The light has weight....

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victorespinoza

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The light has weight....

According to my research, the colors of a reflector of high power do not reach the clouds, this is because the color is attracted by gravity.

Very affectionate
Victor Elias Espinoza Guedez
July 28, 2011
 
The light has weight....

According to my research, the colors of a reflector of high power do not reach the clouds, this is because the color is attracted by gravity.

Very affectionate
Victor Elias Espinoza Guedez
July 28, 2011
Acc

My research has indicated that red light taste like cherrys and yellow light smells like lemons.

Snuggles,
Origin
a week ago next thursday
 
Why light produces waves, because it weighs. Let us remember that a wave produces a touch.
 
Light is indeed bent by a gravity field, so I suppose you could say it has weight. Even this would not be entirely correct, because the bending is due to the time-space distortion from gravity, but it behaves just like weight.

However, none of this can be observed on Earth. The bending resulting from the gravity of earth is undetectable; you need the gravity field of a star and astronomical distances to detect it.

Hans
 
The light has weight....

According to my research, the colors of a reflector of high power do not reach the clouds, this is because the color is attracted by gravity.

Very affectionate
Victor Elias Espinoza Guedez
July 28, 2011

i really reallly really hope for your sake you are just trolling and dont believe this..

ofcourse a reflector has weight it is an object therefor would be affected by gravity.. not the light passing thru that reflector doesnt and for your sake again i hope your just trolling :shrug:
 
Original Post is word salad, but the idea of light having weight is not so bad.

Equavlent weight of light? Light being photons is massless but does have energy.

So:

E=hv;E=energy, h= Plank's constant v=frequency of light. (Plank's formula for energy of a wave)
E=mc^2; m=mass, c=speed of light (Einestein's special relativity)
hv=mc^2; equate the two
m=(hv/c^2);solve for m
W=m/g;definion of weight, g=accelaration due to gravity of an object
W=(hv/c^2)/g ; equivalent weight light

Any comments?

Thanks
 
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Original Post is word salad, but the idea of light having weight is not so bad.

Equavlent weight of light? Light being photons is massless but does have energy.

So:

E=hv;E=energy, h= Plank's constantv=frequency of light. (Plank's formula for energy of a wave)
E=mc^2; m=mass, c=speed of light (Einestein's special relativity)
hv=mc^2; equate the two
m=(hv/c^2);solve for m
W=m/g;definion of weight, g=accelaration due to gravity of an object
W=(hv/c^2)/g ; equivalent weight light

Any comments?

Thanks

Wikipedia says that the photon has no energy.
 
According to my research, the colors of a reflector of high power do not reach the clouds, this is because the color is attracted by gravity.

So that's why the moon is black and white! The colors of the vegetation, oceans etc can't make it past the clouds, so all we see is a false image meant to hide the Moon's peoples from us. (And no wonder - most of the population is beautiful women who are attracted to people with funny ideas about science.)
 
Original Post is word salad, but the idea of light having weight is not so bad.

Equavlent weight of light? Light being photons is massless but does have energy.

So:

E=hv;E=energy, h= Plank's constant v=frequency of light. (Plank's formula for energy of a wave)
E=mc^2; m=mass, c=speed of light (Einestein's special relativity)
hv=mc^2; equate the two

This is a bad idea, $$E=mc^2$$ is not valid for the photon. The formula is the rest energy for massive particle. The photon does not exist at rest and has zero mass.

m=(hv/c^2);solve for m

You can't do this, see above.

W=m/g;definion of weight, g=accelaration due to gravity of an object
W=(hv/c^2)/g ; equivalent weight light

Any comments?

This is even worse.
 
If the photon does not weigh, why produces waves. Let us remember that a wave produces a touch.
 
This is a bad idea, $$E=mc^2$$ is not valid for the photon. The formula is the rest energy for massive particle. The photon does not exist at rest and has zero mass.

Thank you for your comement. I am aware that a photon is massless.

Electomagnatic radiation is deflected by gravity.

Why can't I use an "equivlent mass" term to explain apparent weigh?

:shrug:
 
This is a bad idea, $$E=mc^2$$ is not valid for the photon. The formula is the rest energy for massive particle. The photon does not exist at rest and has zero mass.

Thank you for your comement. I am aware that a photon is massless.

Then , you should be aware that you can't write $$hf=mc^2$$ as you attempted.

Electomagnatic radiation is deflected by gravity.

Yes, but not because "light has weight". The reason is that light follows geodesics.

Why can't I use an "equivlent mass" term to explain apparent weigh?

For the reasons explained above.
 
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