It seems to me that the hidden dimensions, curled into very tight spaces, are in fact perfect micro-chambers, to contain the idea I had in mind concerning the gravitational field’s need for the presence of dark matter; I propose that it doesn’t. Instead of saying that the mysterious matter is the extra source, created mathematically by scientists to answer for the gravitational source of the universe, saying that it might be stuck inside the hidden dimensions of spacetime. But why should it be this exotic substance? Why can’t it just be something we are struggling with at the moment already? Like a diluted sea of microscopic extremal black holes?
An extremal black hole will have a ground state of mass that is proportional to its charge and angular momentum. This means that the black hole will either radiate particle pairs at a much slower rate, or they won’t emit the particles at all. The following equation describes the curvature of spacetime round a massive spherical body;
ds^2=-c^2(1-2GM/c^2r)dt^2+(1-2GM/c^2)^-1_dr^2+r^2d^2
The curvature produced by this weak sea of black holes i predict would sufficient to stabilize the gravitational forces needed. Black holes are predicted to form from the collapsed states of certain large stars, about several times larger than our star. They do so, because of gravitational acceleration, given by the formula;
a=(GM_ ß)/d^2=mg
Remember, a free falling object will have the force of gravity totally cancelled out as it’s that weak. We know that from Newton’s Force Equation is derived as f= ma, where this also shows an inertial system to derive the acceleration due to gravity, and thus;
g=(GM)/d^2
So the gravitational acceleration is the mass of a gravitationally warped object M, and the distance d from it. Also, instead of working out the mass of a black hole in the conventional way, you could measure it against the gravitational acceleration formula, by;
M=gd^2/G
We use the same method to work out the mass of the earth. The G is Newtons universal gravitational constant (6.7×10-11 m3/(kg sec2). We find the Earth's mass = 9.8 × (6.4×106)2 / (6.7 × 10-11) kilograms = 6.0 × 1024 kilograms. To make an accurate measure of the gravitation being produced in the hidden dimension, we would need to take the content of the proposed dark matter, which is about 25% of matter in the universe (as predicted by NASA), and spread that out in a uniformal distribution throughout the dimension, take the gravitational affects of the black holes, but we are dealing here with very small calculations for each extremal black hole. We would need to work out how many of these micro black holes would be needed, and if they represent particles, then the sea of black holes would have a finite number of particles consistent.
The gravitational acceleration, is then simply given as g=(GM)/d^2, and calculating the mass is gd^2/G.
To take into account the mass of this black hole sea, we can estimate the amount of matte required, proportional to the what the theory predicts. Dark matter coves 25% of all matter, so, in theory the same amount of matter would be needed to make up the gravity needed in the sea. Even just as important, we would need to scale the density D of the universe, against the radius 10^26, and measure how diluted this matter really is. We can measure the density, and radius of a black hole in a series of proportionalities. The radius R of a black hole, even a micro black hole is directly proportional to its mass (R- M). And the density of a black hole is found to be given by its mass divided by its volume (D=M/V).
I work out that there will be something like 10^9 particles that make up the black hole sea. This would mean that there is about a billion more particles making this sea, than there is the normal baryons found in matter. Neutrinos might be so lightweight that they can travel between dimensions. They would also naturally form under the relativistic effects on the energy deposition rate via neutrino pair annihilation near the rotation axis of a black hole normally, but here we are talking about a Kerr black hole. And also, these black holes won’t radiate photons or neutrinos. They’re stable radiatively.
Electron neutrinos or even antineutrinos are generated whenever neutrons change into protons or protons into neutrons, the two forms of beta decay. As we already know, about 50 trillion neutrinos pass through our bodies in just under one second! They originally came from sun. They are a gravitational king for this matter, and are themselves classed as being a form of dark matter. A source of frame-dragging at a very small scale would radiate from this sea of black holes. The black holes will spin at the speed of light, just like macroscopic black holes. The Centripetal force is proportional to the centrifugal force (F=mrW^2).
A black hole need to be of Planck Mass at smallest size 2x10^-8kg. The Compton Wavelength given as lambda=h/mc=2pi(h/mc) of a black hole is proportional to its Schwartzchild Radius 1 / (2M − r); very small black holes are very hot. This is because the decrease in size and magnification of density makes these little things extremely hot. A typical micro black hole would have a temperature of 10^16 K, which is 200 GeV.
Might the curvature produced from the extremal black holes be seeping into the other dimensions, producing the gravitation thought to be answered through the use of Dark Matter?
Reiku :m:
An extremal black hole will have a ground state of mass that is proportional to its charge and angular momentum. This means that the black hole will either radiate particle pairs at a much slower rate, or they won’t emit the particles at all. The following equation describes the curvature of spacetime round a massive spherical body;
ds^2=-c^2(1-2GM/c^2r)dt^2+(1-2GM/c^2)^-1_dr^2+r^2d^2
The curvature produced by this weak sea of black holes i predict would sufficient to stabilize the gravitational forces needed. Black holes are predicted to form from the collapsed states of certain large stars, about several times larger than our star. They do so, because of gravitational acceleration, given by the formula;
a=(GM_ ß)/d^2=mg
Remember, a free falling object will have the force of gravity totally cancelled out as it’s that weak. We know that from Newton’s Force Equation is derived as f= ma, where this also shows an inertial system to derive the acceleration due to gravity, and thus;
g=(GM)/d^2
So the gravitational acceleration is the mass of a gravitationally warped object M, and the distance d from it. Also, instead of working out the mass of a black hole in the conventional way, you could measure it against the gravitational acceleration formula, by;
M=gd^2/G
We use the same method to work out the mass of the earth. The G is Newtons universal gravitational constant (6.7×10-11 m3/(kg sec2). We find the Earth's mass = 9.8 × (6.4×106)2 / (6.7 × 10-11) kilograms = 6.0 × 1024 kilograms. To make an accurate measure of the gravitation being produced in the hidden dimension, we would need to take the content of the proposed dark matter, which is about 25% of matter in the universe (as predicted by NASA), and spread that out in a uniformal distribution throughout the dimension, take the gravitational affects of the black holes, but we are dealing here with very small calculations for each extremal black hole. We would need to work out how many of these micro black holes would be needed, and if they represent particles, then the sea of black holes would have a finite number of particles consistent.
The gravitational acceleration, is then simply given as g=(GM)/d^2, and calculating the mass is gd^2/G.
To take into account the mass of this black hole sea, we can estimate the amount of matte required, proportional to the what the theory predicts. Dark matter coves 25% of all matter, so, in theory the same amount of matter would be needed to make up the gravity needed in the sea. Even just as important, we would need to scale the density D of the universe, against the radius 10^26, and measure how diluted this matter really is. We can measure the density, and radius of a black hole in a series of proportionalities. The radius R of a black hole, even a micro black hole is directly proportional to its mass (R- M). And the density of a black hole is found to be given by its mass divided by its volume (D=M/V).
I work out that there will be something like 10^9 particles that make up the black hole sea. This would mean that there is about a billion more particles making this sea, than there is the normal baryons found in matter. Neutrinos might be so lightweight that they can travel between dimensions. They would also naturally form under the relativistic effects on the energy deposition rate via neutrino pair annihilation near the rotation axis of a black hole normally, but here we are talking about a Kerr black hole. And also, these black holes won’t radiate photons or neutrinos. They’re stable radiatively.
Electron neutrinos or even antineutrinos are generated whenever neutrons change into protons or protons into neutrons, the two forms of beta decay. As we already know, about 50 trillion neutrinos pass through our bodies in just under one second! They originally came from sun. They are a gravitational king for this matter, and are themselves classed as being a form of dark matter. A source of frame-dragging at a very small scale would radiate from this sea of black holes. The black holes will spin at the speed of light, just like macroscopic black holes. The Centripetal force is proportional to the centrifugal force (F=mrW^2).
A black hole need to be of Planck Mass at smallest size 2x10^-8kg. The Compton Wavelength given as lambda=h/mc=2pi(h/mc) of a black hole is proportional to its Schwartzchild Radius 1 / (2M − r); very small black holes are very hot. This is because the decrease in size and magnification of density makes these little things extremely hot. A typical micro black hole would have a temperature of 10^16 K, which is 200 GeV.
Might the curvature produced from the extremal black holes be seeping into the other dimensions, producing the gravitation thought to be answered through the use of Dark Matter?
Reiku :m: