You claim to be competant at electromagnetism. I don't believe you.First of all I think that your "quetion 2" has nothing to do with my claim
It took you more time to write your last post than it did for me to solve those questions.nd really I don't have much time to stay in the forums as I would like to to spend it with unproductive subjects.
Yes, you and I have met before. And once you made it obvious you don't know any mainstream physics or maths and you have no intention of learning any, despite making wild claims about such things, I stop sugar coating my responses. It's generally easy to tell the difference between crank newcomers and sane new comers. Within seeing about 3 of CptBork's posts, I could tell he was sane and knowledgable. Hence why I didn't jump down his throat when he said "I've studied string theory". I see from his posts he's knowledgable in the right things for that to be entirely possible and since he doesn't seem to stretch the truth, I believe him.Second, You should review your posting to see that you are, how to say, too agressive and this always leave to very bad discussions. I know that because I have already discussed with you other times and because I have the experience to have discussed with others that behave like you and rarely those discussions could leave to a productive conclusion.
You've made claims about the standard model, electromagnetism and a variety of simpler mathematical and physical concepts and none of those times have you shown you're competant at them. Just now on PhysOrg you claimed that solutions to the wave equation are spanned by a 2 dimensional basis because it's second order.
And yet $$y(x,t) = \sum_{n=1}^{\infty} \sin\left( \frac{n \pi x}{L} \right) \left( A_{n}\sin\left( \frac{n \pi c t}{L} \right) + B_{n}\cos\left( \frac{n \pi c t}{L} \right)$$ is a solution to the wave equation over the infinite dimensional orthogonal basis $$\sin(k n x)$$ and $$\cos(k n x)$$. As I said to you in either this thread or the one on PhysOrg, degree n equations need n independent boundary conditions to uniquely specify a solution. A general solution over functions will be spanned by infinitely many basis vectors.
If you don't want people to instantly think you're fulll of BS, show some level of competancy at the topics you discuss. Then I'll be cordial, just like I'm polite to people like Ben and QuarkHead. Until you earn my respect, I don't give it. Infact, you're earnt my scorn by your nonsense claims.