Motor Daddy
Valued Senior Member
Now back to the task at hand, Tach's answer as to why the equations are "anti-mainstream, crackpot" stuff.
Yes it's constant acceleration. For example, a car has an initial velocity of 23 m/s and a final velocity of 82.7 m/s. It was under constant acceleration for 3 seconds. What distance did the car travel? What was the acceleration rate?
Forget it! I'm wasting my time with you. This is a physics and math section on a science forum. The equations of motion are HS stuff, are they not? AN learned this stuff when he was 2 years old! You don't address my responses, you simply make up more stuff to try and complicate things further, to the point that everything is lost in the words. If you don't understand what the equations of motion are used for, and don't recognize them when you see them, I suggest you learn them before you start touting Relativity.
Is that a rhetorical question, or did you actually ask me to solve a 7th grade math problem?
It was my response to your previous replies and questions. You ask me questions, I respond, and then you respond with this? Like I said, forget it, I'm wasting my time with you. No free lessons for you. If you learned this stuff in 7th grade then why were you so confused (and still are) about what the equations were?
You asked for details.
I didn't ask you for details
Motor Daddy said:What is anti-mainstream crackpot about the following? Tell me specifically in detail![/i]
As I said beforeMotor Daddy said:you asked me, because you didn't recognize the equations as being equations of motion.
I'll leave it to you to relate the terms "kinematics" and "equations of motion".Before you ask someone to turn their attention to a scenario in which you've left it an open assumption that da/dt = 0 and t[sub]u[/sub] ≤ t ≤ t[sub]v[/sub], you would have to say more before assuming your readers find a motive for turning their attention to kinematics.
Motor Daddy said:You asked me what the first equation meant to me and I told you,
Motor Daddy said:Yes it's constant acceleration. For example, a car has an initial velocity of 23 m/s and a final velocity of 82.7 m/s. It was under constant acceleration for 3 seconds. What distance did the car travel? What was the acceleration rate?
Motor Daddy said:and asked you what it meant to you. You could have just gave a simple direct to the point answer as I did, but you wandered off on some tangent, as usual with you.
Is that a rhetorical question, or did you actually ask me to solve a 7th grade math problem?
I already categorized it as 7th grade. That's a pretty overt way of saying the opposite.Motor Daddy said:You get caught off guard
Now who's caught off guard.Motor Daddy said:and look foolish,
Which part confused you more, my inquiry into why you chose da/dt = 0 and t[sub]u[/sub] ≤ t ≤ t[sub]v[/sub], or the second question about the roots of a quadratic?Motor Daddy said:and then try to cloud the issue with paragraphs of BS so as to confuse the reader,
What grade level of competency does my question immediately above demonstrate?Motor Daddy said:to hide your incompetence of 7th grade math
You wouldn't be able to form a competent assessment of my understanding of 7th grade math since you evidently dropped out in the 6th grade.Motor Daddy said:and lack of understanding thereof!
All you said was
It means the average velocity of an object, times the time of travel, is equal to the distance the object traveled. The equations are a complete set of equations so that you can "plug and play" three factors to find the other two factors.
We've already established that your reader could not have reached that conclusion without first assuming da/dt = 0 and t[sub]u[/sub] ≤ t ≤ t[sub]v[/sub], which is has no factual predicate for assuming it to be so. This, of course may not be obvious if you are still scratching your head over 7th grade math and aren't able to appreciate the ideas from readers who not only grew out of that but moved on to 8th and 9th grade math, leading to the actual math that describes kinematics as explained by its two inventors.Motor Daddy said:Now you can't read? You're pulling my leg, right?
I said:
It means the average velocity of an object, times the time of travel, is equal to the distance the object traveled. The equations are a complete set of equations so that you can "plug and play" three factors to find the other two factors.
Wow, it looks like you guys had fun all night. It leads me to wonder where you are posting from, i.e. what time zone are you in?
MD has stick-to-it-iveness. I think he is pretty much staying focused on the nature of the universe, so I would be surprised if he has gotten mixed up with a bad crowd of motor oil sniffers.No, I just wasn't out all night sniffing motor oil, or whatever MD does for kicks.
Get some sleep, lol.Makes me wonder if I can repackage Valvoline or STP as a math-enhancing aroma therapy with the brand name "Plug N Play". The logo could be a big Sparky, a humanoid spark plug wearing a contraption that appears to be downloading vast equations directly into his brain. Upon close inspection, they would turn out to say "x + 1 = 1 + x", something along that line, something that appeals to the 6th grade level of math competency.
MD has stick-to-it-iveness. I think he is pretty much staying focused on the nature of the universe, so I would be surprised if he has gotten mixed up with a bad crowd of motor oil sniffers.
We touched on the mainstream view, if you mean Big Bang Theory, and that discussion addressed the gravitational waves associated with changes in motion of bodies in space due to interruptions of motion, and the time delay of that information. Is that what you mean by the mainstream view?Good way to take the steering wheel and try to pull this jalopy out of the ditch after MD ran this off the road at his highly improbable 185 mph (82.7 m/s he said). In his dreams.
Gravity waves. (You really mean gravitational waves.) In any case, you might first start with your understanding of the difference between a field and a wave. The subject of the possibility of gravity waves being emitted by mass would or would not fall into the fringe depending on why you think there is any reason to discount the mainstream view.
Markus Hanke said:What do you mean by "instantaneous effect" ? Perhaps I can help to clear this point up a little.
As I said curvature is not an "effect" of energy, curvature is energy, so it makes little sense asking for a mechanism or wonder about it being "instantaneous". Do you see the difference ?
quantum_wave said:Are you telling me that GR does not maintain that the curvature is felt instantaneously while the changes or interruptions to the motion of objects is time delayed. That was my misconception then.
http://www.sciforums.com/showthread...-s-mechanism&p=3063064&viewfull=1#post3063064
Markus Hanke said:Right, I misunderstood you; my impression was that you were talking about some "action" that needed to be performed by energy to curve space-time, and whether that was instantaneous.
Anyway, the above statement is of course correct; static fields are "felt" instantaneously, whereas changes in the field propagate at the speed of light. This of course makes sense, because a static field is just simply curved space-time; a body approaching such a field will follow the "contours" of that curved space-time, right there and then at every point it traverses. There is no exchange of information ( i.e. exchange of particles ) required for static fields.