a sphere in "space" around the point of emission of the light. In the frame of the box, that point in "space" moves backwards with respect to the box.

Compare the Einstein train/box frame, in which the light sphere spreads out from the source at the centre of the box at an equal speed in all directions. This is in accordance with Einstein's 2nd postulate.
I see the redrawn diagram in post #1137. Let me test my understanding. This is a depiction of a single flash of light emitted from the center of the train and the light flash is observed by a passenger on the train and by an observer on the embankment. The left hand column and the center column are two frames of reference according to SR. One frame is from the embankment, and the other is inside the train. You have drawn three time lapse pictures of the light sphere expanding for each of the two Einstein frames in accordance with the postulates of SR.

Einstein’s Embankment Frame
On the left we have the three time lapse pictures of the light sphere expanding from the instant of the event. The first time lapse picture shows the light sphere as a circle with the point of emission as a point in the center of the light sphere, and the rectangle represents the train position as it passes the observer. I think you have shown the train length contracted :). The first frame is just an instant after the light flash and the radius of the light sphere is small and hasn’t reached the sides of the train and hasn’t reached the observer yet.

On the left, the second and third pictures show the train rectangle passing the observer and the light sphere continuing to expanding. I am assuming that the third time lapse picture which shows the light flash reaching the side of the train is also the point in time when the observer on the embankment sees the flash. It is as if the observer on the embankment has his nose right up to the side of the passing train. Is that right or close enough?

There is a time delay from the instant of the flash until the observer on the embankment sees it. To clarify, I think you are depicting a time delay from the perspective of the observer on the embankment so he sees the flash when the light sphere expands out to him at c from his frame as if his nose was at the side of the train.

Einstein’s Train Frame
The Einstein train frame, the middle set of time lapse pictures is from the train frame. The three pictures show the light sphere expanding within the train in accordance with Einstein’s second postulate:
Special Relativity
2. Second postulate (invariance of c)
As measured in any inertial frame of reference, light is always propagated in empty space with a definite velocity c that is independent of the state of motion of the emitting body.

The light sphere expanding in the train frame moves with the train according to the perspective of the observer on the train and the observer on the train sees the light sphere expanding relative to the inside of the train car. If he is sitting at the middle of the train in a window seat with his nose up to the window he sees the light on a time delay as the light sphere expands from the middle of the train car to his perspective at the side window. He sees the embankment moving past the windows.

Comparison between the two Einstein frames:
From the embankment the light sphere expands from its point of emission toward the observer on the embankment who would testify that he saw the flash just before the train has passed but after the center of the train has passed. He probably knows that there was a time delay between the flash and the time the light sphere from the flash reached him, but when the sphere reached him, as shown in the third time lapse picture in the left hand column, the train was almost past him when he saw the light. The nose of the passenger sitting by the window had already passed the observer on the embankment, right.

From inside the train the light sphere expands from its point of emission toward the sides of the train car. When the passenger sitting with his nose to the window sees the light flash as the light sphere expands to reach him he would testify that the observer on the embankment who had his nose right up to the train had already passed outside his window.

In other words, the light sphere moved in accordance with SR in each frame and the description of the light sphere and the physical location of the observers implies that there was a separate light sphere in each frame.

MD’s view from the moving box.
MD from his moving box which we can call the train car for all intents and purposes initiates a light flash from the center of the box. According to MD’s postulate:

Light propagates at c from the absolute point in space where it is propagated.

Thus from inside MD’s box the light sphere expands as the box moves away from the point of emission. The light reaches an observer sitting at the side and toward the rear of the box at the same time that it reaches an observer outside the box who has his nose right up to the box. They both see the same light sphere and would testify that they also saw the nose of the other observer pass at the same time as the light reached them.

Have I got a grasp of how the two different postulates would change the description of the observations from inside and outside the box, i.e. the train?
 
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Motor Daddy:

I have re-drawn my diagram to include a picture showing how things would look in the Motor Daddy universe in the frame of the train/box.

attachment.php


Notice that in the Motor Daddy universe the light spreads out in a sphere in "space" around the point of emission of the light. In the frame of the box, that point in "space" moves backwards with respect to the box.

Compare the Einstein train/box frame, in which the light sphere spreads out from the source at the centre of the box at an equal speed in all directions. This is in accordance with Einstein's 2nd posulate.

Let's discuss one aspect of the diagrams at a time, so that we can identify each problem separately.

In your diagram on the left, Einstein's embankment frame, you show that the embankment observer thinks light traveled .5 seconds to travel from the source at the midpoint of the train to the receiver attached to the side of the train, which is .5 light seconds from the source.

James, that is incorrect. The embankment observer will see that the receivers on the sides of the train have moved to the right in the diagram, as the receivers on the sides of the train are affixed to the train, and the train has traveled to the right in your diagram. So, in the bottom pic of your left diagram, the light has not yet reached the side receivers at the midpoint of the length of the sides of the train. In other words, in Einstein's embankment frame, the light can't possibly reach the side receivers in .5 seconds, because light has to travel a greater distance than .5 light seconds to reach them. The radius lines of the light sphere from the center of the sphere to the point the receivers are attached at the midpoint of the length of the train will be at an angle to the right, which means the radius lines are longer than .5 light seconds in length.

Please explain that before we continue.

I've attached a pic to show the distance the light has to travel to reach the side receivers, of which the light has clearly not reached yet. Also note, that if the light sphere needs more time to expand to reach the side receiver, the train is also traveling to the right, so the time is even greater, as the angle increases. The light sphere will grow outside the train's front before the light reaches the sides.

attachment.php
 
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Origin has no measurements using my method.

For one, Einstein uses a different sync method. Another thing which einstein makes a fatal mistake is that he measures the round trip light travel time in the frame, and divides that time in two to come up with the length. That is absurd!!! Obviously the length is wrong if the frame is in motion, as the times could be"

(2+4)/2=3
(3+3)/2=3
(4+2)/2=3

As you can see, since he uses round trip light travel time and divides by two, he gets the length wrong for anything other than a zero velocity (3+3) in the example.

His method has so many mistakes it's laughable!

He assumes the frame to be at rest ("at rest" in reference to what he has no clue).

He uses round trip light travel time and divides by 2 and hides the different one-way times.

He assumes that it always takes .5 seconds for light to travel the distance of .5 light seconds in every frame, regardless of the velocity.

He disregards the fact that light is emitted at a point in space, and light travels away from that point equally in all directions.

He disregards the fact that after the source emits light it could travel away from the center of the light sphere.

He just plain makes a big hairy mess of everything! His method is a joke!!!

See what I mean QW? You have to get on board with denying that the speed of light is measured properly. Of course that makes one wonder why in the world MD would use the accepted speed of light in his discussions if he thinks that we don't measure it properly. Curious, no?

I noticed that you don't like how Einstein measured the speed of light. Since Einstein was not involved in actually measuring the speed of light I guess you are just spinning some sort of crap to help your denial.

QW you really need links? It is really simple, qoogle 'speed of light' and all of the sites will have the speed of light as c, and they will note that it is independent of motion. If you want to know how the speed of light is measured google 'how is the speed of light measured'.

I know I am wasting my time because you guys are convinced that you have figured out something that proves you are smarter than Einstein (and Hawking, Feynman, ect.). The reality is that for the people that have actually studied this stuff you sound a bit like a 4 year old child confidently explaining how a computer works.

You guys are embarrassing.
 
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