Gravity never zero

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If you want to pretend you wrote it yourself, and didn't cut and paste, you should get rid of the footnote.
 
wellwisher, I assume the quote was from wiki, since the formula seems to have been. It would help to note the source of a quote and generally a link to it.
 
If you want to pretend you wrote it yourself, and didn't cut and paste, you should get rid of the footnote.

I left it there, so I would not be accused of cheating. If youread Wiki you will realize there is more one definition of entropy.

Your definition was elementary and limited. It did not provide you solid enough ground, to act like an expert who can discount others. There are other boneheads that have also been doing this and the staff is not doing its research but letting the boneheads act.
 
Disappointing!

Watch the link and explain to me the loss of mass. combustion: chemical equations

Laws of Chemistry

Emil, any mass lost during a chemical reaction would be equivalent to the radiated heat during the process, assuming the process is capable of containing all, by products of the process. Under most conditions the mass involved in that heat loss is far below our measurable threshold.

We cannot prove it. However, I do believe there has been some verification of the loss of mass during the normal decay of radioactive material. Assuming that at least a portion of that mass was from radiating infrared radiation, any process that results in radiating heat should logically also result in some loss of mass.

Does that radiated energy at some time contribute to an increase in mass elsewhere? It is likely to the extent that one can be sure that the EM radiation at some time is absorbed somewhere else. As we have no truely closed systems to work with, it would seem likely that ultimately not all radiated heat is re-absorbed. Some portion may radiate away through the universe indefinitely. And thus the initial total mass must be diminished by an amount equal the lost EM radiation.
 
weelwisher:

If gravity is modeled by general relativity GR and gravity was zero, GR would no longer apply, since it only applies if there is gravity. If gravity equal zero the is no gravity phenomena present so GR does not apply.

No, that's wrong.

General relativity is a model of spacetime in general - gravity or no gravity. In general relativity "gravity equals zero" is equivalent to saying "flat spacetime". GR still applies.

The definition of work, is force acting over a distance. If gravity was zero there would also be no gravitational work acting. This means entropy would be maximized.

Non sequitur.

Gravitational work, by increasing pressure, causes local entropy to decrease.

Pressure of what? What are you talking about?
 
Disappointing!

Watch the link and explain to me the loss of mass. combustion: chemical equations

Laws of Chemistry
I think there was a hint of it when if I work out the weight of a Carbon atom and the weight of a Oxygen molecule and compare it to the weight of a Carbon dioxide atom would they be exactly equal? :)

Definition: Law which states energy cannot be created or destroyed, but may be changed from one form to another.
So if it lost energy it is also a mass loss, but if the whole reaction is contained there is conservation of mass since it is an enclosed system.
 
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OnlyMe, can you give a link, where mass loss is revealed as you stand for?

Emil, within thermonuclear reactions I include normal radioactive decay, which may include neutron radiation and EM radiation under normal conditions and a variety of broken atomic parts in a bomb. The only aspect that involves a loss of mass if you account for ejected particles as conserved mass, is the EM radiation. For that the easiest reference is the first, I know of on record.

DOES THE INERTIA OF A BODY DEPEND UPON ITS ENERGY-CONTENT?, Einstein's 1905 paper that introduced the equation E = mc^2 (though in that paper he used "L" in place of "E". E was later used in the formula to standardize terminology.)

The paper essentially says that when an electron in an atom moves between energy states it emits or absorbs a photon and that in the process the atom loses or gains mass, equal to the energy of the photon divided by c^2.

Photons extend in wavelength far above and below the visible light spectrum we associate with light. At least a portion of the heat radiated away from any body is in the form of heat in the EM spectrum.

If you accept the equation E = mc^2 and Eistein's paper introducing it as valid, then when any process involving mass or an object, radiates heats in the EM spectrum it must also lose mass. Which in classical terms, weights and measures, is insignificant, but cannot be ignored.

While chemical reactions do not involve the loss of particles in the same way that a nuclear decay might, they do involve heat radiated at least partially in the EM spectrum and so, by the same logic must involve some transfer of mass from one atom to another, and a loss of mass where that EM radiation fails to be re-absorbed by another atom.
 
I think there was a hint of it when if I work out the weight of a Carbon atom and the weight of a Oxygen molecule and compare it to the weight of a Carbon dioxide atom would they be exactly equal? :)
Yep, with the correction "Carbon dioxide molecules".
Also, the weight of two Carbon atom and the weight of a Oxygen molecule compared to the weight of two Carbon monoxide molecule are exactly equal. :)
Definition: Law which states energy cannot be created or destroyed, but may be changed from one form to another.
Yes, for example potential energy turns into kinetic energy.
Or reversible chemical reaction where energy is needed.
So if it lost energy it is also a mass loss, but if the whole reaction is contained there is conservation of mass since it is an enclosed system.
Always must be considered an enclosed system !
Otherwise laws of conservation of mass and energy are not valid !
 
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Emil, Robbitybob1. :)

Have you considered the case where particles/anti-particles with 'mass' (electron and positron for example) mutually annihilate and produce only GAMMA e-m radiation?

There ALL the 'mass' (matter form) has converted to 'massless' (E-M radiation form).

For more background on 'Gamma Decay', look up....

http://en.wikipedia.org/wiki/Gamma_decay


Hope this helps your discussion. :)

Cheers.

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Have you considered the case where particles/anti-particles with 'mass' (electron and positron for example) mutually annihilate and produce only GAMMA e-m radiation?
Hi RealityCheck,
Yep, in this case I considered the particles as a wave. :)
:cheers:
 
Hi RealityCheck,
Yep, in this case I considered the particles as a wave.
:cheers:

OK. But I make no comment on the 'wave' aspect, mate. :)

I only meant my post/link to regard the question whether E-M radiation (ie photons) contribute to 'mass' (and vice versa when the photons 'depart') when the photons enter into the 'massive' context (in this case the electron-positron pair context). That's all I meant to comment on.

As to the further question of whether particles of 'mass' are also 'waves' or not, I will leave it to the present discussion-in-train participants on that question to consider further from their respective perspectives/knowledge and known science, as the case may be.

Cheers and good luck and good thinking, Emil, everyone! :)

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RealityCheck,

You have nothing to do with particles. They are part of a model. :)

Cheers.

Yes, mate, I understand your stance on that aspect. Naturally, even a HULA HOOP has a 'wave effect' when thrown through a 'waterfall'. In that illustrative context, the leading-edge of the 'hoop' passes through first and affects the waterfall 'surface', followed in due course by the 'hoop' trailing-edge which cuts through in its turn.

So in that scenario, the hula-hoop has a 'wavelength equal to its diameter? Nevertheless, we KNOW that the hula-hoop is a massive structure or 'massive particle' with defined leading and trailing 'edges' and contours etc etc. 'mass/matter/energy' properties.

It depends on the context of the 'WHOLE interaction' (rather than just ONLY leading OR trailing edge interaction separated by measurement/distance interactive factors).

The whole picture may be 'parsed' by either the observer or the detector as being a 'double wave' OR as a 'whole wave' having spatially far-separated components/effects which may or may not be included in any one 'instantaneous' event/measurement etc.

Cheers and keep the thinking coming! Goodnight! :)

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