Question

D

dark

Registered Member
A singer has twice as many pants as pairs of shoes in her wardrobe, and three halves as many t-shirts as pants. What is the least number of items she can have in her wardrobe in order to make a different shoes, pants and t-shirt combination for each day of the year?
 
Find the minimum value for shoes that fits the following equation:

pants = 2 x shoes
t-shirts = 3 x shoes

shoes x pants x t-shirts >= 365
 
s x 2s x 3s >= 365

6s >= 365

s => 365/6

s => 60.833

61 = s

pants = 122
t-shirts = 183
366

Is 366 the least amount of clothing items needed?
Please correct what I did wrong if my answer was incorrect.

Thanks!
 
Last edited:
dark said:
s x 2s x 3s >= 365

6s >= 365
Click to expand...

s * 2s * 3s = 6s^3, not 6s.

So...

6s^3 >= 365 ... s^3 >= 61 ... so s >=4 (rounding up)

4 pairs shoes, 8 pairs pants, 12 t-shirts.

Now, does a pair of shoes count as 1 or 2 items? :confused:
 
You must log in or register to reply here.
Back
Top