1]
Shown in this diagram below is a light source, in this case a single star surrounded by it's photon light field as suggested by the speckling.
Of course we can not normally see a photon that hasn't impacted on matter so your imagination is required to assume the speckle as the location of photons that are impacting upon objects of imaginary matter. You will also have to imagine that the photons are all travelling outward from the source at the rate of 'c'.
It can be reasoned that every speckle of photon light is occurring at the same simultaneous moment. Regardless of location all objects of matter placed in this field will record the light event simultaneously.
As time progresses all photons change their location according to their speed of 'c'. All do so simultaneously so that no matter when you take your snap shot, although time has passed the Hyper Surface of the present is still constant universally
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2]
This time we have included 6 observers labeled A, B, C, D, E and F in the image below:
Their relative velocity to each other and to the light source at this stage is not important but can be assumed as zero.
Distance from the light source is also unimportant, however what is important is to clearly understand that regardless of distance or velocity of the observers relative to each other and the light source, the photons that are impacting on those observers must do so simultaneously for all observers.
As all photon events in the light field are occuring simultaneously then all observers must observe that effect simultaneously.
You will notice a clock is included in the image and note that regardless of where the hands are pointing t=t[SUB]hsp[/SUB] for all points in the light field.
Extrapolate this fact to every part of this universe [ normal space ] and it can be seen that t=t[SUB]hsp[/SUB] or the NOW is simultaneous for all observers.
If all observers where in fact stationary relative to each other and the light source then the passage of time regardless of the metric used would be at the same rate for all observers.
However in reality most observers are moving at relative velocity and accordingly their time passage rates are relative yet always maintaining simultaneity of the t=t[sub]hsp[/sub] or "NOW.
btw "religious style" arguement will not be accepted.
If the logic is not understood then I will be more than happy to explain further
Simlpy deal with the logic presented and we might very well achieve something.
Shown in this diagram below is a light source, in this case a single star surrounded by it's photon light field as suggested by the speckling.
[constructed image c/o photo shop software]
Of course we can not normally see a photon that hasn't impacted on matter so your imagination is required to assume the speckle as the location of photons that are impacting upon objects of imaginary matter. You will also have to imagine that the photons are all travelling outward from the source at the rate of 'c'.
It can be reasoned that every speckle of photon light is occurring at the same simultaneous moment. Regardless of location all objects of matter placed in this field will record the light event simultaneously.
As time progresses all photons change their location according to their speed of 'c'. All do so simultaneously so that no matter when you take your snap shot, although time has passed the Hyper Surface of the present is still constant universally
--------------
2]
This time we have included 6 observers labeled A, B, C, D, E and F in the image below:
[constructed image c/o photo shop software]
Their relative velocity to each other and to the light source at this stage is not important but can be assumed as zero.
Distance from the light source is also unimportant, however what is important is to clearly understand that regardless of distance or velocity of the observers relative to each other and the light source, the photons that are impacting on those observers must do so simultaneously for all observers.
As all photon events in the light field are occuring simultaneously then all observers must observe that effect simultaneously.
You will notice a clock is included in the image and note that regardless of where the hands are pointing t=t[SUB]hsp[/SUB] for all points in the light field.
Extrapolate this fact to every part of this universe [ normal space ] and it can be seen that t=t[SUB]hsp[/SUB] or the NOW is simultaneous for all observers.
If all observers where in fact stationary relative to each other and the light source then the passage of time regardless of the metric used would be at the same rate for all observers.
However in reality most observers are moving at relative velocity and accordingly their time passage rates are relative yet always maintaining simultaneity of the t=t[sub]hsp[/sub] or "NOW.
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Care to discuss?btw "religious style" arguement will not be accepted.
If the logic is not understood then I will be more than happy to explain further
Simlpy deal with the logic presented and we might very well achieve something.