Originally posted by MacM
ANS: I would conceed you are more "knowledgable" of physics at least as taught. But (and I already know your response to this will be assininely negative but who cares) I am more adept to understanding reality than you.
This in itself is a somewhat assine comment. Your 'understanding reality' must be based on experiences you have already had... unless you call on some higher power, which I don't think you will. That said, your only experiences have been in standard every day physics. Although you learned about nukes, you had no actual experiences with seeing 2 atoms collide... and all your 'knowledge' of the situation is based soley on the text books given to you. In terms of relativity, you have no personal experiences where you would think they played a large role (even though they may have, and you not realised it). I take issue with you assuming you are more 'adept to understanding reality' when you are not adept to picking up a book and learning about things that you personally can not test.
Do you not realize that unless challenges are made to current theory and you go through life preaching current concepts as a matter of absolute law of reality that there could be no change.
Challenges are worthless unless they are made with a complete understanding of the theory. You haven't made a signle original challenge which hasn't already been answered... it accomplishes nothing.
Using the teachings of current concepts as their own justifiction is defeatist and no progress will occur.
Until you see a 'reality' in which the current concept breaks down, we have nothing to build a new one on.
many issues are beyond absolute detail of mathematics they are a matter of clarity of thought and not seeing the world through tainted glasses.
'Clarity of thought' will not disprove realtivity unless it finds some internal contradiction which was missed by the many people who developed, use, teach, and learn it. What it takes to disprove realitivty is a physically possible situation where relativity gives the wrong answer.
I support my arguement from my perspective without the benefit OR yoke of burden of authority.
A 'perspective' is severily damaged by a lack of knowledge in the field, because you are effectively blind to the reasoning behind it.
It is "Xxxxxxx" Xxxxxxx.
You know someone is serious when they call you and Xxxxxxx
Originally posted by ryans
It takes many lines for you to explain gravitational force in your frane work, it takes about half a page to state, and solve Newton's equations!
What is simple?
The derivation can be found on the UniKEF homepage... however it is a mess to derive, and in the end relies on constants which are not easily measurable. Also, the derivation gives the same result as integrating point forces over an area/volume (I think you know what I mean, but the phrasing may be poor). The benefit in the standard approach is that it is easily calculatable and doesn't rely on any unknown constants. You can actually get an answer, and not a bunch of unknowns.Originally posted by ryans
Give me a mathematical statement for your definition of gravitational force Mac.
It is "Xxxxxxx" Xxxxxxx.
You know someone is serious when they call you and Xxxxxxx
Originally posted by ryans
It takes many lines for you to explain gravitational force in your frane work, it takes about half a page to state, and solve Newton's equations!
What is simple?
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are you under the impression, ryans, that when newton first published his theory of gravitation, it took only one line? if so, then you are wrong. he filled several chapters of principia with it. the explanation alone took one.
just because you can state a result in one line, does not mean that the theory was simple, or easy to state, or trivial to come up with, in the beginning. in fact, i believe the contrary is true: the simpler and more obvious the theory, the more difficult it is to come up with.
The derivation can be found on the UniKEF homepage... however it is a mess to derive, and in the end relies on constants which are not easily measurable.
Also, the derivation gives the same result as integrating point forces over an area/volume (I think you know what I mean, but the phrasing may be poor).
The benefit in the standard approach is that it is easily calculatable and doesn't rely on any unknown constants. You can actually get an answer, and not a bunch of unknowns.
Look up the yukawa potential to see its exact form.
Mac you ****, this as a genuine proposition. To my knowledge, this integral cannot be solved within the framework of modern mathematics, due to the nature of the singularity at r=0. If someone can solve this integral, it would change physics, as it is a standard integral in field theories where infinities arise. Thus if a solution is found in your framework, I will be genuinly and instantly converted.
Originally posted by MacM
They are simply a hypothetical bifurcation of the standard "G" constant. Their product will result in "G". One would use "G" to calculate gravity but "U" and "~" will have other useful purposes once they are determined.
I can't even find the slide that had the solution on it now. But anyway, how do you find U, ~, and G?
Actually this is not yet known. Dr Allards calculus only evaluates the concept as applied to two circles and the UniKEF form of integration has never been done for solid geometry.
You will get the same result as standard gravity calculations. As much as you don't like to admit it, you system is a standard push gravity system.
Further the concept does not integrate objects to a point source in the same manner that standard integration is used. U.. Integration has a different function which includes geometry of the object in its final conclusion. Only solid congruent spheres will produce the same general result of being equivelent points
I agree that only spheres at a distance are incredibly accuratly estimated as point masses. For all other shapes, you will (by neccesity) get the same result as volume integration. These equations have been used on large groups of stars, and have given correct answers. (While the star is a sphere, the group of evenly distributed ones is not.)
Newtonian is easier than Relativity but you like Relativity.
I like both. I have no reason to rely on relativity when I calculate everyday stuff here on earth. Newtonian isn't completely correct, but at sub-sub-c-velocities it is damn close.
I believe it should come down to which one is the most correct to observation and testing.
Good. Relativity wins then, as it has passed every observational and test put to it.
I can tell you that as of right now Newton is in trouble and I think so is Einstien but I won't go there until my data is at hand and at that time I am going to fully enjoy this MSB's participation.
Please stop using your invisible data as if it supprts your cause. I have my own test going that supports relativity. You'll see it next april. Until then just believe that my data completely supports it
They are simply a hypothetical bifurcation of the standard "G" constant. Their product will result in "G". One would use "G" to calculate gravity but "U" and "~" will have other useful purposes once they are determined.
I can't even find the slide that had the solution on it now. But anyway, how do you find U, ~, and G?[/quote ]
ANS: I don't. G is G as found historically. The U nad ~ are Field energy and absorbtion coefficient. I give a hypothetical example but no actual derivation is done. Whatever therre respecive values they must account for the weakest gravity to Black Hole gravity. In genral it appears U is quite large and ~ is amazingly small.
Actually this is not yet known. Dr Allards calculus only evaluates the concept as applied to two circles and the UniKEF form of integration has never been done for solid geometry.
You will get the same result as standard gravity calculations. As much as you don't like to admit it, you system is a standard push gravity system.
Further the concept does not integrate objects to a point source in the same manner that standard integration is used. U.. Integration has a different function which includes geometry of the object in its final conclusion. Only solid congruent spheres will produce the same general result of being equivelent points
I agree that only spheres at a distance are incredibly accuratly estimated as point masses. For all other shapes, you will (by neccesity) get the same result as volume integration. These equations have been used on large groups of stars, and have given correct answers. (While the star is a sphere, the group of evenly distributed ones is not.)
Newtonian is easier than Relativity but you like Relativity.
I like both.
I have no reason to rely on relativity when I calculate everyday stuff here on earth. Newtonian isn't completely correct, but at sub-sub-c-velocities it is damn close.
believe it should come down to which one is the most correct to observation and testing.
I can tell you that as of right now Newton is in trouble and I think so is Einstien but I won't go there until my data is at hand and at that time I am going to fully enjoy this MSB's participation.
Please stop using your invisible data as if it supprts your cause. I have my own test going that supports relativity. You'll see it next april. Until then just believe that my data completely supports it
You are basing your perspective on a macroscopic approach. The difference are more pronounced at micro csopic scale.
Actually, gravity is less pronounced on a microscopic scale. Especially when measuing changes caused by geometry, because the atomical bonds are highly geometrically dependent.
Good. Relativity wins then, as it has passed every observational and test put to it.
ANS: In a contest between Newton and Einstien I would agree.
Actually, in contest to every other theory so far.
If you don't want to hear about testing then don't attack the concept before it is posted. Is that fair or what?
Then don't attack relativity before you understand how it was derived and what it says. Is that fair or what?
Scary, agreed on all points.Originally posted by MacM
ASN: We agree but that doesn't need to be overly huge. A bowling ball is more than adequate and they have measured microgravity in Casimir Tests.
I agree as long as you don't try to declare the contest over.
Deal but that doesn't mean I am prohibited from raising questions or challenging answers.
Lets wrap up the "Relativity" string and move on.