msbiljanica
Registered Senior Member
Presupposition-Part number (the number of gaps) negates the second number(gap number)
-one of then must be gaps numbers, other parts who have contact where is deleted together
Process:
P1- 0=¤3(1)2(1)2¤n-(.0)¤2(2)2¤=1
2
P2- 1 =¤3(1)2(1)2¤n-(.1)¤2(2)2¤=1
¤1(6)2¤
P3- ¤1(2)1¤ =¤3(1)2(1)2¤n-(.2)¤2(2)2¤=2
¤2(6)1¤
P4- 1 =¤3(1)2(1)2¤n-(.3)¤2(2)2¤=1
3
P5- 0 =¤3(1)2(1)2¤n-(.4)¤2(2)2¤=1
¤3(6)1¤
P6- 1 =¤3(1)2(1)2¤n-(.5)¤2(2)2¤=2
¤3(1)1(4)2¤
P7- 1 =¤3(1)2(1)2¤n-(.6)¤2(2)2¤=1
¤3(1)2(4)2¤
P8- 0 =¤3(1)2(1)2¤n-(.7)¤2(2)2¤=0
¤3(1)2(5)2¤
P9- 0 =¤3(1)2(1)2¤n-(.8)¤2(2)2¤=0
¤3(1)2(1)1(1)1(2)2¤
P10- 0 =¤3(1)2(1)2¤n-(.9)¤2(2)2¤=0
¤3(1)2(1)4(2)2¤
--images--
General form
negates 1 =an-(.c)b=negates 2
suptraction
or
negates 1 =an-(.c)b
negates 2
suptraction
[S47]-negates subtraction
CM-[S47] -dot no know
________
images are in pdf (Download pdf)
PDF - https://docs.google.com/open?id=0B3WUvmmPIWZ4MmpzME5YNF9UbXF3eFJES1dsNkZPUQ
-one of then must be gaps numbers, other parts who have contact where is deleted together
Process:
P1- 0=¤3(1)2(1)2¤n-(.0)¤2(2)2¤=1
2
P2- 1 =¤3(1)2(1)2¤n-(.1)¤2(2)2¤=1
¤1(6)2¤
P3- ¤1(2)1¤ =¤3(1)2(1)2¤n-(.2)¤2(2)2¤=2
¤2(6)1¤
P4- 1 =¤3(1)2(1)2¤n-(.3)¤2(2)2¤=1
3
P5- 0 =¤3(1)2(1)2¤n-(.4)¤2(2)2¤=1
¤3(6)1¤
P6- 1 =¤3(1)2(1)2¤n-(.5)¤2(2)2¤=2
¤3(1)1(4)2¤
P7- 1 =¤3(1)2(1)2¤n-(.6)¤2(2)2¤=1
¤3(1)2(4)2¤
P8- 0 =¤3(1)2(1)2¤n-(.7)¤2(2)2¤=0
¤3(1)2(5)2¤
P9- 0 =¤3(1)2(1)2¤n-(.8)¤2(2)2¤=0
¤3(1)2(1)1(1)1(2)2¤
P10- 0 =¤3(1)2(1)2¤n-(.9)¤2(2)2¤=0
¤3(1)2(1)4(2)2¤
--images--
General form
negates 1 =an-(.c)b=negates 2
suptraction
or
negates 1 =an-(.c)b
negates 2
suptraction
[S47]-negates subtraction
CM-[S47] -dot no know
________
images are in pdf (Download pdf)
PDF - https://docs.google.com/open?id=0B3WUvmmPIWZ4MmpzME5YNF9UbXF3eFJES1dsNkZPUQ