Ha ha. Get banned.
Well, the experts have found that it can't be done. Try as you might, you can't mesaure light in a laboratory and work out your absolute speed - the result is always what you'd expect to get if Earth was at absolute rest.
What do you make of that?
MD, you said that you would leave the measurement of absolute velocity to the experts.
The experts have done the measurements using your proposed method, and always measured zero.
A basic rule of common sense is that if the map disagrees with the ground, the ground is rong.
In science, this means that if reality (ie real experiments) disagree with the theory, then the theory is wrong.
Reality disagrees with your concept of space and time. Your concept is wrong.
Really? Then how do you explain light travel time being different if measured from front to rear than rear to front?
So you don't believe in time dilation and length contraction, either?MotorDaddy said:Pete, your math will use time dilation and length contraction. Those only exist in Einstein's world. I don't live in Einstein's world, I live in reality.
So you don't believe in time dilation and length contraction, either?
MD, you have the greatest research tool in the world at your fingertips. Use it.
Experimental basis of Special Relativity
Why do you think you know what reality is when you haven't even looked?
Really? Then how do you explain light travel time being different if measured from front to rear than rear to front?
Dude, the distance light travels is determined by the length of the train. If the train has a constant length, then light travels the SAME distance; front to rear = rear to front.
The train's velocity is irrelevant. At least that's my explanation for "why the travel times are different", they AREN'T different, OK?
Of course, this is only true if you're an observer on the train; it isn't true for an external observer. I surmise that MD's confusion is related to his habit of making continual and arbitrary change of coordinates. You can't get away with that sort of carry-on, it just isn't scientific.
Why is the speed of the train "key", and to what?Tach said:This is textbook physics, the train speed is KEY, if you don't know it, you can always try learning it instead of posting stupid stuff.
Why is the speed of the train "key", and to what?
I think you're the one posting stupid stuff. But by all means, explain what the train's velocity has to do with the time it takes a beam of light to travel the length of the train. Go on, you know you want to.
Lost for words, are we?
Not doing very well with that "explanation" either, the one you can't provide because you haven't got a clue?
Dude, the distance light travels is determined by the length of the train. If the train has a constant length, then light travels the SAME distance; front to rear = rear to front.
The train's velocity is irrelevant. At least that's my explanation for "why the travel times are different", they AREN'T different, OK?
Of course, this is only true if you're an observer on the train; it isn't true for an external observer. I surmise that MD's confusion is related to his habit of making continual and arbitrary change of coordinates. You can't get away with that sort of carry-on, it just isn't scientific.
The observer on the train sees light take the same time to traverse the train in either direction, which is a consequence of light having a constant speed. He assumes the latter is true.phyti said:The times are different, but Einstein defined them for the inertial observer to be equal!
What this is about is forming a rigorous definition of time and more importantly, distance (as traveled by light), in fact identical distances if the A and B have zero relative velocity."We have not defined a common ``time'' for A and B, for the latter cannot be defined at all unless we establish by definition that the ``time'' required by light to travel from A to B equals the ``time'' it requires to travel from B to A. Let a ray of light start at the ``A time'' from A towards B, let it at the ``B time'' be reflected at B in the direction of A, and arrive again at A at the ``A time'' ."
The times are different, but Einstein defined them for the inertial observer to be equal!
"We have not defined a common ``time'' for A and B, for the latter cannot be defined at all unless we establish by definition that the ``time'' required by light to travel from A to B equals the ``time'' it requires to travel from B to A. Let a ray of light start at the ``A time'' from A towards B, let it at the ``B time'' be reflected at B in the direction of A, and arrive again at A at the ``A time'' ."
1905 paper, par 2.