sounds like to me you're backpedaling from pretending to know, because you are embarrassed from the pretending and got caught.
and yet, here you are. responding with a manipulative backpedaling post. sound like you care to me. i find your nonsense just as hilarious. all you do is just click on links and reiterate them towards others. this is just as much as a joke.Thanks for the laugh. It sounds like you think I care what anyone here, thinks about me.
Did you want links to definitions and the words used in a couple of Goggle searches?
You are yourself hilarious!
Farsight, you are either stupid, or have some evil agenda. What Einstein is saying in your reference is exactly what PhysBang and I have been saying. The equivalence of acceleration and gravitation holds only locally in Einstein's spacetime manifold Notice the "in its entirety" qualification. This indicates that E. is accepting that there exists no global coordinate system for which there exists a coordinate transformation that "cancels" gravitation globally, unlike acceleration which is defined relative to a globally defined Minkowski space (globally defined means "flat" in this context)
Sorry Billy. I'll try again:Thanks, but that was not my question at end of post 238.
Yes. Or at least it ought to be, because "the time" is merely a measure of local motion. And d is distance: motion traverses a distance. Like Quarkhead conceded the other day, there's no motion in spacetime. It's an abstract "arena", a block-universe that is absolutely static. You can draw worldlines in it, and you can use it to work out spacetime intervals and other things. But we do not live in spacetime, the map is not the territory. Ours is a world of space and motion. Whether that motion is through space, or within the thing we call a clock.I'm not fully following your math /understanding your point, but it seems to me you may be more formally saying what I have said. I.e. that objects have a trajectory in space time and for any one inertial reference frame, one can consider it a path in 3D (x,y,z) space with time parameter "t" marked along the 3D path to specify particular points by (x,y,x,t) in a 4D or spacetime coordinate system. I have noted that instead of "t" which is regular seconds intervals (and sub-division), you could, for example, mark the 3D path with parameter "d" where d is also regular intervals (and subdivisions) of some constant distance (say in cm) along the path, just like "t" was constant intervals of time along the path. If the object is not accelerating, then the "d" and "t" parameter marking systems are identical, but not so if the object is accelerating. Is this basically what your more formal math is telling us? Or something quite different?
Sorry Billy. I'll try again:
Yes. Or at least it ought to be, because "the time" is merely a measure of local motion. And d is distance: motion traverses a distance. Like Quarkhead conceded the other day, there's no motion in spacetime. It's an abstract "arena", a block-universe that is absolutely static. You can draw worldlines in it, and you can use it to work out spacetime intervals and other things. But we do not live in spacetime, the map is not the territory. Ours is a world of space and motion. Whether that motion is through space, or within the thing we call a clock.
OK, so can you show us, using your map with distance and no time, how to do a physics problem? Because otherwise you have no map at all. Or is this another physics question you will dodge?Sorry Billy. I'll try again:
Yes. Or at least it ought to be, because "the time" is merely a measure of local motion. And d is distance: motion traverses a distance. Like Quarkhead conceded the other day, there's no motion in spacetime. It's an abstract "arena", a block-universe that is absolutely static. You can draw worldlines in it, and you can use it to work out spacetime intervals and other things. But we do not live in spacetime, the map is not the territory. Ours is a world of space and motion. Whether that motion is through space, or within the thing we call a clock.
No. What does "flat-but-titled" mean? If you respond, as I expect you to, that it refers to a Minkowski space with the diag{1. 1, 1, -1} metric, where the light cone "rotates" as it follows a spacetime geodesic, then you immediately find a contradiction.And do you now understand the difference between 1) flat-and-level 2) flat-but-tilted and 3) curved yet?
There's no contradiction if you remember that a light cone is an abstract thing that doesn't actually exist. See this Stanford article for a mention of the tilted light cones, but better still take a look at a depiction of Riemann curvature:No. What does "flat-but-tilted" mean? If you respond, as I expect you to, that it refers to a Minkowski space with the diag{1. 1, 1, -1} metric, where the light cone "rotates" as it follows a spacetime geodesic, then you immediately find a contradiction.
There's no problem with that. Look at the plot again, or better still look at a bigger "rubber sheet" depiction like this one. Look at the bottom centre. There's a small region in the middle where spacetime is flat and level. If there was no curvature, the entire plot would stay that way. You need the curvature to get off the flat and level. But light doesn't curve because "the spacetime in the room you're in is curved". It curves because "the spacetime in the room you're in is tilted".Surely even you can see this? According to your god, according to me, according to any sane mathematician/physicist there exist 2 and only 2 options. Spacetime is globally flat ($$R_{jk} =0$$) or it is not.
PhysBang is a troll. And you're still having trouble understanding gravity, because you confuse mathematical abstraction for physics reality. You now know that there is no motion in spacetime. You now know that light doesn't move through spacetime. So you now know that the real reason light curves is because space is inhomogeneous, just like Einstein said. Such that the speed of light is spatially variable.Quarkhead said:As I and PhysBang have wasted too much time trying to explain to you, that locally flat (in this context) does NOT imply "globally flat". It is elementary differential geometry
"Experiments continue to show that there is no 'space' that stands apart from space-time itself...no arena in which matter, energy and gravity operate which is not affected by matter, energy and gravity. General relativity tells us that what we call space is just another feature of the gravitational field of the universe, so space and space-time can and do not exist apart from the matter and energy that creates the gravitational field. This is not speculation, but sound observation."
https://einstein.stanford.edu/content/relativity/a11332.html
OK, we are getting an admission out of Farsight that "tilted spacetime" is just "curved spacetime", so at least that's progress.There's no contradiction if you remember that a light cone is an abstract thing that doesn't actually exist. See this Stanford article for a mention of the tilted light cones, but better still take a look at a depiction of Riemann curvature:
Not all spacetime curvature relates to "tidal force" and the difference in gravity across a finite region (i.e, tidal difference) is not the cause of gravitational time dilation, it's the absolute effect of gravity.Imagine you placed light-clocks throughout an equatorial slice of space, then plotted the clock rates. The curvature you can see on the plot depicts spacetime curvature which relates to tidal force.
Notice here that Farsight is using specific mathematical terms, even though he refuses to learn or use mathematics. If anyone doubts that, merely ask Farsight to show the mathematics that represent his idea and, eventually, you will see him write about the evils of mathematics.But the force of gravity at any location depends on the gradient at that location. The spacetime "tilt". The first derivative of potential, not the second.
Note that this is an imaginary plot that nobody can look at. Farsight wants us to ignore how actual plots might look (NB: if we did the plot as he suggests, we wouldn't see a difference in the plots) and he is simply going to substitute his own ideas for any observational evidence. This is because Farsight hates observational evidence and would rather substitute his own "understanding" in place of physics that can produce results.There's no problem with that. Look at the plot again,
He says this, but never produces influence.or better still look at a bigger "rubber sheet" depiction like this one. Look at the bottom centre. There's a small region in the middle where spacetime is flat and level. If there was no curvature, the entire plot would stay that way. You need the curvature to get off the flat and level. But light doesn't curve because "the spacetime in the room you're in is curved". It curves because "the spacetime in the room you're in is tilted".
Farsight is great at insulting people when he can't answer their questions. If you want Farsight to insult you, simply ask him a simple question about the mathematics behind his ideas. Or ask him to show you how his ideas on photons making everything can reproduce the spin that he talks about so much.PhysBang is a troll.
See, there you go: Farsight hates math, even though he makes mathematical claims all over the place.And you're still having trouble understanding gravity, because you confuse mathematical abstraction for physics reality.
People likely haven't got this because Farsight, despite being asked for years, has never been able to show how to do the simplest gravity application with inhomogeneous space. Not one. You would think that a "physics expert" could do even a little physics, even that of his own choice. But, no.You now know that there is no motion in spacetime. You now know that light doesn't move through spacetime. So you now know that the real reason light curves is because space is inhomogeneous, just like Einstein said. Such that the speed of light is spatially variable.
Have you got that yet?
OK, big boy, try thisThere's no contradiction
Force of gravity? What is that? Haven't you repeatedly referred to the article where John Baez says gravity is not a force? And gradient of what? Gravitational potential? If so, in all theories of gravitation, the potential (recall that in GR the potential is encoded in the metric tensor) the important operator is the divergence of the gradient - the so-called Laplacian operator in Newtonian theory, which is a second order differential operator acting on a scalar field of potentials. In the Newton-Poisson formulation this has the nice property that it satisfies the Laplace Equation in the presence of a field but in the absence of matter i.e $$\nabla^2 \phi =0$$. But the force of gravity at any location depends on the gradient at that location. The spacetime "tilt".
So this is wrongThe first derivative of potential, not the second.
Your pathetic attempts to patronize me (or anyone else that has studied differential geometry) are doomed unless you can do the mathematics - in spite of you poo-pooing mathematics, as PhysBang and others have rightly said your silly analogies and kindergarten pictures are woefully inaccuratesHave you got that yet?
Take your time thinking about the answer Fartsightif by "state of space" he means it is a property of "spatial space" why does he need 10 functions? Surely, in its matrix representation a metris defined on only 3 coordinates is a 3 x 3 matrix, i.e. a maximum of 9 functions. (I know the answer, so don't try to flannel)
There's no contradiction if you remember that a light cone is an abstract thing that doesn't actually exist. See this Stanford article for a mention of the tilted light cones, but better still take a look at a depiction of Riemann curvature:
There's no problem with that. Look at the plot again, or better still look at a bigger "rubber sheet" depiction like this one. Look at the bottom centre. There's a small region in the middle where spacetime is flat and level. If there was no curvature, the entire plot would stay that way. You need the curvature to get off the flat and level. But light doesn't curve because "the spacetime in the room you're in is curved". It curves because "the spacetime in the room you're in is tilted".
PhysBang is a troll. And you're still having trouble understanding gravity, because you confuse mathematical abstraction for physics reality. You now know that there is no motion in spacetime. You now know that light doesn't move through spacetime. So you now know that the real reason light curves is because space is inhomogeneous, just like Einstein said. Such that the speed of light is spatially variable.
Have you got that yet?
OK. Light goes straight. Parallel lines don't meet. Et cetera.OK, big boy, try this. In flat spacetime, all geodesics are what, in ordinary parlance, we would call "straight lines"
Yep.Otherwise they are "curves"
True. You will be aware that I am not enamoured of this sort space/time switching inside black holes. And that I will point out that a light cone is an abstract thing. I cannot point up to the clear night sky and say look, there's a light cone! So what's your point?Every geodesic is entitled to a tangent vector at every point. So if you "tilt" the light-cone as you "move" it along a straight-line geodesic you ru the risk of converting space-like vector into a time-like vector. Not good.
But there is no light cone. And there is no worldline. And no spacetime. And no coordinate system, and no metric. They're all abstract things. Space and energy and motion aren't. What's your point?Conversely, if you wish to avoid the same thing happening on a curved geodesic, you are obliged to "tilt" the light-cone
Yes we all know about that. Gravity is not a force in the Newtonian sense, but people talk about the force of gravity. They also talk about g and 9.8m/s². Quit carping and make your point.Force of gravity? What is that? Haven't you repeatedly referred to the article where John Baez says gravity is not a force?
And?And gradient of what? Gravitational potential? If so, in all theories of gravitation, the potential (recall that in GR the potential is encoded in the metric tensor) the important operator is the divergence of the gradient - the so-called Laplacian operator in Newtonian theory, which is a second order differential operator acting on a scalar field of potentials. In the Newton-Poisson formulation this has the nice property that it satisfies the Laplace Equation in the presence of a field but in the absence of matter i.e $$\nabla^2 \phi =0$$
It isn't wrong. Go and check your facts. Here's something for you: According to Eq. (8.5) tidal forces are second derivatives of the gravitational potential.In GR, where the potential $$\phi$$ is replaced by the metric tensor $$g_{jk}$$, the divergence of the gradient is given by $$R_{jk}-\frac{1}{2}R$$ and the first term (curvature tensor) is first order in the connection which in turn is second order in the metric (the potential). Since these 2 sets of differential equations are defined with respect to different quantities, one can see that curvature is second order in the metric (the potential)
The first derivative of potential, not the second.
So this is wrong
You start with 4 x 4 spacetime terms, but reduce it to 10 because the metric is symmetric. Space and time are involved because you measure the "metric properties" of space using rods and clocks. At the fundamental level both employ the motion of light. For example you place light clocks throughout an equatorial slice of space, then plot the clock rates to depict Riemann curvature.Regarding your Einstein quote - the state of "empty space" is given by the 10 functions $$g_{jk}$$ - please answer this question......
if by "state of space" he means it is a property of "spatial space" why does he need 10 functions? Surely, in its matrix representation a metric defined on only 3 coordinates is a 3 x 3 matrix, i.e. a maximum of 9 functions. (I know the answer, so don't try to flannel)
Have you understood what I've told you yet? Your pencil doesn't fall down because the spacetime in the room you're in is curved. And it doesn't fall down because the space in the room you're in is curved, see Baez about that. Instead it falls down because....Your pathetic attempts to patronize me (or anyone else that has studied differential geometry) are doomed unless you can do the mathematics - in spite of you poo-pooing mathematics, as PhysBang and others have rightly said your silly analogies and kindergarten pictures are woefully inaccurate.
No it doesn't. And you will not find Einstein saying that. Nor Quarkhead any more, because he now knows that spacetime is a static abstraction, and that light does not move through it. He now knows that light moves through space....Light/photons follow geodesics in curved spacetime. That is GR and to deny that is to deny GR and the great man who you so often misquote....
What's been shown here is that my physics knowledge far surpasses Quarkhead's, who reacts with feather-spitting outrage. As for elsewhere, people like him are "moderators" elsewhere.paddoboy said:...As has been shown here, and in your total bannings elsewhere...
But there is no light cone. And there is no worldline. And no spacetime. And no coordinate system, and no metric. They're all abstract things. Space and energy and motion aren't. What's your point?
So metrics both don't exist and space has "metrical properties" that form the foundation of Einstein's work, including "inhomogeneous space". Yet whenever anyone asks Farsight to use these metrics to show us how the physics works, Farsight can't do it.You start with 4 x 4 spacetime terms, but reduce it to 10 because the metric is symmetric. Space and time are involved because you measure the "metric properties" of space using rods and clocks. At the fundamental level both employ the motion of light. For example you place light clocks throughout an equatorial slice of space, then plot the clock rates to depict Riemann curvature.
Here is where Farsight always stops, because he can't explain why a pencil falls down!Have you understood what I've told you yet? Your pencil doesn't fall down because the spacetime in the room you're in is curved. And it doesn't fall down because the space in the room you're in is curved, see Baez about that. Instead it falls down because....
Really? Because the beginning of chapter 4 of "The Meaning of Relativity" has this quotation from Einstein:No it doesn't. And you will not find Einstein saying that. Nor Quarkhead any more, because he now knows that spacetime is a static abstraction, and that light does not move through it. He now knows that light moves through space.
Sure, if we define "physics" to be the contents of Farsight's fantasies without regard for the work of scientists or what one can observe, then Farsight is by far the expert.What's been shown here is that my physics knowledge far surpasses Quarkhead's, who reacts with feather-spitting outrage. As for elsewhere, people like him are "moderators" elsewhere.