Chinglu said:You can find here that the circular path and the linear velocity is sufficient to calculate the sagnac. Angular velocity is not necessary.
Please note, for the 5th and final time, that rotation equals acceleration. The apparatus is unaccelerated == the apparatus is not rotating. At this point I'm giving up; I wish you the best of luck with the pursuit of your MMX/GPS "contradiction", maybe you've uncovered a grand conspiracy?? With such an amazing ability to interpret explanations as they are spoon-fed to you I'm sure you'll go far in the Physics world. Anyway, I'm unsubscribing from this thread...Chinglu's Mathpages link said:Just as in the case of the circular loop, if the apparatus is unaccelerated, the two beams will travel equal distances around the loop, and arrive at the detector simultaneously and in phase. However, if the entire device (including source and detector) is rotating, the beam traveling around the loop in the direction of rotation will have farther to go than the beam traveling counter to the direction of rotation, because during the period of travel the mirrors and detector will all move (slightly) toward the counter-rotating beam and away from the co-rotating beam.