funkstar said:
Originally Posted by geistkiesel
No, I do not believe that the earth is siitting in a state of absolute velocity = zero rest. I say that in the measurement of light the motion of the earth does not insert errors that cannot be determined and therefore removed.
Sorry? Are you denying or affirming the invariance of c? Because if there are no error to be determined...
No the earth is not sitting in a state ovf zero motion and measurements can be made such that the errors introduced by the earth motion can be corrected for.
Assume the sun is dragging the solar system along with it at 208 km/sec.
With respect to what?
Some distant star with a measured v =0.
Geistkiesel said
Look at it like this. Virtually every inertial frame Vf that moves wrt the embankment, the earth, has accelerated wrt the embankment, Ve.
But where is the embankment? Is that at rest?
The embankment is the surface of the planet earth,
Geistkiesel said,
The Ve has never been observed to accelerate in the sense that Vf accelerates and produces a relative motion wrt Vf and Ve. Here, however, we know apriori, that it was the Vf that accelerated, not the Ve, therefore why pretend the silliness of asuming the Vf is ever at rest wrt Ve
I don't think anybody is claming that. Relative rest is rather dull.
They claim the passenger trains are at rest while the train stations are "seen"whizzing ion by. Where have you been lately?
SRT claims the equivalence of inertial frames and passenger train examples are sumerous claiming the train can "consider it self at rest wrt the emabnkment" a physically impssible condition to achieve.
Geistkeisel
Because you can move your pencil over the surface of a piece of paper and crunch out the 'theory' that the Vf, say a passenger train, could, once a relative motion wrt Ve is observed, ever be at rest and the Ve be moving with relative velocity VF (which must be the measured relative velocity.). This is physically impossible condition to achieve, and all the theory in the universe is not going to change that reality.
The frames are not equivalent. Ve and Vf, that is. Only Vf accelerates with rspect to Ve and you cannot come back a week after the acceleration event and say, "I've forgoptten all about my previous accelreated statethe fact taht I have moved, so I'll just assume SRT as the fix for the lapsed mermory.
Ok. Then where is the primordial embankment?
What the hell is a primordial embankment? Is this supposed to be a funny, or a serious question regarding the laws of physics?
Geistkiesel said
SRT preaching the mantra that the relative velocity of frame and photon will always measure C is sheer nonsense.
Ah, denying it. Then the onus is on you to find, say, a sub- or superluminal photon in a vacuum. And an explanation for gravitational lensing. Oh, and explain why relativistic effects need to be accounted for in GPS. And find the absolute rest frame. And an explanation for the precession of the perihelion of Mercury. And an explanation for the frame dragging effects recently confirmed. And explain why those atomic clocks don't match up.
funster said:
Common sense does not override reality.
Please define common sense. I bet that the common sense you have is the good stuff, right? The commn sense that you have, I mean, right??
A pair of photons emitted simultaneously from a point on a frame defines, a zero point reference for a perfect zero velocity FOR.
Geistkiesel said,
To assume this universally is to ignmore even the possibility of , or need to measure the relative velocity of frame and photon. This says that never in the development of human technology will there be a possibility to do what is claimed to be impossible.
Measuring the velocity of the frame and a photon is easy.
yes it is easy. Easier still is to measure the relative velocity of frame and photon as C + v or c - v depending on direction of the frame wrt the photon direction of motion.
Geistkiesel said,
...the relative velocity of frame and photon will always be measured at C..
.
The frame at c relative to some rest frame?!?
Well, one can use the velocity of the emitted photns to calibrate the velocity measure re teh phoiton trajectories which comprise the rfame proper.
Geistkiesel said,
Remember, the invariant location of the emission point of the photons.
This is just another way of saying "absolute space and time".
All I said was that the emission point was invariant, from any physiocal intervention, once the point is defined. Yes, it is another way to describe absolute space and time. After all, that is the way it is.
Geistkiesel said
Are you able to prove with certainty that the photons will arrive at L and R simultabneously ? Prove it I mean. Don't ask me what I believe, look at the problem and solve it. You are unable to do so without draggng cliched formulae from off the shelf, correct?.
First, if you use the "consideration" of the moving observer as a crucial condition in your conslusion you have failed.
In other words, if we don't accept absolute space and time we have failed. Sorry, no-can-do.James R's analysis, given the invariance of light speed, is perfectly correct: The rod clocks will show the same time when the photons hit. You may not believe that this is true for the real universe, but the thought example is unassailable.
Given the invariance of the SOL gives us absolute space and time. It is the measure of relative velocity of frame and photon that is mistaken by SRT. Look at the gedanken, the measurements of the SOL are wrt the invariant point of emission of two photons moving in opposite directions. Even one emitted photon defines a FOR: there is a zero point and a trajectory line both invariant spatially.
FYI the expression c- v is a measure of the difference in speeds of c and the frame, it is not a measurement of the SOL less than c. Also, c + V does not grant the SOL values > c it merely reflects the measured relative velocity of frame and photon moving in oppposite directions wrt each other. What is wrong with this?
.
No, if you deny that the emitted photons define an invariant point in space you have failed. If you cannot see that the trajectories of the emitted photons define an invariant straight line then you have failed. Someone told you to deny absolute space time reality under any reply or attack which is what you do with slavish obedienece. You fear even to hypothecise something anathemic to your SRT.
Geistkiesel said,
In the experiment in the figure all time measurements are wrt the moving clocks.
Sure, if space and time are absolute, and the point of emission is at rest (meaning fixed) in this frame.
The point of emission and the projected trajectory of the photons is the frame. Don't you get it yet?
What do you object to when the photons are emitted, that they aren't moving at the speed of c wrt the emission point? Is this what you are saying?
Geistkiesel said
There is symmetry in the ML and MR distances M being the midpoint of the L and R clocks. See if you can follow the logic of the development of the t' expression.
Ask yourself just one question. When the left photon has moved ct and arrived at L the right photon has moved an equal distance has it not? I am not asking about any frame motion here.
When thje left photon then reflects back to the emission point it has travelled another ct distance right? ALso the right photon has travelled ct. But the photons do not arrive at the L and R clocks at the same time because the fucking frame id moving.
I am not saying absorbed what I say is the truth, I say just analyze the problem wrt the photon motion motion
All this, with except for the moving clocks reading different times, is largely what the stationary observer sees.
So what that stationary observer sees it also. This cooincidental. Take the exeperiment to empty space and conduct the same experiment.
Geistkiesel said,
Assume the experiment has been run 10,000 times using the same relative velocity every time. Then the stationary observers can place clocks exactly at the locations of the L and R clocks when/where the photons arrive, correct? We can get the same results using stationary clocks even, but the difficulty you have is to argue away that two clocks colocated, one moving, the other stationary, (really stationary) will not record the arrival of the photons at the colocated positions simultaneously.
Go for it.
If time and space are absolute, then, of course, you're right. If you want us to show relativistic effects in a Newtonian universe, then, of course, we can't.
Are you saying that the "absolute space and time" words, that you brought up, recognizing the implications of what you were looking at is sufficient to distract you from a detailed analysis of the gedanken? because you haven]t done this have you? You cannot find an error in logic or phyiscs so you revert to cliche'd SRT. When you studied and accepted SRT you bought into a crock of shit and now personal pride refuses to allow you even the consideration that a smart cookie like yourself was hoodwinked, baited and reeled in by a smooth talking SRT prof,
If time and space are absolute, then, of course, you're right. If you want us to show relativistic effects in a Newtonian universe, then, of course, we can't.
But this universe does not appear to be Newtonian.
04-14-05 04:57 PM But this universe does not appear to be Newtonian.
The gedanken that you are responding to sure seems Newtonian doesn't it? You have found no holes in the specifics have you? What just is your problem with absolute space and time, these words aren't allowed in your club, are they?
The universe sure appears to be Newtonian to me.
Show us what you have and defeat the post here. Ths is
why you showed up in the first place isn't it?
Geistkiesel