McM anad Funkstar, I jmped in here as I have when I saw my handle mentioned, therefore I am responding to both of you motre particularly to Funkstrar.
MacM said:
Oh I see. HeHe. You do have some learning yet to do.
funkstar said:
“ Then you must have missed this gem:
“ Originally Posted by geistkiesel
In the experiment in the figure all time measurements are wrt the moving clocks.
”
funkstar said:
Which flatly contradicts the invariance principle. ”
MacM said:
How so? Careful I am baiting a trap.
funkstar said:
“ It explains specifically where he is wrong and why. ”
MacM said:
.
funkstar said:
“ Did you not see that I granted him an extra frame if he wanted it? ”
You granted him an extra frame. How nice. When this waltz is over then perhaps we can begin to take apart your view piece by piece.
funkstar said:
Because if the rod clocks read different times, then light has taken different rod time to cover the same distance in the rod frame. This directly contradicts the assumption of constancy of light speed in all frames! Is it somehow hard to grasp why? It's very basic, yet it seems to me that we're flogging the horse, here...
First, let me suggest, the rod frame is moving here, it isn't stationary, absolutely, it is moving, absolutely!
Mr Funkstar, you are missing a very interesting physical point, two of them actually. Let us assume for the moment that the frame is moving wrt the stationary frame, OK? At the instant the photons are emitted the test begins. The left photon, lp, is moving toward the oncoming L clock and travels a distance ct during which the physical frame has travelled a distance vt. The right phhoton has travellecd a distance ct to the right and is then a disatnce vt + vt from the right clock R. OK the photons have arrived at the clocks at different times.
That is one, above. Two: When the photons are emitted from the physical midpoint of L and R the physical frame moves away from the emission point, which is an invariant point in space. The photons both move with respect to the emission point, invariant in space and time, hence the velocity of the physical frame can also be measured from the common zero point.
How you might ask will the velocity be measured from this arrangement.
The SOL is the same in the emission point zero frame and as determined in
the physical frame, which is moving.
The following is a hypothetical. I am assuming that , in general, the physical frame will be in absolute motion wrt to any point of emission of a photon, which may be untruue, the frame may be at absolute rest. We shall see.
The rp moved a distance ct at the instant the lp has arrived at L after moving an initial distance ct wrt the emission point (only coincidentally also referenced in the Ve). The rp is located a distance of 2vt fromR here. In order to reach R the photon must cross the 2vt plus a tad more that the frame moves while the rp is crossing the 2vt distance, or:
ct' = 2vt + vt'
or t' = t (2v)/(c - v), which is incidentally the measured time difference between a moving and a stationary test. from this then we may calculate v as v = ct'/(2t + t'), so a t' = 0 means v = 0, a t' > 0 means v > 0.
Only if the frame were absolutely at rest would your statement that the photons covered the same rod distance in the same time be true; I anm suggesting you need much more than "theoretical truth" here.. The lp and rp covered the same distance alright, but not the same rod distance. How could photons cover the same rod distance if the frame is moving in the direction of R? Answer: it can't.
A vital point here mr. Funkstar, is that the supposed fact that a human observer "sees no physical frame motion" is scientifically and physically insignificant.
The only thing the observer on the physical frame is 1) the emission of the photons, and 2) the arrival times back at the physical midpoint simultaneously, with the times of the roundtrips embedded in the reflected signals from L and R,; or recovering the slips of paper, two of them, that have the arrival times swtamped on their surface when the photons arrive.
You are saying that the stationary erxperiment will be induistinguishable from obervers on the physically moving frame from the same arrangement with the frame stationary wrt Ve.
SRT negates the motion of the observer theoretically which is a corruption of the integrity of experimental physics ; "don't measure the relative velocity of frame and photon it is always c".
The relative velocity of the frame and photon is always either c + v , or c - v, both of which assume the constant velocity of the speed of light at least during the experiment under discussion. Neither c + v nor c - v physically adds or subtracts velocity of light. The expressions are an accounting of the velocity differences in frame and photon depebnding in the relative ditrection of motion of both.
I have contradicted the fundy of SRT, for sure, so has Mac M, QQ, even SL in a way. James R confirms the errors in SRT by being consistently unable to find specific flaws n the objections raised here. Chroot, a gunslingher from another forum, claiming the highest and most knowledgeable level of physics possible (greater even than Yuriy, who has taught me more about physics than he is aware of) has scorned the dissidents to SRT, but unfortunately he is unable to offer any physical laws, data, argument or whatever that successfully underminds thed dissident's objections. There are many more than one or two objections you know.
Good post Mr. Funkstar, you at least keep the discussion going in the proper direction and have minimized extraneous personal inferences intoyour posts.
Geistkiesel [/indent]