Thanks again Kevinalm - I am beginning to get Bussard's idea. There seem to be three obvious concerns:
(1) As I understand it, some electrons are leaking out of the many cusps between the coils, but their loss may not be too bad as they can return along field line passing thru the coil centers. Most will just mirror back and forth inside along field lines as charged particles do in the Earth's ionosphere.
Unlike the ionospheric electrons which are following field lines with a radius of curvature greater than the Earth's radius (short segment of as 1000 meters are essentially straight) these Bussard elections will have high energy (needed to make the deep negative well) and a radius of curvature of a few meters. Now I am too lazy to see how cyclotron radiation scales with energy and radius of curvature, but seems to me that there is a good chance that electron with 150Kev (for the p/B reaction) whipping around the coils (or even just "mirroring" inside the interior between pairs of cusps will cool the system via cyclotron radiation. Wonder if they considered this?
(2) The multiple (fully probably) ionized boron B+++++ will fall down the well ok and climb up the other side, turn around and fall back down again.
The good part of this is they will be coming from all directions but not be entirely thermal in the center area where all the most energetic collisions can occur (Much better that trying to run a fusion reaction of less than 1% of them that happen to be in high energy tail of the Maxwellian distribution of a thermal plasma.)
The bad part of this is that they will be highly (or fully ionized) at the outer edges of the plasma with essentially zero energy as they turn around and be surround by electrons. Some of these electrons will be too fast for the B+++++ ions to capture. These fast electrons will have their trajectories bent by the 5 positive charges much more than when "scooting" by a single charge proton. I.e. this acceleration, 5 times greater will produce radiation at least 5 times greater. I think this alone will exceed the energy the reaction produces as even when only D & T are in the plasma and the energy is coming out in a neutral particle, there is significant energy loss via this unavoidable radiation.* (Not to mention the accumulating damage to the coils and especially the insulation between them.)
The slower electrons passing near an quasi stationary boron ion will just recombine with it radiating X-rays of various energies depending upon which level they drop into.
But captured or accelerated electrons are not the only source of radiative cooling. Few of the P on B collisions will be so well aligned (head-on) making fusion compare to 100s of times more strong collisions that that just scatter and again the B+++++ should make that radiation power at least 5 times greater. Of course if B and P (the proton) are in equal concentration (you want that for highest rate of reaction) then there are and even more B on B radiative scattering as their head-on collision ALL bounce 180 degrees as they lack the energy to fuse (approach within the strong force range) If he does get some fusion, then each produces three energetic alphas to bang into boron and protons and make huge accelerations of those charged particles - more radiation losses (but I doubt we need worry about this
)
(3) It will be impossible to keep the plasma free of the "out gassing" molecules (especially in the intense X-ray and flux hitting the wall of vacuum chamber as electrons are captured into the inner atomic shell of B+++++ making it into a B++++ ion etc.) Once these atoms (typically Carbon, Oxygen and Nitrogen, perhaps a little Cl or F from the plastics of coil insulations) get in to the energetic plasma it will cool quickly by this high energy continuum radiation (Mostly X-rays but even some lower energy harsh UV -perhaps even some short wave length visible line as part of the recombination of the electron lowering the degree of ionization will cascade down the many high principle quantum numbers instead of be directly captured into a deep atomic shell of the B+++++ etc.
I am just guessing and drawing on old memory* but think that Bussard's machine will at best be an alternative source of radiation not energy. I.e. it will never get to the state of fully ionized plasma in a 150Kev deep well because of the high power radiation (Photons, not radioactivity) it will produce in the effort to get there.
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*As I recall in the old Princeton "stellarator" they were stopped by the radiation losses well before getting to even D/T reaction temperature by the fact that the vacuum systems was not good enough - too many multiple charged ions in the plasma. At Princeton, as I recall, they finally got these vacuum system impurity atoms radiation losses down by modifying the magnetic field so that the outer flux line went out into something called a "diverter" with liquid nitrogen cold traps to freeze out the unwanted ions that were radiating away all the energy as fast as they could put it in. (Effectively they "çaught" the atoms out gassing from the chamber walls as soon as they became ions - I.e. while still in the outer "skin" of the confining magnetic field and led them out into the "diverter's cold traps.)
Unbelievable (for me at least) is that Bussard wants 50% his plasma to be these multiple-charged radiating atoms!
Thus,
I predict it will, at best, be one expensive X-ray light bulb.
Put me down as "very skeptical". Has no one done these radiation calculations? To put it very crudely, but clearly, it seems to me he wants to fill a bucket, which as large hole in the bottom (the radiation), by pissing in it with a small steam of energy flow (the injected electrons).
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*Not only is the "unavoidable" radiation at least 5 times less, the fusion cross section is greater and the energy release per fusion is several times gfreater also - so in the DT reaction the unavoidable radiation is sustainable. I strongly doubt it is in The PB reaction as all three factors are stacked against it -by my crude estimate: 5x5x5 = or > 125 I.e. Bussard is at least 125 times worse off.