I agree that what I personally did was not in vacuum, but the molecules of air are much smaller than the 30 cm length of the photons I measured and they were line radiation from a gas discharge glow of a gas not found in air. (Sodium vapor much like those used to on some streets making yellow light.) Each of these facts separately and independently makes your "instantaneous jumps” between atoms (with inertial delays in each atom) alternative impossible (two independent reasons briefly discussed near the end of this post plus another, first discussed, but not much related to my lab experiment that measured the length of the photon.):...if your exposition proves that a photon travels from A to B across vacummuous space I will be more than happy to part with my $100 usd....but we shall see...
Obviously there is already a significant disadvantage to your presentation and that is it is performed in an ambient medium [ air or nitrogen or whatever as it doesn't matter ] so the need to show light transiting a vacuum is still a concern. However if one can conclude that satisfactory evidence is possible even in an ambient medium such as air we may side step that requirement.
It could be proposed for example that light energy "jumps" from particle to particle across the space in between instantaneously, with out traveling [in a medium such as glass - optic fibre or water or air or anything of mass.] the delay in time being experienced due to distance, being a mass inertia effect*** and not a time to transit effect. So ruling out mass as the medium for transit is very necessary. It is the space that is vacant between particles of mass, the vacuum and the void that is normally inhabited only by photons and em that is in question. …
*** the invariant speed of light could actualy be a significant aspect of "inertia" but is lost to us because we put it the photon outside of mass instead of inside mass. [ which is where we can only observe it any way...]
Light comes from the sun to the Earth’s very-high, extremely-rarefied atmosphere thru a very high vacuum in about 8.5 minutes. We know the position of the moon, mercury and Venus as function of time very accurately compared to 8.5 minutes. All three occasionally do pass directly between Earth and sun, but for my current purpose Mercury is best as it is closest to the sun. It appears as a small dark spot moving across the sun - Many years between these observations as there are lots of ways sun Mercury and Earth can fail to be well enough aligned almost on one common line. The most recent one was a few years ago and very carefully recorded as the exact size of the AU and the sun can be determined most precisely from the Mercury transit time etc. I.e. Astronomers know exactly (compared to 8.5 minutes) when Mercury's shadow makes "first contact" with the sun's edge actually takes place (about 7 minutes later it is seen on Earth) So we have a start event and a stop event about 7 minutes separated by the delay of light travels yet there are essentially no atoms to be providing your "inertial" delay with instantaneous jumps between atoms.
Furthermore and even more simple and powerful proof against your idea is the fact that the edge of the shadow of Mercury during it transit across the sun is very sharp especially if photographed from an air plane or balloon above almost all of the Earth atmosphere atoms. If the edge of the shadow were jumping between atoms as your alternative suggest the shadow would not have sharp edges. The entire shadow would be a "bell curve" intensity shape darkest at the center with gradual increase in light as one moves away from that dark center - not any well defined edge to the shadow.
This is because with each "jump" to the next atom the energy is moved slightly to the side of the straight line path in some random fashion. I.e. your alternative has the energy making a "random walk" generally towards the Earth. If there are N atoms taking part in the step by step transit to the Earth and each on average causes the energy to "slip sideways" from the straight line path by D on average, then the net total sideways slip when the energy get to the Earth is D times the square root of N. The sharp edged observed shadow would not form - We would observe a "bell curve" intensity pattern with no defined edge at all!
If N is relatively small, say 1500, then each of the sideways steps are very big as is the total sideways slip. This is because the AU = 150 million Km. I.e. each step on average between atoms is 100,000,000 meters long and the typical "slide ways slip" D would be many kilometers away from the straight line path. Likewise in the ~7 minutes of "Mercury shadow" travel to Earth there are ~420 seconds so each the atoms delaying the energy transport must "inertially hold" the energy for ~0.3 seconds, presumable in some energy storing excited state. That is an "eternity” for an excited state to avoid decay back to the ground state. Furthermore when the energy is released 0.3 sec later by the atoms how does it know which way to go?
Consider an atom that is 1,000,000 Km off the straight line path from sun to Earth. It too is in sun light so is holding energy on average of 0.3 sec also. When it releases the stored energy it is just as likely to be instantaneously jumping to an atom that is closer to the sun as to one which is further away. It might jump to one that with subsequent jumps delivered the energy to Earth. Thus even the sun its self (forget about the minor problem of Mercury’s sharp edged shadow) would not appear to be a 0.5 degree wide disk in the sky. Sunlight would be coming to the Earth from EVERY direction if sunlight energy were stored in atoms for 0.3 seconds on average. I.e. some packets of sun energy would get farther from the sun than the Earth is and then the release of energy would send the energy back towards and atom which was nearer to the sun, if the Earth were not in the way. I.e. sun light would come to earth even at midnight! (But of course there would not be any night. Only the minimum light time probably called "mid dim" 12 hours from "max light" - day and night would not exist if your alternative were true (and there were only 1500 or so steps).
Now let’s consider the opposite extreme N is enormous, "zillions of steps" not a mere1500. For example let’s assume that average atmospheric density up to 100,000 feet is the average density of atoms ALL the way to the sun.
First let’s note what the effect of only the 100,000 foot thick atmosphere actually does to star light. "twinkle, twinkle, little star" is caused by very small random density changes in the atmospheric density (as is the sky being blue, but that is another story) let’s say, just to illustrate the problem your alternative faces in this case: the total random deflection of star light, its "twinkle" on average, I will conservatively assume is only 0.000,1 degree. (If it really were that small, the stars would not "twinkle" to the unaided eye as the angular resolution of our vision is not that good.)
For convenience I will call the 100,000 feet 30,000m. Now in the 150,000,000,000 m AU (distance to the sun) there are 5,000,000 or five million of these 100,000 foot thick atmospheres "slabs" to get thru with random deflection of the light path each greater than my conservative 0.000,1 degree in each. The net angular deflection effect is not 5,000,000 times 0.000,1 = 500 degrees but the square root of that or 22+ degree total off sets but I will call it 20 degrees just to be even more conservative. (My 0.000,1 degree is also too small, well below human eye resolution ability, and we do see the little stars "twinkle" do we not?)
Thus in this "N very large" case, the angular width of the sum would be 40 times larger than it is, and just to return briefly to the Mercury transit shadow, in this N large case: There would be no shadow as with the back ground sun light being deflected on average of 20 degrees the tiny (by comparison to the 0.5 degree wide sun) black dot that we see transiting the sun would be invisible.
Hell, as I think Mercury never gets 20 degrees from the sun's center and the sun light would appear to be coming from a "edgeless disk" 40 degrees wide to where the intensity was half the central intensity, we could only know of the existence of Mercury via its tiny gravitational effect on Venus, if we could know that Mercury even exists at all. (I am not sure we could even see Venus, the brightes star in the heavens, with the un aided eye - it too might always be lost in the >40 degree wide sun.)
SUMMARY: Your alternative theory of energy instantaneously jumping from atom to atom with some "inertial storage delay" in each atom to explain why the speed of light it finite conflicts with the most rudimentary observations of even the Neanderthals. - Namely the 24 period is dark for ~12 hours. It also conflicts with the fact the sun appears to be a disk with sharp edges only 0.5 degrees wide (instead of at least 20 degrees wide). It also conflicts with the fact that Mercury is not only visible to the un-aided eye, but one of the brighter "stars" in the heavens.
These observations alone destroy your alternate theory of why light has a delay in going from A to B; however the $100 was not offered for this. It was offered for showing that something is moving between the light source and the screen (or place he energy is absorbed). That I did as I even measured the length of this "something" and found it to be ~30 cm long - much too long to be stored in an atom "as is." If compressed down to atomic size during the storage period many times in both paths T & R of the interferometer, then the spinning (and suffering collisions) atom would have no way to know in which way to send it on its next instantaneous step to another atom of the air.
Even if that precise angular information could somehow be stored in each atom for each delay period, there is still the need for exact "in phase" recombination at the screen to produce the constructive interference peaks observed (and preservation of exact 180 "out of phase" at the screen to make the zero intensity nulls of the interference pattern). This is totally impossible even if one also postulates that somehow both the direction of energy travel and the phase information could be stored in the atom. This is because the atom is in constant motion during the storage interval and moves thru a distance very large compared to the wave length. Thus even if it could regenerate the 30 cm long wave with exactly the phase it had when it was absorbed, that is not the phase it must re-emitted from the atom's new location at the time it releases the stored energy for the next instantaneous step. Thus, the atom must store the 30cm long wave's exact energy* and give it back later, store the phase of the wave it absorbed, record how far and in what direction is has moved during the storage period, compute the correct "phase shift" needed due to the atom's shifted location while storing before sending the new phase information onto the next absorbing atom in the chain of absorbing atoms. Also the sending of all this information correctly requires that the atom knows which of the zillions of atoms is the "next atom" in the chain. For example, the phase shift required and the information about the magnitude of the energy (none actually travels if your alternative is correct) must be tailored to compensate for the speed of BOTH the now emitting atoms and the now (it is instantaneous in you model) speed of the next absorbing atom whose identity must be known by each of he releasing atoms!
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Finally, although I worked in air the more accurate tests of the "either" were in vacuum. In fact Michelson also made one of the (if not the most) accurate direct measurements of the speed of light in vacuum. For this there was a mile long steel pipe with mirrors at each end to reflect the beam back and forth about 20 times as I recall. - Effectively a 20 mile path thru very high vacuum. With "mirror folded" interferometers, this pipe was also used to do many interferometer studies, some no doubt like mine measured the length of photons from various gases in addion to sodium.
The famous M&M test of the either theory was not done in this vacuum pipe as like the wiki drawing of my prior post, the two paths or "arms" of the interferometer must be nearly orthogonal. I seem to recall that they did have a much shorter pipe that was orthogonal to the mile long pipe and repeated that M&M test again with its help, getting the "null result” still of course. Unfortunately the mile long vacuum pipe no longer exists. (It was owned by some mid western university as I recall. After it had been used for a dozen or so years there was little demand for it, so the university sold it, as scrap iron, I think.)
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*It is known that sodium line radiation passes thru air with little or no absorption both experimentally (when used to illuminate streets with yellow light) and from the fact that there is no energy level in O2 or N2 above the ground state energy level by an energy difference exactly equal to the energy of each sodium generated photon. Thus for an atom to "swallow the energy" and hold or store it you must violate conservation of energy. - No exactly appropriate energy level exists for the storage of 100% of the energy incident on the atom. Thus, a little energy would be lost in each step (Several pecent at least, I would guess.). So if the radiation entering an air filled room via the door were harsh UV or x-ray it would be only a radio frequency wave by the time it got to the other side of the room!
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