QM + GR = black holes cannot exist

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http://casa.colorado.edu/~ajsh/orbit.html

http://casa.colorado.edu/~ajsh/approach.html

The photon sphere

1.5 Schwarzschild radii from the singularity.

This is the location of the innermost unstable circular orbit. To maintain circular orbit at this radius requires going at the speed of light. In particular light itself can orbit the black hole in circular orbits at this radius. For this reason, this location is sometimes called the photon sphere.

Inside 1.5 Schwarzschild radii, no circular orbits exist, stable or unstable: all free fall orbits fall into the black hole. To maintain orbit inside 1.5 Schwarzschild radii without falling in, it would be necessary to keep rockets constantly on burn.

Photons do not orbit in circles at the horizon, just skimming the surface. The place where photons orbit in circles is the photon sphere, at 1.5 Schwarzschild radii. Photons emitted at the horizon fall in; except that if a photon is emitted exactly vertically outward exactly at the horizon, then it will hover at the horizon, not moving at all.

http://casa.colorado.edu/~ajsh/singularity.html
The last stable orbit in the Schwarzschild geometry is at r=6M. Between the photon sphere at r=3M and r=6M the possibility of knife edge orbits exist. These orbits require energy to be summed to the orbit to remain stable.
This is false. You apparently don't understand the difference between a free-fall and an object under acceleration. Ask one of your peers, I simply can't continue to tell you that you're wrong unless you consider the possibility that you are.
Hi Bruce. I've identified your problem.

By claiming that Galileo is "right" what you are maintaining is that fall times are independent of mass. In other words, from 10 meters above the Earth:
A golf ball would take 1.4 seconds
A bowling ball would take 1.4 seconds
A car would take 1.4 seconds
A building would take 1.4 seconds
The moon would take 1.4 seconds
The sun would take 1.4 seconds
A black hole would take 1.4 seconds

I'm confident that between my identification of your logical fallacy and the mathematical analysis I provided in the other thread you'll be able to reconcile this problem on your own.

Good luck!
Get a clue. You can't identify anything. Pay attention. The rate has nothing to do with the mass of the object in free fall. That's what the guy in the link (you think doesn't apply) said. Galileo figured that out. His experiment is based on weak field Earth parameters so the measurements reflect that. Get it? You think the parameter for M is the spacetime curvature associated with the Earth for objects like the Sun and black holes? Let's do it for an object whose mass is < the mass of the earth. The moon.

dr_shell/dt_shell = (2M/r)^1/2

M_earth = .00444meter

r_earth = 6.371E6meter

= (.00888m/6.371E6)^1/2

= .00003733384159 (c=1)

The rate objects fall in the near earth spacetime is dependent on the mass of the earth and the distance r. The mass of the falling object has no bearing on this. So your analysis claiming Galileo was wrong is crank nonsense. You need to learn the physics if you want folks to quit calling you names. Idiot wind.
 
The rate objects fall in the near earth spacetime is dependent on the mass of the earth and the distance r. The mass of the falling object has no bearing on this. So your analysis claiming Galileo was wrong is crank nonsense. You need to learn the physics if you want folks to quit calling you names. Idiot wind.
So, you're saying that all objects would take 1.4 seconds to fall 10 meters to the Earth unless they are "very very big"? That seems scientific to you, does it?
 
You don't need to accelerate to "c" to escape the photon sphere. You only need to accelerate to sqrt(2)c. You would need to accelerate to "c" at the event horizon.
If something was in a black hole it would already have had to have accelerated faster than the speed of light to even get to the event horizon. The escape velocity at the event horizon is the speed of light, but closer to the center of the black hole the escape velocity is greater than the speed of light. Then light inside of the event horizon wouldn't even make it to the event horizon, because the escape velocity of where it was inside of the black hole would have already been greater than the speed of light.
 
http://casa.colorado.edu/~ajsh/orbit.html

http://casa.colorado.edu/~ajsh/approach.html

The photon sphere

1.5 Schwarzschild radii from the singularity.

This is the location of the innermost unstable circular orbit. To maintain circular orbit at this radius requires going at the speed of light. In particular light itself can orbit the black hole in circular orbits at this radius. For this reason, this location is sometimes called the photon sphere.

Inside 1.5 Schwarzschild radii, no circular orbits exist, stable or unstable: all free fall orbits fall into the black hole. To maintain orbit inside 1.5 Schwarzschild radii without falling in, it would be necessary to keep rockets constantly on burn.

Photons do not orbit in circles at the horizon, just skimming the surface. The place where photons orbit in circles is the photon sphere, at 1.5 Schwarzschild radii. Photons emitted at the horizon fall in; except that if a photon is emitted exactly vertically outward exactly at the horizon, then it will hover at the horizon, not moving at all.

http://casa.colorado.edu/~ajsh/singularity.html
The last stable orbit in the Schwarzschild geometry is at r=6M. Between the photon sphere at r=3M and r=6M the possibility of
So, you're saying that all objects would take 1.4 seconds to fall 10 meters to the Earth unless they are "very very big"? That seems scientific to you, does it?
So, you're saying that all objects would take 1.4 seconds to fall 10 meters to the Earth unless they are "very very big"? That seems scientific to you, does it?
So, you're saying that all objects would take 1.4 seconds to fall 10 meters to the Earth unless they are "very very big"? That seems scientific to you, does it?
So, you're saying that all objects would take 1.4 seconds to fall 10 meters to the Earth unless they are "very very big"? That seems scientific to you, does it?
So, you're saying that all objects would take 1.4 seconds to fall 10 meters to the Earth unless they are "very very big"? That seems scientific to you, does it?
Quit trolling.
 
RJBeery,
I'd reason (feel free to find evidence to the contrary) that Gravity is a unification of field fluctuations surrounding all matter. (It can be disputed whether matter is the cause of the gravitation field, or whether that a distortion in space-time creates a pocket where gravity exists and matter accumulates.) In either sense there is going to be a limitation on the speed of gravity based upon the unified fluctuation. I couldn't tell you what the value is specifically however it's what defines the base Unified Rate of Attraction that both Galileo and Newton were familiar with.

Increasing or decreasing the volume of mass doesn't increase the Rate of Attraction it just factors in on the distance at which the Rate of Attraction effects other bodies. The further the distance the greater the time period that a small body is effected by Attraction, which is what effect's the speed of it's relative "Fall". However that fall could only ever accelerate as fast as that fluctuation propagates.

This is why some of the members here have likely come across a little rude to you in what you've been postulating because you are trying to argue against something that isn't just a belief, a hypothesis or even a theory, it's something that has been test (and continually tested) to be true.
 
To All,
It's come to the attention of the moderation that some posters have been overly hostile in regards to how they conduct themselves here. We ask if you could please refrain from name calling and seemingly hostile interactions so that the report button can be given a rest, as it threatened to quit this morning and we don't have a replacement one.
 
You don't need to accelerate to "c" to escape the photon sphere. You only need to accelerate to sqrt(2)c. You would need to accelerate to "c" at the event horizon.
???? $$\sqrt{2} \, c \; \color{red}{\gt} \; c$$
 
RJBeery,
I'd reason (feel free to find evidence to the contrary) that Gravity is a unification of field fluctuations surrounding all matter. (It can be disputed whether matter is the cause of the gravitation field, or whether that a distortion in space-time creates a pocket where gravity exists and matter accumulates.) In either sense there is going to be a limitation on the speed of gravity based upon the unified fluctuation. I couldn't tell you what the value is specifically however it's what defines the base Unified Rate of Attraction that both Galileo and Newton were familiar with.

Increasing or decreasing the volume of mass doesn't increase the Rate of Attraction it just factors in on the distance at which the Rate of Attraction effects other bodies. The further the distance the greater the time period that a small body is effected by Attraction, which is what effect's the speed of it's relative "Fall". However that fall could only ever accelerate as fast as that fluctuation propagates.

This is why some of the members here have likely come across a little rude to you in what you've been postulating because you are trying to argue against something that isn't just a belief, a hypothesis or even a theory, it's something that has been test (and continually tested) to be true.
First of all, being wrong does not merit ad hominem attacks on any science forum. Secondly, I'm simply not wrong. Double shame on the closed minds here AND the moderator who attempts to justify their behavior. Please click here to see my analysis and give your feedback if desired.
 
???? $$\sqrt{2} \, c \; \color{red}{\gt} \; c$$
Gah! You'd have to accelerate to sqrt(2)c if you wanted to break free of a circular orbit at the photon sphere (not possible, obviously).

The equation for escape velocity is
sqrt(2GM/r)

I've made a calculator at Wolfram Alpha for a 100 Solar Mass black hole HERE. Change the "1.0" to the multiplier of the R_s desired.

The photon sphere is at 1.5 R_s, and the result is 2.448E8 m/s which is clearly < c.
 
rpenner, since you've posted here you must know of the Galileo issue. Would you mind taking 10 seconds to explicitly let others know that the mathematical proof is valid? Your response in the other thread clearly meant that you passively agreed with it, but brucep is not getting the message and I'm tiring of trying to penetrate his skull.
 
I have a few questions (sort of on topic but not much related to BH.):
First is: Do photons have a very tiny gravitational field?
They have no rest mass so I guess the answer is no* (and at end of post support that with simple observation). Here is the problem that makes me have some doubt:

An electron and positron far from all other mater and 2 cm from each other, I think, could be orbiting about their mass center. A meter from it I think there should be a weak and slightly modulated gravitational field. (Modulated as in 1/4 the orbit period the field at 1M from the center of mass changes in magnitude only (not direction) from:
M/(1.01)^2 + M/(0.99)^2 To 2M/(1.0...0X)^2
(Yes I'm too lazy to find X and how many zeros between X and the 1.0 as I'm just justifying "modulated")

Second question: Does this modulation at point 2 meters form the mass center have speed of light delay? - I. e. does not have its max strength (about 25% as strong) exactly when field at 1M from mass center does have its max? - I think "yes.

Third question: These two charges are accelerating so are radiating. Hence spiral closer together will they not? Again, I think "yes."

Fourth question: Eventually they will transform into two ~ 511Mev gamma rays, that travel away from the old mass center point (perhaps the still mass center point if answer to question 1 was yes) will they not?

Fifth question: Does the slightly modulated gravitational field speeding off into space continue but now as a growing "no field hole" centered on the old mass center point? If answer to Q1 was yes, I think there is no hole as that remains forever the mass center of the two gamma rays, but if answer to Q1 is no then I guess there is an expanding field free hole.

Now for my observation supporting the No answer to Q1:
On a clear night I look at some stars - first with one eye then with the other. It is fact that both eye see the same star field. But consider the small (incredibly small) angle the path of the photons reaching my right eye differs from the path of the photons coming to my left eye. If these photons did have mutual gravitational attraction for say 100,000 light year long paths, then the "photo light field" should be "quills of light" with no light voids between. I. e. the field of stars seen by my right eye should not be the same as that seen by my left eye. Likewise, If I did not like the star field one eye was seeing, (other closed) just move head a little to see a different star field.

Comments (or at least what answers do you think correct to my 5 questions?)

* Also the photon's M = E/(c^2) mass is "frame dependent" so that would seem to be a problem with their "bending of space" view of gravity, I think. I do lean to the POV that all energy which is the same in all frames does make gravity. I.e. the gravity from a hot brick deceases slightly as it cools - Its temperature (random KE) is same in all frames. Any arguments on this POV? Note that jar of half ice & half water has T = 0C in all frames.
 
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I have a few questions (sort of on topic but not much related to BH.):
First is: Do photons have a very tiny gravitational field?
They have no rest mass so I guess the answer is no* (and at end of post support that with simple observation). Here is the problem that makes me have some doubt:

An electron and positron far from all other mater and 2 cm from each other, I think, could be orbiting about their mass center. A meter from it I think there should be a weak and slightly modulated gravitational field. (Modulated as in 1/4 the orbit period the field at 1M from the center of mass changes in magnitude only (not direction) from:
M/(1.01)^2 + M/(0.99)^2 To 2M/(1.0...0X)^2
(Yes I'm too lazy to find X and how many zeros between X and the 1.0 as I'm just justifying "modulated")

Second question: Does this modulation at point 2 meters form the mass center have speed of light delay? - I. e. does not have its max strength (about 25% as strong) exactly when field at 1M from mass center does have its max? - I think "yes.

Third question: These two charges are accelerating so are radiating. Hence spiral closer together will they not? Again, I think "yes."

Fourth question: Eventually they will transform into two ~ 511Mev gamma rays, that travel away from the old mass center point (perhaps the still mass center point if answer to question 1 was yes) will they not?

Fifth question: Does the slightly modulated gravitational field speeding off into space continue but now as a growing "no field hole" centered on the old mass center point? If answer to Q1 was yes, I think there is no hole as that remains forever the mass center of the two gamma rays, but if answer to Q1 is no then I guess there is an expanding field free hole.

Now for my observation supporting the No answer to Q1:
On a clear night I look at some stars - first with one eye then with the other. It is fact that both eye see the same star field. But consider the small (incredibly small) angle the path of the photons reaching my right eye differs from the path of the photons coming to my left eye. If these photons did have mutual gravitational attraction for say 100,000 light year long paths, then the "photo light field" should be "quills of light" with no light voids between. I. e. the field of stars seen by my right eye should not be the same as that seen by my left eye. Likewise, If I did not like the star field one eye was seeing, (other closed) just move head a little to see a different star field.

Comments (or at least what answers do you think correct to my 5 questions?)

* Also the photon's M = E/(c^2) mass is "frame dependent" so that would seem to be a problem with their "bending of space" view of gravity, I think. I do lean to the POV that all energy which is the same in all frames does make gravity. I.e. the gravity from a hot brick deceases slightly as it cools - Its temperature (random KE) is same in all frames. Any arguments on this POV? Note that jar of half ice & half water has T = 0C in all frames.

Billy, you present a series of questions that are very difficult to answer from a single theoretical basis. It seems your questions assume an inherent definition of gravity consistent with GR, and yet most of your questions/thought experiment are formed within the context of an interaction between fundamental particles, which is the domain of QM and an area where the charge relationship dominates the interactions. Gravity has not yet been successfully incorporated or explained within the context of QM. Still...

To the issue of whether a photon has a gravitational field, I would say no.., at least not directly and/or independently. But even this depends on the theoretical context you approach the issue from. If you approach that question from some interpretations of GR all energy contributes to a gravitational field. Some would interpret this to mean that even the photon has (or contributes to) a gravitational field. If on the other hand you begin from some of the theoretical work of Haisch, Rueda & Puthoff dealing with inertia and gravitation as emergent from an interaction between vacuum energy (specifically an EM spectrum of the ZPF) and charged particles (which could be extrapolated to matter), photons would have no independent gravitational field, while they would play a role in how inertia and gravitation emerges from quantum phenomena. (Note that Haisch et al are only dealing with the issue as boundary conditions between charged fundamental particles and an isotropic EM ZPF background. Extending their theoretical work to a classical scale is entirely speculative on my part... But it would suggest that the photons associated with the EM ZPF spectrum do not independently gravitate.)

I have a lot of trouble addressing the questions that follow, as individual questions, because they seem to me to be questions which would be dominated by QM rather than GR and gravity (Even though my comment above does just that.., crosses that divide). As example, when you begin with an orbiting electron/positron pair, even if those particles generate any independent gravitational field, they are point particles and their charge interaction would be far greater than any possible gravitational field.

While gravitation seems to have a far greater reach than, charge related interactions, it is also generally a far weaker force. It is only the extreme gravitational forces found at the centers of stars and black holes where gravity overcomes those charge related forces associated with atomic stability. This would not be the case when dealing with individual fundamental particles.

It does not seem to me that gravity can logically be thought of as playing a role in the hypotheticals you present.

Your last paragraph brought to mind a quote, which I am sad to say, I cannot find the reference for right now. It went something like this,

while it is true that all mas can be thought of as energy (or an expression of energy), not all energy is (or can be thought of), as mass.

Keeping all of the above in mind, it seems that your thought experiment is attempting to ask what happens to the gravitational field if the source, the electron/positron pair in your example, annihilate one another radiating away as two gamma rays. To that my answer would be that the gravitational field dissipates at the speed of light outward from the center of mass of the initial electron/positron pair. The mass has been converted completely to a non-mass form of energy, the gamma rays. From the Haisch et al perspective, the gamma photons would have no independent gravity, so the initial field would just dissipate at the speed of light.

If the gamma photons, do have independent gravitational fields, the change in the combined field would still occur at the speed of light, photons propagate at the speed of light, but the change in the gravitational field would be the same as if you were dealing with two stars, initially orbiting one another.., and then flying off away from their initial center of mass. The only difference would be how fast the change happens.

If this last accurately describes your overall question, it really did take me all of the above rambling to get there.
 
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Was Galileo Right or Wrong?

If two different masses are dropped at the same time, which one hits the ground first?

Poster #1: By claiming that Galileo is "right" what you are maintaining is that fall times are independent of mass. In other words, from 10 meters above the Earth:
A golf ball would take 1.4 seconds
A bowling ball would take 1.4 seconds
A car would take 1.4 seconds
A building would take 1.4 seconds
The moon would take 1.4 seconds
The sun would take 1.4 seconds
A black hole would take 1.4 seconds

Poster #2: The rate has nothing to do with the mass of the object in free fall. Galileo figured that out. His experiment is based on weak field Earth parameters so the measurements reflect that. The rate objects fall in the near earth spacetime is dependent on the mass of the earth and the distance r. The mass of the falling object has no bearing on this.

Tashja: Who is correct?

Prof. Berenstein: Both superficially seem to say the same thing to me.

In the time of Galileo, people thought that more massive objects fell faster to the ground (here we are talking about appreciably faster as could be measured in those times). Galileo showed that this was nonsense with an argument by contradiction. He also showed that gravity was an acceleration, and that it seemed to be independent of the type of material that was being let go in free fall.

It was afterwards with Newton that Newton refined the concept with the universal law of gravitation and the statement that the gravitational mass is equal to the inertial mass (this is an experimental observation). The universal law of gravitation then states that the acceleration due to any gravitational field is independent of the mass of the object (but this statement is only valid in an inertial system)

On the other hand the effective acceleration of an object towards the earth depends on the reduced mass (not just the mass). If the mass of an object is much much smaller than the earth's mass, the reduced mass is essentially the mass of the small object, and the effective acceleration becomes independent of the mass of the object. On the other hand, if we take a mass much larger than that of the earth (even of a magnitude like the moon), the apparent acceleration due to earths attraction between the moon and the earth would not be completely independent of the mass, and this is because the earth would be accelerated towards the falling object itself (this is the reaction in the action -reaction principle). This definitely would affect the timing of such a fall in an experiment which depends on the effective acceleration.

Poster # 2 fails only on being vague. The rate objects fall near earth might refer to the acceleration of the object relative to an inertial system, or relative to the earth. If poster #2 refers to a relative acceleration, then he is making a mistake (but for small objects it is negligible, so he is correct), whereas if he refers to the acceleration relative to an inertial system he is entirely correct.

Poster #1 is just snarky (he is not defending a position, just attacking a statement). With his examples he is trying to insinuate that the timing of free fall experiments would be different (because the sun would not fall to the ground in 1.4 s), but as argued above, that is just as expected in Newtonian mechanics.

In the end, of course Galileo was right (provided enough context is given).

I hope this helps.
Best,
David

---------------------------------------------------------------
David Berenstein | Department of Physics
University of California, Santa Barbara, CA 93106
---------------------------------------------------------------



Prof. Horowitz: Hi Tashja, poster #2 is correct: The rate objects fall in the near earth spacetime is dependent on the mass of the earth and the distance r. The mass of the falling object has no bearing on this, PROVIDED it is much smaller than that of the earth.

Best regards,
Gary Horowitz




 
...
If two different masses are dropped at the same time, which one hits the ground first?
...
Hi Tashja, thanks again for your independent research. Unfortunately, your wording was incorrect and led the Professors astray. I have explicitly restricted the question to masses being dropped separately, at different times. With the wording you provided, I would agree with "poster #2" as well.

I would also point out that they use phrases like "much smaller than that of the Earth" and "for small objects it is negligible", but brucep's assertion was that
brucep said:
Since Galileo discovered this he's technically right infinite in extent.

brucep is simply wrong on all accounts and his meltdown is occurring because of his inability to accept that fact.
 
I have a few questions (sort of on topic but not much related to BH.):
First is: Do photons have a very tiny gravitational field?
They have no rest mass so I guess the answer is no* (and at end of post support that with simple observation). Here is the problem that makes me have some doubt:

An electron and positron far from all other mater and 2 cm from each other, I think, could be orbiting about their mass center. A meter from it I think there should be a weak and slightly modulated gravitational field. (Modulated as in 1/4 the orbit period the field at 1M from the center of mass changes in magnitude only (not direction) from:
M/(1.01)^2 + M/(0.99)^2 To 2M/(1.0...0X)^2
(Yes I'm too lazy to find X and how many zeros between X and the 1.0 as I'm just justifying "modulated")

Second question: Does this modulation at point 2 meters form the mass center have speed of light delay? - I. e. does not have its max strength (about 25% as strong) exactly when field at 1M from mass center does have its max? - I think "yes.

Third question: These two charges are accelerating so are radiating. Hence spiral closer together will they not? Again, I think "yes."

Fourth question: Eventually they will transform into two ~ 511Mev gamma rays, that travel away from the old mass center point (perhaps the still mass center point if answer to question 1 was yes) will they not?

Fifth question: Does the slightly modulated gravitational field speeding off into space continue but now as a growing "no field hole" centered on the old mass center point? If answer to Q1 was yes, I think there is no hole as that remains forever the mass center of the two gamma rays, but if answer to Q1 is no then I guess there is an expanding field free hole.

Now for my observation supporting the No answer to Q1:
On a clear night I look at some stars - first with one eye then with the other. It is fact that both eye see the same star field. But consider the small (incredibly small) angle the path of the photons reaching my right eye differs from the path of the photons coming to my left eye. If these photons did have mutual gravitational attraction for say 100,000 light year long paths, then the "photo light field" should be "quills of light" with no light voids between. I. e. the field of stars seen by my right eye should not be the same as that seen by my left eye. Likewise, If I did not like the star field one eye was seeing, (other closed) just move head a little to see a different star field.

Comments (or at least what answers do you think correct to my 5 questions?)

* Also the photon's M = E/(c^2) mass is "frame dependent" so that would seem to be a problem with their "bending of space" view of gravity, I think. I do lean to the POV that all energy which is the same in all frames does make gravity. I.e. the gravity from a hot brick deceases slightly as it cools - Its temperature (random KE) is same in all frames. Any arguments on this POV? Note that jar of half ice & half water has T = 0C in all frames.
 
Hi RJ, but what is the difference if the two masses are dropped separately at different times? They make it quite clear that as long as the masses are smaller than the Earth, Galileo's right. Don't you agree?
 
Hi RJ, but what is the difference if the two masses are dropped separately at different times? They make it quite clear that as long as the masses are smaller than the Earth, Galileo's right. Don't you agree?
No!! Tashja, you are clever enough to understand my explanation. Please read it in the other thread. If you drop the items at the same time then they essentially become a "single item". If you drop them separately and time the descent you will get different results with different masses because the Earth has been pulled up towards the falling objects at correspondingly different rates.

Send a link of the other thread to your mentors, if you wish. They will surely agree with my analysis.
 
Hi Billy T

The energy of the photon is a component of the tensor descri
I have a few questions (sort of on topic but not much related to BH.):
First is: Do photons have a very tiny gravitational field?
They have no rest mass so I guess the answer is no* (and at end of post support that with simple observation). Here is the problem that makes me have some doubt:

An electron and positron far from all other mater and 2 cm from each other, I think, could be orbiting about their mass center. A meter from it I think there should be a weak and slightly modulated gravitational field. (Modulated as in 1/4 the orbit period the field at 1M from the center of mass changes in magnitude only (not direction) from:
M/(1.01)^2 + M/(0.99)^2 To 2M/(1.0...0X)^2
(Yes I'm too lazy to find X and how many zeros between X and the 1.0 as I'm just justifying "modulated")

Second question: Does this modulation at point 2 meters form the mass center have speed of light delay? - I. e. does not have its max strength (about 25% as strong) exactly when field at 1M from mass center does have its max? - I think "yes.

Third question: These two charges are accelerating so are radiating. Hence spiral closer together will they not? Again, I think "yes."

Fourth question: Eventually they will transform into two ~ 511Mev gamma rays, that travel away from the old mass center point (perhaps the still mass center point if answer to question 1 was yes) will they not?

Fifth question: Does the slightly modulated gravitational field speeding off into space continue but now as a growing "no field hole" centered on the old mass center point? If answer to Q1 was yes, I think there is no hole as that remains forever the mass center of the two gamma rays, but if answer to Q1 is no then I guess there is an expanding field free hole.

Now for my observation supporting the No answer to Q1:
On a clear night I look at some stars - first with one eye then with the other. It is fact that both eye see the same star field. But consider the small (incredibly small) angle the path of the photons reaching my right eye differs from the path of the photons coming to my left eye. If these photons did have mutual gravitational attraction for say 100,000 light year long paths, then the "photo light field" should be "quills of light" with no light voids between. I. e. the field of stars seen by my right eye should not be the same as that seen by my left eye. Likewise, If I did not like the star field one eye was seeing, (other closed) just move head a little to see a different star field.

Comments (or at least what answers do you think correct to my 5 questions?)

* Also the photon's M = E/(c^2) mass is "frame dependent" so that would seem to be a problem with their "bending of space" view of gravity, I think. I do lean to the POV that all energy which is the same in all frames does make gravity. I.e. the gravity from a hot brick deceases slightly as it cools - Its temperature (random KE) is same in all frames. Any arguments on this POV? Note that jar of half ice & half water has T = 0C in all frames.
Hi Billy T
The photons energy is a component of the stress-energy tensor.
http://en.m.wikipedia.org/wiki/Stress–energy_tensor

As the photon follows it's natural path (null geodesic) through the gravitational field (spacetime curvature) it's energy contributs to the local spacetime curvature over it's path. It's a very small contribution and it's fleeting since the photons energy remains with the photon as it continues along the natural path of light.
 
No!! Tashja, you are clever enough to understand my explanation. Please read it in the other thread. If you drop the items at the same time then they essentially become a "single item". If you drop them separately and time the descent you will get different results with different masses because the Earth has been pulled up towards the falling objects at correspondingly different rates.

Send a link of the other thread to your mentors, if you wish. They will surely agree with my analysis.

RJ, that is taking only the effect of the different masses of the falling objects, on the earth's mass and inertial resistance, into account. You are correct in stating that the larger mass will "pull" the earth toward it more than the smaller mass would, but what is being neglected is that the earth "pulls" the smaller mass toward it more than it does the larger mass. You have to account for the inertial resistance of all objects.

The net result is that if you begin with the same separtion distance and assume both objects are at rest relative to oneanother, it does not matter what the mass of each object is, the total mass and distance between the masses, is all that matters. They, a small and large object dropped toward a larger object, fall toward the larger object at the same rate. This will hold true as long as you are comparring how two objects with masses smaller than the third object, interact with the larger mass gravitationally.
 
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Hi Tashja, thanks again for your independent research. Unfortunately, your wording was incorrect and led the Professors astray. I have explicitly restricted the question to masses being dropped separately, at different times. With the wording you provided, I would agree with "poster #2" as well.

I would also point out that they use phrases like "much smaller than that of the Earth" and "for small objects it is negligible", but brucep's assertion was that


brucep is simply wrong on all accounts and his meltdown is occurring because of his inability to accept that fact.
If I was wrong you'd be writing

dr/dt = (2M/r)^1/2 (Newton, Einstein, and everybody else in physics)

As

dr/dt = (2M+m)^1/2

LOL

Regardless your juvenile analysis it's

dr/dt = (2M/r)^1/2

LOL
 
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