As I understand it, for a particle (or a person) travelling @ "c" time does no longer exist and everything stands still relative to the "c" (Einstein?).
Not Einstein. That would be Minkowski, and his mistake of equivocating the speed of light to the basis of time. He didn't know there might be something "faster" / "slower" that was actually the basis of time, and that it was not proportional to any velocity, the speed of light inclusive.
The estimates currently range from a minimum of 10,000 x c. I'm holding out for c^2, but it may be a while before that idea can be tested.
Is it possible that relativity does not hold @ "c" ?
It holds, just not the way Minkowski imagined it. Time dilation works just like the Lorentz transformation he adopted, BUT THERE IS A RESIDUAL amount of passage of time that remains, even for a photon.
If a photon is circularly polarized (possessing a type of quantum spin), it doesn't stop being circularly polarized, or propagating by means of time varying electric and magnetic field vectors in space along its Poynting vector, just because Minkowski decided nothing was "faster" / "slower" than the propagation of light.
Comes to mind the person running up an escalator which moves @ "c" does not get to the top any faster than if he were standing still.
Yes, this is still true. The speed of light doesn't stop being invariant just because entanglement is "faster" / "slower".
"Our dimension" necessarily experiences time as a duration of an event.
But how can a "timeless dimension" be measured as experiencing duration of an event ?
Never equivocate an instant of time with a time interval. An instant of time may turn out to actually have duration, but since nothing else is "faster"/"slower", we'll never have anything else to compare that instant to.
After the instant of 'now', which is only the absolute origin of time everywhere in the universe, time proceeds at different rates (lengths of time intervals) based on relative velocity, proximity to gravitational fields, etc.
Question 1; If we eliminate human observation (and measurement, does time exist for two entangled particles travelling @ "c" ?
Yes. Conservation of mass/energy (E=mc^2) is what assures us this is true, and this only works if there is both time and inertia (energy).
Quantum physics was formerly incompatible with relativity because relativity excluded entanglement. Because there were too many divide by zeros, quantum physics opted to substitute unitarity for time for the last 50 years. Here we have mended time in relativity so that it can be used again in quantum physics.
Bound energy persists in time only because entanglement is the instantaneous force that actually binds them into matter, antimatter (due to hansda's analysis). Before it was realized by hansda that Newton's laws could be applied to entanglement with a crack left in the door for entanglement simultanaeity as the basis of time for instantaneous force / inertia / acceleration, I had no clue this analysis might be possible.
Unbound energy propagating in space persist in time while propagating because entangled particles produced the photon(s) to begin with, and all of the quantum field permeating the universe is entangled with itself.
Question 2; If time does not exists when travelling @ "c", why should an entangled pair be required to recognize distance (a measurement of distance/time) at all ?
Time DOES still exist when a pair of entangled photons are traveling at c.
And you here you have won the prize for the best question about entanglement posted in the entire thread.