Entropy:A concept that is not Physical Quantity
shufeng-zhang China
Email: uhsgnahz@126.com
This paper demonstrate entropy is not a physical quantity.
We define heat engine efficiency η as: η= W/W1, that is, replacing Q1 in the original definition η=W/Q1 with W1, W still is the net work of the heat engine applied to the outside in one cycle, W1 is the work the heat engine applied to the outside in the cycle, then, we use Stirling cycle as the element reversible cycle , if ∮dQ/T =0 is tenable, we can prove ∮dW/T =0 and ∮dE/T =0.
If the formula ∮dQ/T=0, ∮dW/T=0 and ∮dE/T=0 can really define new system state variables, it comes to the absurd result of such a definition.
In fact, during the process of obtaining “entropy”, ∑[(ΔQ)/T)] become∫dQ/T is untenable, therefore, the formula ∮dQ/T=0, ∮dW/T=0 and ∮dE/T=0 are untenable.
The“entropy”defined by Boltzmann is used to interpret “entropy” by Clausius, so, it is at the same time denied.
(The whole paper Google : "Entropy:A concept that is not Physical Quantity yudu")
shufeng-zhang China
Email: uhsgnahz@126.com
This paper demonstrate entropy is not a physical quantity.
We define heat engine efficiency η as: η= W/W1, that is, replacing Q1 in the original definition η=W/Q1 with W1, W still is the net work of the heat engine applied to the outside in one cycle, W1 is the work the heat engine applied to the outside in the cycle, then, we use Stirling cycle as the element reversible cycle , if ∮dQ/T =0 is tenable, we can prove ∮dW/T =0 and ∮dE/T =0.
If the formula ∮dQ/T=0, ∮dW/T=0 and ∮dE/T=0 can really define new system state variables, it comes to the absurd result of such a definition.
In fact, during the process of obtaining “entropy”, ∑[(ΔQ)/T)] become∫dQ/T is untenable, therefore, the formula ∮dQ/T=0, ∮dW/T=0 and ∮dE/T=0 are untenable.
The“entropy”defined by Boltzmann is used to interpret “entropy” by Clausius, so, it is at the same time denied.
(The whole paper Google : "Entropy:A concept that is not Physical Quantity yudu")
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